CHEMISTRY COLLEGE

Research Hypatia's achievements in the worldof science.

What is she most known for?

Write down three interesting facts about her

life.

Answers

Answer 1
Answer:

Answer:

See explanation

Explanation:

Hypatia is popular for her work in mathematics. She also did some work in the area of astronomy. Her well know work in mathematics is her ideas about conic sections.

She was born the Theon of Alexandria and she was a professional mathematician in her life time.

She was the greatest mathematician of her time and she was telling leader of the Neoplatonist school of philosophy in Alexandria. By so doing, she conquered the culture of sexism in her time.

She was trained by her father in mathematics and eventually replaced him. She was the last major mathematician in the Alexandrian tradition.

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The periodic table displaysOA. all of the known elements that exist in the world today.OB. only the important elements that exist in the world.OC. only the important compounds that exist in the world.
Name the following : [Ni(NH3) 4(H2O)2(NO3)2​
Calculate the relative molecularmass of Zn (NO3)2
How does a pharmaceutical percolator work
Draw the Lewis structure for BrCl3. What are the approximate bond angles about the central atom?a. 60°.b. 90°.c. 109°.d. 120°.e. 180°.

wo reactions and their equilibrium constants are given. A + 2 B − ⇀ ↽ − 2 C K 1 = 2.57 2 C − ⇀ ↽ − D K 2 = 0.226 A+2B↽−−⇀2CK1=2.572C↽−−⇀DK2=0.226 Calculate the value of the equilibrium constant for the reaction D − ⇀ ↽ − A + 2 B .

Answers

Answer: The value of equilibrium constant for the net reaction is 11.37

Explanation:

The given chemical equations follows:

Equation 1:  A+2B\xrightarrow[]{K_1} 2C

Equation 2:  2C\xrightarrow[]{K_2} D

The net equation follows:

D\xrightarrow[]{K} A+2B

As, the net reaction is the result of the addition of first equation and the reverse of second equation. So, the equilibrium constant for the net reaction will be the multiplication of first equilibrium constant and the inverse of second equilibrium constant.

The value of equilibrium constant for net reaction is:

K=K_1* (1)/(K_2)

We are given:

K_1=2.57

K_2=0.226

Putting values in above equation, we get:

K=2.57* (1)/(0.226)=11.37

Hence, the value of equilibrium constant for the net reaction is 11.37

What mass of nitrogen gas is required to react completely with 2.79 g of hydrogen gas to produce ammonia?

Answers

the balanced equation for the formation of ammonia is as follows
N₂ + 3H₂ ---> 2NH₃
stoichiometry of H₂ to N₂ is 3:1
number of H₂ moles reacted - 2.79 g / 2 g/mol  = 1.40 mol 
if 3 mol of H₂ reacts with 1 mol of N₂
then 1.40 mol of H₂ reacts with  - 1.40/3 = 0.467 mol of N₂
mass of N₂ required - 0.467 mol x 28 g/mol = 13.1 g
mass of N₂ formed is 13.1 g

Which element is a halogen?chlorine (Cl)
oxygen (O)
carbon (C)
radon (Rn)

Answers

The element that has been a halogen from the given elements have been Chlorine. Thus, option A is correct.

Halogen has been given as the group of metallic compounds that have been consisted of the one valence electrons in their last orbitals.

The halogens have been the most reactive elements and belong to group 18 of the periodic table. From the given set of elements, the number of valence electrons in the following has been:

  • Chlorine = 1 valence electron
  • Oxygen = 6 valence electrons
  • Carbon = 4 valence electrons
  • Radon = 8 valence electrons

Since the element having 1 valence electron has been Chlorine. Thus, the element that has been a halogen from the given elements have been Chlorine. Thus, option A is correct.

For more information about halogen, refer to the link:

brainly.com/question/2288388

Answer is chlorine (Cl)

An 18-karat gold necklace is 75% gold by mass, 16% silver, and 9.0% copper.A. What is the mass, in grams, of the necklace if it contains 0.24 Oz of silver?
B. How many grams of copper are in the necklace.?
C. If the 18- karat gold has a density of 15.5g/cm^3, what is the volume in cubic centimeters?

Answers

B. How many grams of copper are in the necklace.?
I think that the answer would be option B.

A system absorbs 12 J of heat from the surroundings; meanwhile, 28 J of work is done on the system. What is the change of the internal energy ΔEth of the system?

Answers

Answer: The value of change in internal energy of the system is, 40 J.

Explanation : Given,

Heat  absorb from the surroundings = 12 J

Work done on the system = 28 J

First law of thermodynamic : It is a law of conservation of energy in which the total mass and the energy of an isolated system remains constant.

As per first law of thermodynamic,

\Delta U=q+w

where,

\Delta U = internal energy  = ?

q = heat  absorb from the surroundings

w = work done on the system

Now put all the given values in this formula, we get the change in internal energy of the system.

\Delta U=12J+28J

\Delta U=40J

Therefore, the value of change in internal energy of the system is, 40J.

Station 9: Iodine ______________ g I2 Perform the calculations in the space between each lettered problem. Enter the answer with correct significant figures and units on the line provided.

Answers

Answer:

a) Moles of iodine molecules = 0.0748 moles of Iodine molecules

b) Moles of iodine atoms = 0.150 moles of iodine atoms

c) Number of iodine atoms = 9.03 * 10²² atoms

d) Number of iodine molecules = 4.50 * 10²² molecules

Note: The complete question is found in the attachment below.

Explanation:

a. Number of moles of iodine molecules in 19.0 g of I₂

Molar mass of iodine molecule = 2 * 127 g/mol = 254g/mol

Number of moles = mass / molar mass

Number of moles = 19.0 g / 254 g/mol

Moles of iodine molecules = 0.0748 moles of Iodine molecules

b) Number of moles of iodine atoms

I mole of iodine molecules contains 2 moles of iodine atoms

Therefore, 0.0748 moles of iodine molecules will contain 2 * 0.0748 moles of iodine atoms

Moles of iodine atoms = 0.150 moles of iodine atoms

c) Number of iodine atoms = number of moles of iodine atoms * 6.02 * 10²³

Number of iodine atoms = 0.150 * 6.02 * 10²³

Number of iodine atoms = 9.03 * 10²² atoms

d) Number of iodine molecules = number of moles of iodine molecules * 6.02 * 10²³

Number of iodine molecules = 0.0748 * 6.02 * 10²³

Number of iodine molecules = 4.50 * 10²² molecules
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