1. An isotope of cesium-137 has a half-life of 30 years. If 5.0 g of cesium-137 decays over 60 years, how many grams will remain?

Answers

Answer 1
Answer:

Answer:

1.25 g

Explanation:

Now we have to use the formula;

N/No = (1/2)^t/t1/2

N= mass of cesium-137 left after a time t (the unknown)

No= mass of cesium-137 present at the beginning = 5.0 g

t= time taken for 5.0 g of cesium-137 to decay =60 years

t1/2= half life of cesium-137= 30 years

Substituting values;

N/5= (1/2)^60/30

N/5= (1/2)^2

N/5= 1/4

4N= 5

N= 5/4

N= 1.25 g

Therefore, 1.25 g of cesium-137 will remain after 60 years.


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Which notations represent atoms that have the same number of protons but a different number of neutrons?

Answers

The atoms having the same number of protons but a different number of neutrons have been termed isotopes.

The neutrons and protons are the constituents of the nucleus. The number of protons and electrons is equal in the atom. When two different atoms have the same number of protons the species have been termed isotopes. The atomic number of the species differ that resulting in the different positions in the periodic table.

For more information about the atoms, refer to the link:

brainly.com/question/657632

Atoms of the same element, containing the same number of protons, but different numbers of neutrons, are known as isotopes. Isotopes of any given element all contain the same number of protons, so they have the same atomic number (for example, the atomic number of helium is always 2).

The steps in a reaction mechanism are as follows. Which species is acting as a catalyst? Step 1: Ag+(aq) + Ce4+(aq) <-----> Ag2+(aq) + Ce3+(aq) Step 2: Tl+(aq) + Ag2+(aq) -----> Tl2+(aq) + Ag+(aq) Step 3: Tl2+(aq) + Ce4+(aq) -----> Tl3+(aq) + Ce3+(aq)

Answers

The specie which is acting as a catalyst is; Ag+(aq).

Discussion:

The catalyst is a specie that exists in the same form at the beginning and end of the reaction.

The reaction's mechanism is as follows;

  • Step 1: Ag+(aq) + Ce⁴+(aq) <-----> Ag²+(aq) + Ce³+(aq)

  • Step 2: Tl+(aq) + Ag²+(aq) -----> Tl²+(aq) + Ag+(aq)

  • Step 3: Tl²+(aq) + Ce⁴+(aq) -----> Tl³+(aq) + Ce³+(aq)

Evidently, although Ag+(aq) was converted to Ag²+(aq) in Step 1 of the reaction; the Ag²+(aq) is reverted back to Ag+(aq) in Step 2 of the reaction.

Read more:

brainly.com/question/22498090

Answer:

Ag⁺ acts as the catalyst.

Explanation:

Hello,

In this case, each step is reorganized:

- Step 1:

Ag^+(aq) + Ce^(4+)(aq) \rightleftharpoons Ag^(2+)(aq) + Ce^(3+)(aq)

- Step 2:

Tl^+(aq) + Ag^(2+)(aq) \rightarrow  Tl^(2+)(aq) + Ag^+(aq)

- Step 3:

Tl^(2+)(aq) + Ce^(4+)(aq) \longrightarrow Tl^(3+)(aq) + Ce^(3+)(aq)

In such a way, Ag⁺ is converted to Ag²⁺ in the first step, but then it is regenerated to simple Ag⁺, therefore, Ag⁺ acts as the catalyst.

Best regards.

Conventional fossil fuels are harmful to the environment. Alternative solutions include using nuclear energy or solar energy. A decision to opt for solar power over nuclear energy might be based on which of these facts?A) Nuclear energy is highly unreliable and difficult to store.
B) Solar power plants can be easily set up over small tracts of land.
Eliminate
C) Wastes from nuclear power plants are harmful and difficult to manage.
D) Solar energy is independent of season and can be easily trapped and stored.

Answers

Answer:

C

Explanation:

Wastes from nuclear power plants are harmful and difficult to manage.

Answer:

C

Explanation:

What nuclide undergoes fission to form molybdenum-103, atomic number 42, tin-131, atomic number 50, and two neutrons? Element symbol: _______ mass number: _______

Answers

Answer:

The correct answer is Pu, 234.

Explanation:

In the given case, let us consider the reactant as X. Now the mass number (balanced) on both the sides will be,

Mass of X = Mass of Molybdenum + Mass of Tin + Mass of neutrons

M = 1 * 103 + 1 * 131 + 2 * 0

M = 234

Now the atomic number (balanced) on both the sides,

Atomic number of X = Atomic number of Molybdenum + Atomic number of Tin + Atomic number of neutrons

A = 1*42 + 1*50 + 2*1

A = 94

The atomic number 94 is for the element Plutonium, whose symbol is Pu. Thus, the reactant is 234-Pu.

1. What is the angular distance north or south from the earth's equator beginning at0° at the equator and ending at 90° at either pole?
a. Weather
b. Altitude
c. Latitude
d. Climate

Answers

Answer:

c. Latitude

Explanation:

The angular distance north or south from the earth's equator beginning at 0° at the equator and ending at 90° of either pole is the latitude.

The equator is a line of latitude that divided the earth into two hemispheres.

Only the equator is a great circle as a line of latitude. Others are small circles.

  • Weather is the atmospheric condition of a place over a short period of time
  • Climate is the average weather condition at a place over a long period of time.
  • Altitude of a place is its elevation above a reference plane.

What is the independent variable of the penny lab

Answers

The independent variable in the experiment is the soap and the dependent variable in the experiment is the number of water drops on the surface of the penny. The control is the penny without soap.