CHEMISTRY COLLEGE

How many grams of Cl are in 31.2g CF2Cl2

Answers

Answer 1
Answer:

Answer:

Mass = 42.6 g

Explanation:

Given data:

Mass of CF₂Cl₂ = 31.2 g

Mass of Cl₂ = ?

Solution:

Number of moles of CF₂Cl₂ = mass/molar mass

Number of moles =  31.2 g/121 gmol

Number of moles = 0.3  mol

1 mole of CF₂Cl₂ contain 2 moles of Cl atom.

0.3 mol × 2 = 0.6 mol

Mass of Cl₂:

Mass = number of moles × molar mass

Mass = 0.6 mol × 71 g/mol

Mass = 42.6 g

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According to the valence bond theory the triple bond in ethyne consists of

Answers

Answer:
            According to the valence bond theory the triple bond in ethyne consists of one sigma bond and two pi bonds.

Explanation:
                   Atomic number of carbon is 6. The ground state electronic configuration of carbon is as follow,

                                         1s², 2s², 2p²

And the excited state electronic configuration of carbon is as follow,

                                         1s², 2s¹, 2px¹, 2py¹, 2pz¹

In ethyne the 2s¹ orbital and 2px¹ orbitals having unpaired electrons form sigma bonds by head to head overlapping with orbitals of hydrogen atom and carbon atom. The remaining 2py¹ and 2pz¹ orbitals of both carbons overlap perpendicular to the existing sigma bond resulting in the formation of two pi bonds.

A primary amine contains a five-membered carbon ring. The degree of unsaturation for the five-membered carbon ring is equal to three. In the chemical formula, there are seven carbon atoms. Determine its chemical formula.

Answers

Answer:

C₇H₁₁N

Explanation:

To find the chemical formula, first, let's evaluate the given conditions.

1.Is a primary amine:

This means that the amine is connected to a carbon, like NH₂-R

2.The degree of unsaturation of the five-membered carbon ring is equal to three:

One of the degrees of unsaturation is for the five-membered carbon ring, the other two are for pi-bonds. This means that the five-membered carbon ring has 2 pi-bonds inside.

3.There are seven carbon atoms:

Five of these seven carbons are for the carbon ring and the other two are bonded to the primary amine.

From all of the above, we have that the chemical formula is:

C₅H₅-C₂H₄-NH₂ = C₇H₁₁N  

I hope it helps you!

Three samples of a solid substance composed of elements A and Z were prepared. The first contained 4.31 g A and 7.70 g Z. The second sample was 35.9% A and 64.1% Z. It was observed that 0.718 g A reacted with Z to form 2.00 g of the third sample. Show that these data illustrate the law of definite composition.

Answers

Answer:

The percentage composition of the elements of the compound in the three samples is the same.

Explanation:

The law of definite proportions states that all pure samples of a particular chemical compound contain the same elements in the same proportion by mass.

Sample A:

Mass of A = 4.31 g; mass of Z = 7.70 g

Total mass of sample = 12.01

Percentage mass of A in the sample = (4.31 * 100)/12.01 = 35.9 %

Percentage mass of Z in the sample = (7.70 * 100)/12.01 = 64.1 %

Sample B:

Percentage mass of A in the sample = 35.9 %

Percentage mass of Z in the sample = 64.1 %

Sample C:

Mass of A = 0.718 g; Total mass of sample = 2.00 g

mass of Z = mass of sample - mass of A = 2.00 g - 0.718 g = 1.282 g

Percentage mass of A in the sample = (0.718 * 100)/2.00 = 35.9 %

Percentage mass of Z in the sample = (1.282 * 100)/2.00 = 64.1 %

From the calculations, it can be seen that the percentage composition of the elements in the compound is the same for the three samples.

The _______ are found on the left side of the arrow in a chemical reaction. A. coefficients B. reactants C. products D. subscripts

Answers

B reactants then C is on the right side! If you take h2O and air (the reactants) then the product would be a snowflake. happy holidays!!

Answer:

Reactants

Explanation:

Please help me and promise I will mark as brainiest I need it in ISEF please how much energy does the vehicle hydrogen fuel cell need to break hydrogen into ions ?! ​

Answers

Answer: A typical hydrogen fuel cell produces 0.5 V to 0.8 V per cell. To increase the voltage individual cells can be connected in series.

Under what circumstances may a health insurer charge a higher premium to a woman with a genetic disposition to breast cancer? a) Her mother has breast cancer but she doesn't. b) She has breast cancer. c) Her sister has breast cancer but she doesn't. d) Health insurers can never discriminate based on genetic information in this way.

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D. Health insurer can never discriminate based on genetic information in this way
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