QUICK WILL MARK BRAINLIEST!!Match each of the unknown ions to its appropriate description.

A− A) A nonmetal that gained one electron
B+ B) A metal that lost one electron
C2− C) A metal that lost two electrons
D2+ D) A nonmetal that gained two electrons

Answers

Answer 1

Answer:

Answer:

c2-c

Explanation:

A mental that lost two electrons just joking I don't k ow but I think it ain't the first o e because of comment sense to the 5th power

Answer 2

Answer:

Answer:

A and B

Explanation:

metal form ion by lossing elecron

non metal form ion by gaining electron

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Name the physical properties used in seperating kerosene and petrol

Answers

step by step explanation

simple distillation can be used when the temperature difference between the boiling points of two miscible liquid is at least 25°c. the temperature difference between the boiling points of kerosene and petrol is 25c. hence, this mixture can separated using simple distillation.

answer:

simple distillation

Calculate the relative molecular
mass of Zn (NO3)2

Answers

Answer:

Okyu

Explanation:

Mass of Zn = 65

(NO3)2 = 124

$65 + (14 + 16 * 2) * 2 \n 65 + 124 \n = 184g mol$

Explanation:

Mass of Zn = 65

(NO3)2 = 124

\begin{gathered}65 + (14 + 16 \times 2) \times 2 \\ 65 + 124 \\ = 184g mol\end{gathered}

65+(14+16×2)×2

65+124

=184gmol

1. Based on the appearance of your reaction in the beaker, which reagent do you think was consumed and which reagent had some left over? The aluminum was consumed, and copper was left over as seen by the reddish particles. 2. If 5.0 g of iron metal is reacted with 15.0 g of Cl2 gas, how many grams of ferric chloride will form? About 14.52 grams will form. 3. For the reaction above the amount of ferric chloride obtained in the lab was 9.15 grams. Calculate the percent yield. The percent yield would be around 63.02%. 4. What are some reasons for obtaining a percent yield of less than 100 percent? Factors such as the reactants not reacting completely, human error in the experiment, the reactants might have too large of a surface area for reaction, multiple reactions occurring within an experiment, temperature, etc.

Answers

Answer:

1. Al is consumed first and CuSO₄ remains left.

2. The grams of ferric chloride that forms is 14.5 g.

3. The percent yield is 63.1%

4. Trace of impurities present in the reagents, bad manipulations when preparing solutions, etc.

Explanation:

1. The reaction is:

2Al + 3CuSO₄ = Al₂(SO₄)₃ + 3Cu

The number of moles of Al is less than the number of moles of CuSO₄. Therefore, Al is the limiting reagent and CuSO₄ is the excess reagent. This means that Al is consumed first and CuSO₄ remains left.

2. The reaction is:

2Fe + 3Cl₂ = 2FeCl₃

The number of moles of Fe is:

$n_(Fe) =(m_(Fe) )/(MW_(Fe) ) =(5)/(55.85) =0.0895moles$

The number of moles of Cl₂ is:

$n_(Cl2) =(15)/(70.9) =0.211moles$

We know that 2 moles of Fe react with 3 moles of Cl₂, thus:

2 moles Fe---------------3 moles Cl₂

0.0895 moles Fe-------X moles Cl₂

Clearing X:

$Xmoles_(Cl2) =(3*0.0895)/(2) =0.134moles$

It needs 0.134 moles of Cl₂ but it only has 0.211 moles, thus, Cl₂ is the excess reagent. Fe is the limiting reagent.

2 moles Fe-----------2 moles FeCl₃

0.0895 moles Fe------X moles FeCl₃

Clearing X:

$Xmoles_(FeCl3) =(2*0.0895)/(2) =0.0895moles$

$m_(FeCl3) =0.0895molesFeCl3*(162.2gFeCl3)/(1molFeCl3) =14.5g$

3. The actual yield of FeCl₃ is 9.15 g, the theoritical yield is 14.5 g, thus, ther percent yield is:

$Percent-yield=(Actual-yield)/(Theoritical-yield) *100=(9.15)/(14.5) *100=63.1$ %

4. Trace of impurities present in the reagents, bad manipulations when preparing solutions, etc.

What is the hydrogen-ion concentration of the ph is 3.7

Answers

Answer:

the answer 37

Explanation:

Saved Propane burns in air according to the equation C3Ha(g 502lg)3CO2) + 4H20(g) What volume of O2 in liters would be required if 15.0 L of propane burns, assuming that all of the gases are under the same conditions? Short Answer Toolbar navigation E I E B IUS EA This question will be sent to your Instructor for grading. 20 of 25 l Next > Prev nere to search

Answers

Answer: 75 liters of $O_2$ in liters would be required if 15.0 L of propane burns, assuming that all of the gases are under the same conditions.

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 Lat STP and contains avogadro's number $6.023* 10^(23)$ of particles.

To calculate the number of moles, we use the equation:

$\text{Number of moles of propane}=\frac{\text{Given volume}}{\text{Molar volume}}=(15.0L)/(22.4L)=0.67moles$

$C_3H_8+5O_2\rightarrow 3CO_2+4H_2O$

According to stoichiometry:

1 mole of propane combines with = 5 moles of oxygen

Thus 0.67 moles of propane combine with = $(5)/(1)* 0.67=3.35moles$

Volume of $O_2=moles* {\text {Molar Volume}}=3.35* 22.4L=75L$

Thus 75 liters of $O_2$ in liters would be required if 15.0 L of propane burns, assuming that all of the gases are under the same conditions.

Please help me and promise I will mark as brainiest I need it in ISEF please how much energy does the vehicle hydrogen fuel cell need to break hydrogen into ions ?!