A certain substance X condenses at a temperature of 120.7 degree C. But if a 500, g sample of X is prepared with 55.4 g of urea (NH_2)_2 CO) dissolved in it, the sample is found to have a condensation point of 125.2 degree C instead. Calculate the molal boiling point elevation constant K_b of X. Round your answer to 2 significant digits.
Answers
Answer: The molal boiling point elevation constant of X is
Explanation:
Formula used for Elevation in boiling point :
or,
where,
= boiling point constant = ?
m = molality
= mass of solute (urea) = 55.4 g
= mass of solvent X = 500 g
= molar mass of solute (urea) = 60 g/mol
Now put all the given values in the above formula, we get:
Thus the molal boiling point elevation constant of X is
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A gas mixture with a total pressure of 770 mmHg contains each of the following gases at the indicated partial pressures: 128 mmHg CO2, 232 mmHg Ar, and 183 mmHg O2. The mixture also contains helium gas. What is the partial pressure of the helium gas?
Answers
Answer:
6
Explanation:
fpufjpufuodhodoyhupupddupud
the length of ribbon needed to tie around a vase
B.
the size of a student's waist
C.
the distance from the ground to the top of a ramp
D.
the circumference of an orange
Answers
Answer:
C
the distance from the ground to the top of a ramp
Answers
Answer: The new concentration of the solution is 0.143 M.
Explanation:
Given: = 300.0 mL,
= 0.335 M
= 700.0 mL,
= ?
Formula used is as follows.
Substitute values into the above formula as follows.
Thus, we can conclude that the new concentration of the solution is 0.143 M.
Final answer:
To find the new concentration of the solution, you can use the formula C1V1 = C2V2. Plugging in the given values, the new concentration of the solution is 0.144 M.
Explanation:
To find the new concentration of the solution, we can use the formula:
C1V1 = C2V2
Where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.
Plugging in the given values, we get:
(0.335 M)(300.0 mL) = C2(700.0 mL)
Solving for C2, we find the new concentration of the solution to be 0.144 M.
Learn more about concentration of a solution here:
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Answers
Answer:
8.912x10^-18
Explanation:
-dn/dt = pANa/2piMRT
100 g = initial copper
Number of moles = 100/63.546
= 1.5736
Mass of copper left = 100-10.0168
= 89.9832
Moles = 89.9832/63.546
= 1.4160
dn = 1.4160-1.5736
= -0.1576
dt = 2 hrs
A = 3.23mm² = 3.23x10^-6
M = 63.546
T = 0.0821
T = 1508k
Na = 6.023x10²³
When we insert all these into the formula above
We get
P = 8.912x10^-18atm
(B) False
Answers
Isopropyl methyl ether is slightly soluble in water because the oxygen atom of ethers with 3 or lesser carbon atoms can form hydrogen bonds with water. Therefore, the given statement is true.
What is hydrogen bonding?
Hydrogen bonding is a special class of attractive intermolecular forces that arise because of the dipole-dipole interaction between hydrogen that is bonded to a highly electronegative atom and another highly electronegative atom that lies in the neighborhood of the hydrogen atom.
For example, in water, hydrogen is covalently bonded to the oxygen atom. Therefore, hydrogen bonding arises because of the dipole-dipole interactions between the hydrogen atom of one water molecule and the oxygen atom of another water molecule.
The solubility of ether in water depends upon the extent of the formation of hydrogen bonds with water. Ether which contains three carbon atoms is soluble in water due to these lower hydrocarbon atoms can form hydrogen bonding with water.
But the solubility of hydrocarbons or ethers decreases as increase the number of carbon atoms. This is because higher ethers or ethers with more carbons have more hydrophobic parts. Therefore they cannot be soluble in water as they cannot form hydrogen bonds with water molecules.
Learn more about hydrogen bonding, here:
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Answer:
True
Hydrogen bond is a partial intermolecular bonding interaction between a lone pair on an electron rich donor atom, particularly the second-row elements nitrogen (N), oxygen (O), or fluorine (F), and the antibonding orbital of a bond between hydrogen (H) and a more
electronegative atom or group. Such an interacting system is generally denoted Dn–H···Ac, where the solid line denotes a polar covalent bond, and the dotted or dashed line indicates the hydrogen bond. The use of three centered dots for the hydrogen bond is specifically recommended by the IUPAC. While hydrogen bonding has both covalence and electrostatic contributions, and the degrees to which they contribute are currently debated, the present evidence strongly implies that the primary contribution is covelant.
Hydrogen bonds can be intermolecular (occurring between separate molecules) or
intramolecular (occurring among parts of the same molecule)
Answers
Answer:
Unsweetened tea
Explanation:
A concentrated solution is a solution that has more of the solute in it than the solvent (water).
A diluted solution is a solution that has more solvent (water) than the solute.
From the above we can say that the sweet tea contains more of the tea than water i.e it is concentrated hence, the taste is sweet. On the other hand, we can say that the unsweetened tea contains more water than the tea i.e it is diluted hence, the unsweetened taste.