How is energy transfer connected to your life

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Answer 1

Answer:

Answer:

Baking, microwave, heating system for your house, water boiler, fridge.

Related Questions

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1‑propanol ( nn ‑propanol) and 2‑propanol (isopropanol) form ideal solutions in all proportions. Calculate the partial pressure and the mole fraction ( yy ) of the vapor phase of each component in equilibrium with each of the given solutions at 25 °C. P∘prop=20.9 TorrPprop°=20.9 Torr and P∘iso=45.2 TorrPiso°=45.2 Torr at 25 °C. A solution with a mole fraction of xprop=0.243xprop=0.243 .
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Please ignore my answers because they are wrong.

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Answer:

The wavelength of the radio wave is 3.003 m.

The energy of the radio wave is $6.6194* 10^(-26) J$ .

Explanation:

Frequency of the radio waves, ν = 99.9 MHz = $99.9* 10^6 Hz$

Wavelength and frequency are related to each other by realtion:

$\lambda =(c)/(\nu )$

$\lambda$ = Wavelength of the wave

c = speed of the light

ν = Frequency of the wave

$\lambda =(3* 10^8 m/s)/(99.9* 10^6 s^(-1))=3.003 m$

The wavelength of the radio wave is 3.003 m.

The energy of the electromagnetic wave is given by Planck's equation:

$E=h* \nu$

h = Planck's constant = $6.626* 10^(-34) Js$

The energy of the radio wave with 99.9 MHz frequency will be:

$E=6.626* 10^(-34) Js* 99.9* 10^6 s^(-1)$

$E = 6.6194* 10^(-26) J$

The energy of the radio wave is $6.6194* 10^(-26) J$ .

You need to prepare an acetate buffer of pH 5.47 from a 0.809 M acetic acid solution and a 2.20 M KOH solution. If you have 680 mL of the acetic acid solution, how many milliliters of the KOH solution do you need to add to make a buffer of pH 5.47 ? The pa of acetic acid is 4.76. Be sure to use appropriate significant figures.

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Answer:

How do u post a picture as the question

Treatment of (S)-( )-5-methyl-2-cyclohexenone with lithium dimethylcuprate gives, after protonolysis, a good yield of a mixture containing mostly a dextrorotatory ketone A and a trace of an optically inactive isomer B. Treatment of A with zinc amalgam and HCl affords an optically active, dextrorotatory hydrocarbon C. Identify compounds A, B, and C, including stereochemical configurations. Be sure to explicitly draw H and both wedge/dash bonds at any configuration center.

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Answer:

use google and use the first link

Explanation:

Final answer:

Treatment of (S)-( )-5-methyl-2-cyclohexenone with lithium dimethylcuprate followed by protonolysis produces dextrorotatory ketone A and a trace of isomer B. Compound A can yield optically active, dextrorotatory hydrocarbon C when treated with zinc amalgam and HCl.

Explanation:

Treatment of (S)-( )-5-methyl-2-cyclohexenone with lithium dimethylcuprate followed by protonolysis yields a mixture containing primarily a dextrorotatory ketone A and a trace of an optically inactive isomer B. Compound A can be treated with zinc amalgam and HCl to produce an optically active, dextrorotatory hydrocarbon C.

To provide a specific identification and stereochemical configuration of compounds A, B, and C, I would need additional information or further context about the starting components and reaction conditions, as well as any other relevant data or observations.

Learn more about Treatment of (S)-( )-5-methyl-2-cyclohexenone with lithium dimethylcuprate here:

brainly.com/question/16556003

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Vanadium exhibits a variety of oxidation states. what is the oxidation state of vanadium in vpo3?

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Oxidation state is V(III)

I have always enjoyed eating tuna fish. Unfortunately,a study of the mercury content of canned tuna in 2010 foundthat chunk white tuna contains 0.6 ppm Hg and chunk lighttuna contains 0.14 ppm. (S. L. Gerstenberger, A. Martinson,and J. L. Kramer, Environ. Toxicol. Chem. 2010, 29, 237.) TheU.S. Environmental Protection Agency recommends no morethan 0.1 mg Hg/kg body weight per day. I weigh 68 kg. Howoften may I eat a can containing 6 ounces (1 lb 5 16 oz) ofchunk white tuna so that I do not average more than 0.1 mgHg/kg body weight per day? If I switch to chunk light tuna,how often may I eat one can?

Answers

Answer:

You can eat one chunk white tuna of 6 oz every 21,5 minutes

And, you can eat one chunk linght tuna of 6 oz every 5 minutes

Explanation:

The exposure to mercury may cause serious health problems, and is a threat to the development of the child in utero and early in life.

If you weight 68 kg you can eat:

68 kg * 0,1mgHg/ kg = 6,8 mg Hg per day

Chunk white tuna contains 0,6 mg Hg/kg

Thus, you can eat:

6,8 mg Hg * 1 kg tuna/ 0,6 mg Hg = 11,33 kg of chunk white tuna per day

In ounces:

11,33 kg * 35,274oz/ 1 kg = 400 oz per day

You can eat 66,7 6 ounces of chunk white tuna per day. One every 21,5 minutes

Chunk light tuna contains 0,14 mg Hg/kg

Thus, you can eat:

6,8 mg Hg * 1 kg tuna/ 0,14 mg Hg = 48,57 kg of chunk white tuna per day

In ounces:

48,57 kg * 35,274oz/ 1 kg = 1713 oz per day

You can eat 285,6 6 ounces of chunk white tuna per day. One every 5 minutes

I hope it helps!

What is the density ρh of hot air inside the balloon? assume that this density is uniform throughout the balloon. express the density in terms of th, tc, and ρc?

Answers

With the Ideal Gas formula.

Further Explanation

The ideal gas equation is an equation that presents the relationship between the pressure and volume of a gas with the temperature and the number of moles of the gas itself. This ideal gas equation is based on the laws of Boyle, Charles, and Avogadro.

This equation is generally written as

-PV = nRT

Boyle's Law (T = C)

Boyle's Law about the nature of gas was first created by Robert Boyle (1627¡1691). Boyle found experimentally that at a constant temperature, the pressure in a closed container would be inversely proportional to the volume of the gas. This means that if we press the gas and large volumes to small volumes, the gas pressure will rise, conversely if we expand the gas from small volumes to large volumes, the gas pressure will decrease. The process of pressing gas from large volumes to small volumes is called the compression process. While the process of changing the volume of gas from a small volume into a large volume is called the expansion process.

Gay Lussac Law (V = C)

The Gay Lussac Law was first coined by Joseph Louis Gay-Lussac (1778 - 1850) a chemist from France. Lussac's Gay Law states that under constant volume conditions, an increase in gas pressure will be directly proportional to an increase in gas temperature. This means that the gas in a closed container with a volume does not change (V0 = V1), so if the gas is heated from the initial temperature T0 to the final temperature T1 will cause the gas pressure also rises from the initial pressure (p0) to the final pressure (p1).

Charles Law (P = C)

Charles' ideal gas law is also called the law of constant pressure, first created by Jacques Alexandre Cesar Charles (1746 - 1823) a chemist from France. Charles's Law says "Under conditions of constant gas pressure, the volume of a gas will increase in proportion to the increase in temperature of the gas". This means that if we have a cylinder-piston system that can move up and down freely, then when the gas in the system is heated so that the temperature rises from T0 to T1, then to keep the gas pressure in the cylinder constant, the volume of gas will expand from the condition V0 to V1.

Learn more

The ideal gas equation brainly.com/question/10599201

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Grade: College

Subject: Chemistry

keywords: Gas, the ideal gas.

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What is the freezing point of a solution of 7.15 g MgCl2 in 100 g of water? K f for water is 1.86°C/m. What is the freezing point of a solution of 7.15 g MgCl2 in 100 g of water? K f for water is 1.86°C/m. -0.140°C -2.80°C -1.40°C -4.18°C