How does a pharmaceutical percolator work

Answers

Answer 1

Answer:

Final answer:

A pharmaceutical percolator is a device used to extract active compounds from plants or herbs. It works by passing a solvent through the material to dissolve the desired components. The process involves maceration, percolation, and filtration.

Explanation:

A pharmaceutical percolator is a device used in the pharmaceutical industry to extract active compounds from plants or herbs. It works on the principle of percolation, which involves passing a solvent through a solid material to dissolve the desired components. The percolation process involves three main steps:

Maceration: The plant material is crushed or ground and mixed with a suitable solvent, such as ethanol or water. This mixture is then allowed to stand for a specific period, usually several hours or days, to allow the solvent to dissolve the active compounds.
Percolation: The macerated mixture is then transferred to the percolator, which is a vessel with a perforated plate or bottom. The solvent is poured onto the mixture, and gravity pulls it down through the solid material, dissolving the active compounds along the way.
Filtration: The liquid containing the dissolved active compounds, known as the percolate, is collected at the bottom of the percolator and filtered to remove any solid particles or impurities. The resulting solution can then be further processed or used directly in the production of pharmaceutical products.

Learn more about pharmaceutical percolator here:

brainly.com/question/1183058

Related Questions

What mass of Nz will be needed to produce 31.5 grams of N2O5?4N2 + 502 --> 2N2O5a) 158.3 gramsb) 38.64 gramsc) 4.96 gramsd) 16.34 grams
A gas mixture with a total pressure of 770 mmHg contains each of the following gases at the indicated partial pressures: 128 mmHg CO2, 232 mmHg Ar, and 183 mmHg O2. The mixture also contains helium gas. What is the partial pressure of the helium gas?
How many amino acids are there and what three general categories do they fall into (i do not mean chemical categories in this question)? please include a one-sentence description of these three categories (3)?
For the following reaction, 142 grams of silver nitrate are allowed to react with 22.3 grams of copper . silver nitrate(aq) copper(s) copper(II) nitrate(aq) silver(s) What is the maximum amount of copper(II) nitrate that can be formed
15) What is the hydronium ion concentration [H3O + ] of a 0.125 M hydrocyanic acid solution with Ka = 4.9 × 10-10? The equation for the dissociation of hydrocyanic acid is: HCN(aq) + H2O(l) ⇌ H3O+(aq) + CN- (aq)

Blood samples for research or medical tests sometimes have heparin added. Why is this done?

Answers

It is essential for accurate results that the correct volume of blood is sampled to achieve a correct concentration (and dilution, if liquid heparin is used), and that blood and anticoagulant are well mixed immediately after sampling.

A student is given a sample of a blue copper sulfate hydrate. He weighs the sample in a dry covered porcelain crucible and got a mass of 23.875 g for the crucible, lid, and sample. The mass of the empty crucible and lid was found earlier to be 22.652 g. He then heats the crucible to expel the water of hydration, keeping the crucible at red heat for 10 minutes with the lid slightly ajar. On colling, he finds the mass of crucible, lid, and contents to be 23.403 g. The sample was changed in the process to very light clue anhydrous CuSO4. How many moles of water are present per mole of CuSO4?

Answers

Answer:

There are present 5,5668 moles of water per mole of CuSO₄.

Explanation:

The mass of CuSO₄ anhydrous is:

23,403g - 22,652g = 0,751g.

mass of crucible+lid+CuSO₄ - mass of crucible+lid

As molar mass of CuSO₄ is 159,609g/mol. The moles are:

0,751g × $(1mol)/(159,609g)$ = 4,7052x10⁻³ moles CuSO₄

Now, the mass of water present in the initial sample is:

23,875g - 0,751g - 22,652g = 0,472g.

mass of crucible+lid+CuSO₄hydrate - CuSO₄ - mass of crucible+lid

As molar mass of H₂O is 18,02g/mol. The moles are:

0,472g × $(1mol)/(18,02g)$ = 2,6193x10⁻² moles H₂O

The ratio of moles H₂O:CuSO₄ is:

2,6193x10⁻² moles H₂O / 4,7052x10⁻³ moles CuSO₄ = 5,5668

That means that you have 5,5668 moles of water per mole of CuSO₄.

I hope it helps!

Solve the following problem:

Answers

Answer:

Option 3.

Explanation:

Isomerism is a phenomenon where by two or more compounds have the same molecular formula but different structural patterns.

Geometric Isomerism is a type of Isomerism that occurs within a double bond i.e Geometric isomers have different arrangement within the double bond.

Considering the options given above,

The 1st option is exactly the same as the compound only, it is inverted.

The 2nd option is still the same as the compound, only it is laterally inverted.

The 3rd option satisfy geometric Isomerism as the arrangement differ from the compound in the double bond.

The 4th option is entirely a saturated compound in which geometric Isomerism is not possible.

Determine the limiting reactant when 30.0 g of propane, C3H8, is burned with 75.0 g of oxygen.

Answers

Answer: The limiting reagent is oxygen gas.

Explanation:

Limiting reagent is defined as the reactant that is present in less amount and it limits the formation of products.

Excess reagent is defined as the reactant which is present in large amount.

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For propane:

Given mass of propane = 30.0 g

Molar mass of propane = 44.1 g/mol

Putting values in equation 1, we get:

$\text{Moles of propane}=(30.0g)/(44.1g/mol)=0.680mol$

For oxygen:

Given mass of oxygen = 75.0 g

Molar mass of oxygen = 32 g/mol

Putting values in equation 1, we get:

$\text{Moles of propane}=(75.0g)/(32g/mol)=2.34mol$

The chemical equation for the combustion of propane follows:

$C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(l)$

By Stoichiometry of the reaction:

5 moles of oxygen gas reacts with 1 mole of propane.

So, 2.34 moles of oxygen gas will react with = $(1)/(5)* 2.34=0.468mol$ of propane

As, given amount of propane is more than the required amount. So, it is considered as an excess reagent.

Thus, oxygen is considered as a limiting reagent because it limits the formation of product.

Hence, the limiting reagent is oxygen gas.

Write the condensed ground-state electron configurations of these transition metal ions, and state which are paramagnetic:(a) V³⁺ (b) Cd²⁺ (c) Co³⁺ (d) Ag⁺