CHEMISTRY COLLEGE

HELP ASAP WHICH ONE IS THE ANSWE A OR B OR C OR D ???? ! !!!

Answers

Answer 1

Answer:

Answer:

1. C

2.B

Explanation:

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Which element is oxidized in the following reaction Mn²⁺ + 2 K → Mn(s) + 2 K⁺ ?

Answers

Potassium is oxidized (k)
Leo ger is the nuemonic
- loss electrons = oxidized
- gain electrons = reduced

You can see K gains a positive charge so it is safe to assume it lost some (negatively charged) electrons

In 100 grams of sweet peas there are 14.5 carbohydrates,5.7 grams of sugars,5.1 grams of dietary fiber, 5.4 grams of protein and 0.4 grams of fat what is the percent composition of each?

Answers

14.5 % carb
5.7% sugar
5.1% fiber
5.4% protein
0.4% fat

The equilibrium constant, Kp, equals 3.40 at 25°C for the isomerization reaction: cis-2-butene ⇌ trans-2-butene. If a flask initially contains 5.00 atm of each gas, the system is___________.

Answers

Final answer:

The given reaction will shift towards cis-2-butene once placed in equilibrium. This can be determined by calculating the reaction quotient and comparing it with the equilibrium constant.

Explanation:

The reaction could either shift towards the cis-2-butene or trans-2-butene depending on whether the reaction quotient, Q, is lesser or greater than the equilibrium constant, Kp.

Bear in mind that Kp = Ptrans/Pcis. Let's say that Pt is the partial pressure of trans-2-butene and Pc is the partial pressure of cis-2-butene at equilibrium. If we start with 5 atm of each gas, the change in Pc is -x and the change in Pt is +x.

So, Kp = (5+x)/(5-x). We are given that Kp = 3.4. Solving these two equations will show that x is a negative value, which means that the system shifts towards cis-2-butene.

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Final answer:

For the isomerization reaction cis-2-butene ⇌ trans-2-butene, with an initial pressure of 5.00 atm for both gases and a Kp of 3.40, the system will shift towards the product, trans-2-butene, as Kp > Qp (1). This reflects the principle that a chemical system at equilibrium will shift to counteract any change.

Explanation:

In terms of the equilibrium constant (K), for gas-phase reactions, Kp represents equilibrium in terms of partial pressures, while Kc represents it in molar concentrations. For instance, in the isomerization reaction given cis-2-butene ⇌ trans-2-butene, Kp is given as 3.40. To determine the behavior of the system, we need to compare it to reaction quotient (Q). Given that the flask initially contains 5.00 atm of each gas, Qp is 1 (since Qp = partial pressure of trans-2-butene / partial pressure of cis-2-butene). Since Kp > Qp, the reaction will shift towards the products, hence the system will shift towards trans-2-butene. From this, it is clear that the equilibrium constant and reaction quotient play vital roles in determining the direction of shift in a chemical equilibrium.

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The radius of an atom of gold (Au) is about 1.35 Å.How many gold atoms would have to be lined up to span 5.5 mm ?

Answers

The number of gold atoms that would be needed to span this distance is 20,370.4 atoms.

How many gold atoms would have to be lined up?

To calculate how many gold atoms would need to be lined up to span a given distance, we will us the following method.

The number of gold atoms that would be needed to span this distance:

Distance = Diameter of a gold atom

Distance = 2 x Radius

Distance = 2 x 1.35 Å

Number of gold atoms = Total distance / Distance spanned by a single atom

Number of gold atoms = (5.5 x 10⁻⁴ cm) / (2 x 1.35 Å)

1 Å = 10⁻⁸ cm.

Number of gold atoms = (5.5 x 10⁻⁴ cm) / (2 x 1.35 x 10⁻⁸ cm)

Number of gold atoms = 20,370.4 atoms

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depends how many sig figs you are rounding to so I won't round to tenth or hundredth but the answer is 2.037 * 10^7

The SI unit of time is the second, which is defined as 9,192,631,770 cycles of radiation associated with a certain emission process in the cesium atom. Calculate the wavelength of this radiation (to three significant figures).

Answers

Given:

Radiation emission in Cs atom = 9,192,632,770 cycles

To determine:

The wavelength of the above radiation

Explanation:

It is given that :-

1 sec equivalent to 9,192, 631, 770

Now, frequency (ν) = cycles /sec = 9,192, 631, 770/sec

Wavelength of a radiation is given as:

λ = c/ν

where c = speed of light = 3*10⁸ m/s

λ = 3*10⁸ ms⁻¹/9,192, 631, 770 s⁻¹ = 0.0326 m

Ans: Thus the wavelength of this radiation is 0.033 m

To calculate the wavelength of this radiation if the SI unit of time is the second, which is defined as 9,192,631,770 cycles of radiation associated with a certain emission process in the cesium atom, the wavelength is one cycle of radiation, and therefore the wavelength is 1/9192631770

Which of the following is an oxidation-reduction reaction? Which of the following is an oxidation-reduction reaction? Mg(s) + 2 HCl(aq) → MgCl2(aq) + H2(g) HCl(aq) + LiOH(aq) → LiCl(aq) + H2O(l) NaCl(aq) + AgNO3(aq) → AgCl(s) + NaNO3(aq) Pb(C2H3O2)2(aq) + 2 NaCl(aq) → PbCl2(s) + 2 NaC2H3O2(aq) All of the above are oxidation-reduction reactions.

Answers

Answer:

NONE OF THE ABOVE

Explanation:

None of the above are examples of an oxidation - reduction or a redox reaction . This is because there is no change in the oxidation state of any of the elements in the reaction when the reaction happens .

For a redox reaction , transfer of electrons must take place.
The oxidation states must increase or decrease in atleast 2 of the elements of a compound.
For example :

$Zn^(2+)+Cu$ ⇒ $Cu^(2+)+Zn$

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