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Answer:
Answer is cerebellum. And this is the right answer
Related Questions
One cubic meter of an ideal gas at 600 K and 1000 KPa expand to five times its initial volume as follows:(a) By a mechanically reversible, isothermal process [T 2 = 600K; P 2 = 200kPa; W= -1609 kJ](b) By a mechanically reversible, adiabatic process [T 2 =208.96K; P 2 = 67.65 kPa; W= -994.4 kJ] For each case calculate the final temperature, pressure and the work done by the gas. C p =21 Jmol- 1K-1.
Different fatty acids are distinguished by the length of their_?double bondssingle bondscarboxylic groupscarbon chains
The rate constant for the second-order reaction 2NOBr(g) ¡ 2NO(g) 1 Br2(g) is 0.80/M ? s at 108C. (a) Starting with a concentration of 0.086 M, calculate the concentration of NOBr after 22 s. (b) Calculate the half-lives when [NOBr]0 5 0.072 M and [NOBr]0 5 0.054 M.
(e) Which sample contains more atoms: 2.0 g of Fe2O3 or 2.0 g of CaSO4? Support your answer with calculations.
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A lab group was calculating the speed of a radio car. They measured the distance traveled to be 6 meters and the time to be 3.5 seconds. Then they divided the distance by the time to find the speed. The actual speed was 2.2 m/s. Their percent error is 22.1%.
Percent error is a measure of the difference between an observed value and a true value.
Actual Speed (True Value) = 2.2 m/s
Experimental Speed (Calculated Value) = Distance / Time = 6 m / 3.5 s = 1.714 m/s
The formula for calculating percent error is:
Percent Error = ((|Actual Value - Experimental Value|) / |Actual Value|) * 100%
Calculate the absolute difference between the actual speed and the experimental speed:
|2.2 - 1.714| = 0.486
Calculate the absolute value of the actual speed:
|2.2| = 2.2
Percent Error = (0.486 / 2.2) * 100%
= 0.221 * 100%
= 22.1%
The calculated percent error is approximately 22.1%. This means that the lab group's calculated speed of 1.714 m/s is about 22.1% lower than the true speed of 2.2 m/s.
Percent error is a way to quantify the accuracy of experimental measurements. A positive percent error indicates that the experimental value is higher than the true value, while a negative percent error indicates that the experimental value is lower. In this case, since the calculated speed is lower than the true speed, we have a positive percent error.
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Answer:456
Explanation:
Keg=4.0 x 10-10
What is the value of Key for 2CO2(g) + 2COR + O2g) ?
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Answer:
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to calculate the equilibrium constant value for the reverse reaction:
By knowing that the equilibrium expression is actually:
Thus, we plug in and solve for the inverse of Keq to obtain Key as follows:
Regards!
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Answer:
70.88 mL volume of 1.27 M of HCl is required.
Explanation:
Given data:
Initial volume = ?
Initial molarity = 1.27 M
Final volume = 197.4 mL
Final molarity = 0.456 M
Solution:
Formula:
M₁V₁ = M₂V₂
Now we will put the values in formula.
1.27 M × V₁ = 0.456 M × 197.4 mL
V₁ = 0.456 M × 197.4 mL/1.27 M
V₁ = 90.014M.mL/1.27 M
V₁ = 70.88 mL
70.88 mL volume of 1.27 M of HCl is required.
Final answer:
To prepare 197.4 mL of 0.456 M HCl from 1.27 M HCl, you need 71.03 mL of 1.27 M HCl.
Explanation:
The subject of this problem involves using the concept of molarity in Chemistry. We can use a simple formula for dilution, M1V1 = M2V2, to find the volume. Here M1 (1.27 M) is the molarity of stock HCl, V1 is the required volume, M2 (0.456 M) is the desired molarity, and V2 (197.4 mL) is the volume of the solution. Solving for V1, we get V1 = M2V2 / M1 = (0.456 M * 197.4 mL) / 1.27 M = 71.03 mL. Therefore, 71.03 mL of 1.27 M HCl is needed to prepare 197.4 mL of 0.456 M HCl.
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Answer:
(a)
(b)
(c)
(d)
(e)
Explanation:
Hello,
(a) For the lucite, one computes the moles of C, H and O that are present:
Now, dividing each moles by the smallest moles (oxygen's moles), one obtains:
Finally, we look for the smallest whole number subscript by multiplying by 2, so the empirical formula turns out into:
(b) For the Saran, one computes the moles of C, H and Cl that are present:
Now, dividing each moles by the smallest moles (hydrogen's moles), one obtains:
Finally, as all of the subscripts are whole numbers, the empirical formula turns out into:
(c) For the polyethylene, one computes the moles of C and H that are present:
Now, dividing each moles by the smallest moles (carbon's moles), one obtains:
Finally, as all of the subscripts are whole numbers, the empirical formula turns out into:
(d) For the polystyrene, one computes the moles of C and H that are present:
Now, dividing each moles by the smallest moles (either carbon's or hydrogen's moles), one obtains:
Finally, as all of the subscripts are whole numbers, the empirical formula turns out into:
(e) For the orlon, one computes the moles of C, H and N that are present:
Now, dividing each moles by the smallest moles (nitrogen's moles), one obtains:
Finally, as all of the subscripts are whole numbers, the empirical formula turns out into:
Best regards.
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Answer:
823.2 J
Explanation:
PE = mgh
= (7 kg) (9.8 m/s^2) (12 m)
= 823.2 J
Answer:
RequiredAnswer:-
Mass=m=7kg
Height=h=12m
Gravitational force=g=10m/s^2
- As we know that
- Substitute the values