Which example shows an ecosystem of organisms? A. a single monkey B. a group of tree monkeys C. a group of tree monkeys and a cluster of trees D. a group of tree monkeys, a cluster of trees, a pile of rocks, and a fierce wind

Answers

Answer 1

Answer:

A single monkey is not an ecosystem

As ecosystem comprises of all the living and non living parts a community under study.

So if have define an ecosystem of which monkey is a part then we have to include the living organism like tress and monkey and the non living parts like rock and wind which affects the living organism.

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A solid that forms from a solution during a chemical reaction is called a(an)

Answers

Answer:

precipitate

Explanation:

Precipitation is the creation of a solid from a solution. When the reaction occurs in a liquid solution, the solid formed is called the 'precipitate'. The chemical that causes the solid to form is called the 'precipitant'.

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A lab group was calculating the speed of a radio car. They measured the distance traveled to be 6 meters and the time to be 3.5 seconds. Then they divided the distance by the time to find the speed. The actual speed was 2.2 m/s. What was their percent error?

Answers

Percent error is a measure of the difference between an observed value and a true value.

Actual Speed (True Value) = 2.2 m/s

Experimental Speed (Calculated Value) = Distance / Time = 6 m / 3.5 s = 1.714 m/s

The formula for calculating percent error is:

Percent Error = ((|Actual Value - Experimental Value|) / |Actual Value|) * 100%

Calculate the absolute difference between the actual speed and the experimental speed:

|2.2 - 1.714| = 0.486

Calculate the absolute value of the actual speed:

|2.2| = 2.2

Percent Error = (0.486 / 2.2) * 100%

= 0.221 * 100%

= 22.1%

The calculated percent error is approximately 22.1%. This means that the lab group's calculated speed of 1.714 m/s is about 22.1% lower than the true speed of 2.2 m/s.

Percent error is a way to quantify the accuracy of experimental measurements. A positive percent error indicates that the experimental value is higher than the true value, while a negative percent error indicates that the experimental value is lower. In this case, since the calculated speed is lower than the true speed, we have a positive percent error.

To know more about actual speed here

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Answer:456

Explanation:

Which three are advantages of asexual reproduction?A:Offspring are more likely to survive environmental changes.

B:Some offspring are more likely to survive a disease.

C:Less energy is required to reproduce.

D:The population can increase from only one parent.

E:The population can increase quickly.

Answers

C, D, and E

A and B cannot be true because asexual reproduction means the parent organism is essentially creating clones of itself, providing no variation in DNA and making all offspring vulnerable to the same environmental changes and diseases as the parent.

Answer:

sorry if I get this wrong I think it is C

Explanation:

Sodium phosphate and calcium chloride react to form sodium chloride and calcium phosphate. If you have 379.4 grams of calcium chloride and an excess of sodium phosphate, how much calcium phosphate can you make?

Answers

Answer:- 353.3 g

Solution:- The balanced equation is:

$2Na_3PO_4+3CaCl_2\rightarrow 6NaCl+Ca_3(PO_4)_2$

We start with given grams of calcium chloride and convert them to moles. Then using mol ratio, the moles of calcium phosphate are calculated and converted to grams as.

Molar mass of calcium chloride is 110.98 gram per mol and molar mass of calcium phosphate is 310 gram per mol.

The set is made using dimensional analysis as:

$379.4gCaCl_2((1molCaCl_2)/(110.98gCaCl_2))((1molCa_3(PO_4)_2)/(3molCaCl_2))((310gCa_3(PO_4)_2)/(1molCa_3(PO_4)_2))$

= $353.3gCa_3(PO_4)_2$

So, 353.3 grams of calcium phosphate can be formed.

Answer:

353.3g

Explanation:

The two reactions above, show routes for conversion of an alkene into an oxirane. If the starting alkene is cis-3-hexene the configurations of the oxirane products, A and B are Product A: _______ Product B: _______ Will either of these two oxirane products rotate the plane of polarization of plane polarized light

Answers

Answer:

Product A and B : (2R,3S)-2,3-diethyloxirane and (2S,3R)-2,3-diethyloxirane.

Explanation:

A double bond is converted to an oxirane through oxidation by peracids e.g. mCPBA (meta-chloroperoxybenzoic acid).

Epoxidation can occur at both face of double bond result in formation of two stereoisomers.

Product A and B : (2R,3S)-2,3-diethyloxirane and (2S,3R)-2,3-diethyloxirane

Both A and B contain plane of symmetry. Hence, both the products are achiral. So, they do not rotate the plane of polarization of plane polarized light.

Wich substances is most likely to form in a precipitation reaction?

Answers

Answer:

A precipitation reaction refers to the formation of an insoluble salt when two solutions containing soluble salts are combined. The insoluble salt that falls out of solution is known as the precipitate, hence the reaction's name.

Explanation:

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Sulfur dioxide and oxygen react to form sulfur trioxide during one of the key steps in sulfuric acid synthesis. An industrial chemist studying this reaction fills a 500. mL flask with 3.3 atm of sulfur dioxide gas and 0.79 atm of oxygen gas at 31.0 °C. He then raises the temperature, and when the mixture has come to equilibrium measures the partial pressure of sulfur trioxide gas to be 0.47 atm Calculate the pressure equilibrium constant for the reaction of sulfur dioxide and oxygen at the final temperature of the mixture. Round your answer to 2 significant digits.