CHEMISTRY COLLEGE

Sulfur dioxide and oxygen react to form sulfur trioxide during one of the key steps in sulfuric acid synthesis. An industrial chemist studying this reaction fills a 500. mL flask with 3.3 atm of sulfur dioxide gas and 0.79 atm of oxygen gas at 31.0 °C. He then raises the temperature, and when the mixture has come to equilibrium measures the partial pressure of sulfur trioxide gas to be 0.47 atm Calculate the pressure equilibrium constant for the reaction of sulfur dioxide and oxygen at the final temperature of the mixture. Round your answer to 2 significant digits.

Answers

Answer 1

Answer:

Answer:

0.051

Explanation:

Let's consider the following reaction.

2 SO₂(g) + O₂(g) ⇄ 2 SO₃(g)

We can compute the pressures using an ICE chart.

2 SO₂(g) + O₂(g) ⇄ 2 SO₃(g)

I 3.3 0.79 0

C -2x -x +2x

E 3.3-2x 0.79-x 2x

The partial pressure of sulfur trioxide gas is 0.47 atm. Then,

2x = 0.47

x = 0.24

The pressures at equilibrium are:

pSO₂ = 3.3-2x = 3.3-2(0.24) = 2.82 atm

pO₂ = 0.79-x = 0.79-0.24 = 0.55 atm

pSO₃ = 0.47 atm

The pressure equilibrium constant (Kp) is:

Kp = pSO₃² / pSO₂² × pO₂

Kp = 0.47² / 2.82² × 0.55

Kp = 0.051

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Answers

The answer is A hope this helps

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Answers

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Explanation: Hope it works!!!!!

For the following reaction at equilibrium, which gives a change that will shift the position of equilibrium to favor formation of more products? 2NOBr(g) 2NO(g) + Br 2(g), ΔHº rxn = 30 kJ/mol

Answers

Answer:

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Answers

Answer : The value of 'x' for this expression is, 5.59

Explanation :

The given expression is:

$875=5x^3$

Now we have to determine the value of 'x' by solving the above expression.

$875=5x^3$

$(875)/(5)=x^3$

$175=x^3$

$x=(175)^(1/3)$

$x=5.59$

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Refer to the example about diatomic gases A and B in the text to do problems 20-28.It was determined that 1 mole of B2 is needed to react with 3 moles of A2.
How many grams in one mole of B2?
__g

Answers

Final answer:

The number of grams in one mole of B2 can be calculated using the atomic mass of element B. This is found on the periodic table and then doubled for B2 since it's diatomic. If B is Oxygen for instance, 1 mole of B2 (O2) weighs 32 grams.

Explanation:

To find the number of grams in one mole of B2, we need to know the atomic mass of element B, which isn't provided in your question. However, you can find this information on the periodic table. Once you have the atomic mass of B, you can calculate the molar mass of B2 (which is two times the atomic mass of B) since 1 mole of a substance corresponds to its molar mass in grams.

For example, if element B is Oxygen (O), its atomic mass is approximately 16 g/mol. Therefore, the molar mass of B2 (O2 in this case) would be 32 g/mol. Hence, 1 mole of B2 (or O2) would weigh 32 grams.

Learn more about Molar Mass here:

brainly.com/question/12127540

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Match the vocabulary word with the defination.___1.Hypothesis
___2.Variables
___3.Conclusion
___4.Scientific Method
___5.Procedure

a.The steps you take to complete the experiment
b.Factors that changes in an experiment
c.A possible solution to a problem
d.The result of the experiment
e.The process scientist follow to complete an investigation

Answers

Hypothesis - A possible solution to a problem

Variables - Factors that changes in an experiment

Conclusion - The result of the experiment

Scientific Method - The process scientists follow to complete an investigation

Procedure - The steps you take to complete the experiment

Answer:

1. d

2. b

3. d

4. e

5. a

explanation:

there's nothing else to explain

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