Consider the following chemical equilibrium: C(s) + 2H2 (g) <------> CH4 (g)
Now write an equation below that shows how to calculate Kp from Kc for this reaction at an absolute temperature T. You can assume T is comfortably above room temperature. If you include any common physical constants in your equation be sure you use their standard symbols, found in the ALEKS Calculator.
Answers
Answer:
Kp = [CH₄(g)]/[H₂(g)]²(RT)⁻¹
Explanation:
C(s) + 2H₂(g) => CH₄(g)
Kp = Kc(RT)ⁿ
n= change in molar volumes of gas = 1 - 2 = -1
R = 0.08206 L·Atm/mol·K (gas constant)
T = Kelvin Temperature (arbitrary in problem) K =°C + 273
Kc = [CH₄(g)]/[H₂(g)]² (measured values need to be in moles/L)
Kp = [CH₄(g)]/[H₂(g)]²(RT)⁻¹
Related Questions
For the reaction shown, find the limiting reactant for each of the initial quantities of reactants.4Al(s) + 302(g) —> 2Al2O3(s)Express your answer as a chemical formula. 1 mol Al; 1 mol O2 4 mol Al; 2.5 mol O2 12 mol Al; 10 mol O2 15.4 mol Al; 10.7 mol O2
1‑propanol ( nn ‑propanol) and 2‑propanol (isopropanol) form ideal solutions in all proportions. Calculate the partial pressure and the mole fraction ( yy ) of the vapor phase of each component in equilibrium with each of the given solutions at 25 °C. P∘prop=20.9 TorrPprop°=20.9 Torr and P∘iso=45.2 TorrPiso°=45.2 Torr at 25 °C. A solution with a mole fraction of xprop=0.243xprop=0.243 .
What is the mass of a neutron close to
How many moles of oxygen are in 8.24 moles Mg(NO3)2
Answers
Answer:
C6H14 < C6H13Br < C6H13OH < C6H12(OH)2
Explanation:
Hello,
In this case, since the solubility in water is related with the presence of polar bonds in the given molecules we can see that C6H12(OH)2 has the presence two O-H bonds which promote the highest solubility via hydrogen bonds as well as the C6H13OH but in a lower degree as only on O-H bond is present. Next since the bond C-Br in is slightly close to the polar bond C6H13Br rather than the C-C bonds only had by C6H14 we can infer that C6H13Br is more soluble in water than C6H14, therefore the required order is:
C6H14 < C6H13Br < C6H13OH < C6H12(OH)2
Whereas C6H12(OH)2 is the most soluble and C6H14 the least soluble in water.
Best regards.
Answers
B:Some offspring are more likely to survive a disease.
C:Less energy is required to reproduce.
D:The population can increase from only one parent.
E:The population can increase quickly.
Answers
A and B cannot be true because asexual reproduction means the parent organism is essentially creating clones of itself, providing no variation in DNA and making all offspring vulnerable to the same environmental changes and diseases as the parent.
Answer:
sorry if I get this wrong I think it is C
Explanation:
Answers
Final answer:
A chemical change or reaction between elements or compounds may occur when there is enough energy present. This can be in the form of heat, light, or electricity. An example of this is the reaction between hydrogen and oxygen to form water, which requires a spark.
Explanation:
If two or more elements or chemical compounds come into contact with one another and there is enough energy present, a chemical change may take place. This is because a chemical reaction, which represents a chemical change, requires energy to break the bonds of the reactants and form new bonds in the products. This energy can be in various forms such as heat, light, or electricity.
For example, the reaction between hydrogen and oxygen to form water is a chemical change that requires energy in the form of a spark. On the other hand, an exothermic reaction, such as the combustion of gasoline, releases energy in the form of heat and light.
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Answer:
energy
Explanation:
"If two or more elements or chemical compounds come into contact with one another and there is enough energy present, a chemical change may take place." this was on a science lesson, it's correct.
Answers
Answer:
THE NEW FREEZING POINT IS -4.196 °C
Explanation:
ΔTf = 1 Kf m
molarity of MgCl2:
Molar mass = (24 + 35.5 *2) g/mol
molar mass = 95 g/mol
7.15 g of MgCl2 in 100 g of water
7.15 g = 100 g
(7.15 * 100 / 1000) = 1000 g or 1 L or 1 dm3
= 0.715 g /dm3
Molarity in mol/dm3 = molarity in g/dm3 / molar mass
= 0.715 g /dm3 / 95 g/mol
m = 0.00752 mol/ dm3
So therefore:
ΔTf = i Kf m
1 = 3 (1 Mg and 2 Cl)
Kf = 1.86 °C/m
M = 0.752 moles
So we have:
ΔTf = 3 * 1.86 * 0.752
ΔTf = 4.196 °C
The new freezing point therefore will be 0 °C - 4.196 °C which is equals to - 4.196 °C
Answers
Answer:
M
Explanation:
Henry's law relational the partial pressure and the concentration of a gas, which is its solubility. So, at the sea level, the total pressure of the air is 1 atm, and the partial pressure of O2 is 0.21 atm. So 21% of the air is O2.
Partial pressure = Henry's constant x molar concentration
0.21 = Hx1.38x
H =
H = 152.17 atm/M
For a pressure of 665 torr, knowing that 1 atm = 760 torr, so 665 tor = 0.875 atm, the ar concentration is the same, so 21% is O2, and the partial pressure of O2 must be:
P = 0.21*0.875 = 0.1837 atm
Then, the molar concentration [O2], will be:
P = Hx[O2]
0.1837 = 152.17x[O2]
[O2] = 0.1837/15.17
[O2] = M
Final answer:
The molar concentration of O2 in the surface water of a mountain lake at 20 °C and an atmospheric pressure of 665 torr is approximately 1.21×10-3 M.
Explanation:
To calculate the molar concentration of O2 in the surface water of a mountain lake using Henry's law, we first need to understand how pressure affects the solubility of gases and vice versa.
As per Henry's law, at a constant temperature, the solubility of a gas in a liquid is directly proportional to the pressure of the gas above the liquid. The partial pressure of O2 in air at sea level is 0.21 atm. This means that when the atmospheric pressure is 1 atm, the molar concentration of O2 is 1.38×10−3 M. At higher altitudes, the atmospheric pressure reduces. The given atmospheric pressure at the mountain lake is 665 torr, which is approximately 0.875 atm.
Using these values in Henry's law, the molar concentration of O2 can be calculated as:
C = P * x
where C is molar concentration, P is atmospheric pressure, and x is given solubility at 1 atm. Substituting the values:
C = (0.875 atm) * (1.38×10−3 M) = 1.21x10-3 M approximately
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