Answers
Answer:
333.6 atm
Explanation:
The following data were obtained from the question:
Mole of O2 (nO2) = 3.96 moles
Mole of N2 (nN2) = 7.49 moles
Mole of CO2 (nCO2) = 1.19 moles
Total pressure = 563 mmHg
Partial pressure of N2 =..?
Next, we shall determine the total number of mole in the container.
This can be obtained as follow:
Mole of O2 (nO2) = 3.96 moles
Mole of N2 (nN2) = 7.49 moles
Mole of CO2 (nCO2) = 1.19 moles
Total mole =?
Total mole = nO2 + nN2 + nCO2
Total mole = 3.96 + 7.49 + 1.19
Total mole = 12.64 moles
Next, we shall determine the mole fraction of N2.
This can be obtained as follow:
Mole fraction = mole of substance/total mole
Mole of N2 (nN2) = 7.49 moles
Total mole = 12.64 moles
Mole fraction of N2 =?
Mole fraction of N2 = 7.49/12.64
Finally, we shall determine the partial pressure of N2.
This can be obtained as follow:
Mole fraction of N2 = 7.49/12.64
Total pressure = 563 mmHg
Partial pressure of N2 =..?
Partial pressure = mole fraction x total pressure
Partial pressure of N2 = 7.49/12.64 x 563
Partial pressure of N2 = 333.6 atm
The, the partial pressure of nitrogen, N2 is 333.6 atm
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Under what set of conditions does HCl(g) deviate the most from ideal behavior?a) high temperature and low pressure.b) low temperature and high pressure.c) high temperature and high pressure.d) low temperature and low pressure. e) standard temperatore and pressure.
Please answer this question
Answers
Answer:
3056.25g
Explanation:
Problem here is to find the mass of Cu(NO₃)₂ to weigh out to make for the number of moles.
Given;
Number of moles = 16.3moles
Unknown:
Mass of Cu(NO₃)₂ = ?
Solution:
To find the mass of Cu(NO₃)₂, use the expression below;
Mass of Cu(NO₃)₂ = number of moles x molar mass
Let's find the molar mass;
Cu(NO₃)₂ = 63.5 + 2[14 + 3(16)]
= 63.5 + 2(62)
= 187.5g/mol
Mass of Cu(NO₃)₂ = 16.3 x 187.5 = 3056.25g
Answers
Answer:
The specific heat of magnesium is 1.04 J/g°C.
Explanation:
Heat lost by the magnesium = Q
Mass of the magnesium = m = 62.08 g
Heat capacity of magnesium= c = ?
Initial temperature of the magnesium =
Final temperature of the magnesium= T = 35.60 °C
Heat absorbed by coffee cup calorimeter = Q'
Heat capacity of coffee cup calorimeter = C = 1.79 J/°C
Initial temperature of coffee cup calorimete = = 23.19°C
Final temperature of coffee cup calorimete = T = 35.60 °C
Heat absorbed by the water = q
Mass of water = m' = 77.81 g
Heat capacity of water = c' = 4.18 J/g°C
Initial temperature of water = = 0°C
Final temperature of water = T
According law of conservation of energy , energy lost by coffee will equal to heat required to raise temperature of water and coffee cup calorimeter.
On solving we get:
c = 1.04 J/g°C
The specific heat of magnesium is 1.04 J/g°C.
B.) Positively charged
C.) Strongly ionic
D.) Negatively charged
Answers
Answers
Answer:
Heterogeneous Mixture. Have a good day! =)
Explanation:
Answers
Production of a gas
Production of light
O Production of a solid (precipitation)
Answers
Answer:
Emission of Light
Explanation:
Chemiluminescence is the emission of light as the result of a chemical reaction, and not a property of a specific compound.
Dont know if you were asking for this but hope it helps