Match the words in the left column to the appropriate blanks in the sentences on the right. Make certain each sentence is complete before submitting your answer. ResetHelp 1. NaCl ; ionic bonds{\rm NaCl} ; blank are stronger than the blank in {\rm HCl}. are stronger than the dispersion forces{\rm NaCl} ; blank are stronger than the blank in {\rm HCl} . in HCl. 2. H2O ; hydrogen bonds{\rm H_2O} ; blank are stronger than the blank in {\rm H_2Se}. are stronger than the dispersion forces{\rm H_2O} ; blank are stronger than the blank in {\rm H_2Se}. in H2Se. 3. NH3 ; hydrogen bonds{\rm NH_3} ; blank are stronger than the blank in {\rm PH_3}. are stronger than the dipole-dipole attractions{\rm NH_3} ; blank are stronger than the blank in {\rm PH_3}. in PH3. 4. HF ; hydrogen bonds{\rm HF} ; blank are stronger than the blank in {\rm F_2}. are stronger than the dispersion forces{\rm HF} ; blank are stronger than the blank in {\rm F_2}. in F2.

Answer:

See explanation

Explanation:

In this case, we have 2 types of reactions. is a strong base but only has 2 carbons therefore we will have less steric hindrance in this base. So,  the base can remove hydrogens that are bonded on carbons 1 or 6, therefore, we will have a more substituted alkene (1-methylcyclohex-1-ene).

For the   we have more steric hindrance. So, we can remove only the hydrogens from carbon 7 and we will produce a less substituted alkene (methylenecyclohexane).

See figure 1

I hope it helps!

Answer: -

Many drugs are sold as their hydrochloric salts (RNH₃⁺Cl⁻), formed by reaction of an amine (RNH₂) with HCl.

It is done because amines are generally liquids. But their hydrochloric salts are solid. A solid drug is always more preferable for drug companies as their handling and packaging are easier.

Acebutolol consists of one amide functionality as well as a secondary amine functionality.

When HCl is added, the lone pairs of the nitrogen of the secondary amine attacks it, leading to the formation of it's hydrochloric salts.

Answer: The cell potential of the cell is +0.118 V

Explanation:

The half reactions for the cell is:

Oxidation half reaction (anode):  

Reduction half reaction (cathode):  

In this case, the cathode and anode both are same. So, will be equal to zero.

To calculate cell potential of the cell, we use the equation given by Nernst, which is:

where,

n = number of electrons in oxidation-reduction reaction = 2

= ?

=

= 1.0 M

Putting values in above equation, we get:

Hence, the cell potential of the cell is +0.118 V

The  cell potential for the cell as calculated  is 0.118 V.

What is the Nernst equation?

The Nernst equation can be used to obtain the cell potential of a cell under non- standard conditions. The standard cell potential in this case is zero owing to the fact that both cathode and anode are made of nickel.

Hence;

Ecell = E°cell - 0.0592/nlog Q

Ecell = 0 - 0.0592/2 log (1 00 * 10^-4/1)

Ecell = 0.118 V

The  cell potential for the cell as calculated  is 0.118 V.

Learn more about Nernst equation: brainly.com/question/721749

Answer:

34 g

Explanation:

Let's consider the following balanced equation.

N₂ + 3 H₂ → 2 NH₃

The theoretical mass ratio of N₂ to H₂ is 28g N₂ : 6g H₂ = 4.6g N₂ : 1g H₂.

The experimental mass ratio of N₂ to H₂ is 100g N₂ : 6g H₂ = 16.6g N₂ : 1g H₂.

As we can see, hydrogen is the limiting reactant.

According to the task, we 6 g of H₂ react completely, 34 g of ammonia are produced.

Answer:

Explanation:

Hello!

In this case, since the heat of vaporization is related with the energy required by a substance to undergo the phase transition from liquid to gas, we can compute such amount of energy as shown below:

In such a way, since the enthalpy of vaporization is given as well as the mass, we compute the energy as shown below:

Best regards!