Choose the correct statement(s) for the following reaction: 8Fe(s) + S8 (s) → 8 FeS (s) (a) Iron is being oxidized. (b) Iron is being reduced. (c) Sulfur is being oxidized. (d) Sulfur is being reduced

Answers

Answer 1
Answer:

Answer:

(a) Iron is being oxidized.

(d) Sulfur is being reduced.

Explanation:

Let's consider the following redox reaction.

8 Fe(s) + S₈(s) → 8 FeS(s)

Iron is being oxidized according to the following oxidation half-reaction:

Fe(s) → Fe²⁺(s) + 2 e⁻

Sulfur is being reduced according to the following reduction half-reaction:

S₈(s) + 16 e⁻ → 8 S²⁻(s)


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Increasing which factor will cause the gravitational force between two objects to decrease?weights of the objects
distance between the objects
acceleration of the objects
masses of the objects

Answers

Increasing distance between the objects factor will cause the gravitational force between two objects to decrease. Therefore, option B is correct.

What causes gravitational force to decrease?

The gravitational force grows in proportion to the size of the masses . The gravitational force weakens rapidly as the distance between masses grows. Unless at least one of the objects has a lot of mass, detecting gravitational force is extremely difficult.

Gravity is affected by object size and distance between objects. Mass is a unit of measurement for the amount of matter in an object.

The force of gravity is proportional to the masses of the two objects and inversely proportional to the square of the distance between them. This means that the force of gravity increases with mass but decreases as the distance between objects increases.

Thus, option B is correct.

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Answer:

B

Explanation:

Practice the Skill 21.15b When the following ketone is treated with aqueous sodium hydroxide, the aldol product is obtained in poor yields. In these cases, special distillation techniques are used to increase the yield of aldol product. Predict the aldol addition product that is obtained, and propose a mechanism for its formation. For the mechanism, draw the curved arrows as needed. Include lone pairs and charges in your answer. Do not draw out any hydrogen explicitly in your products. Do not use abbreviations such as Me or Ph.

Answers

Answer:

Check the explanation

Explanation:

Kindly check the attached image below for the step by step explanation to the question above.

What is the molarity of a 27.0% (v/v) aqueous ethanol solution? the density of ethanol (c2h6o, molar mass 46.07 g/mol) is 0.790 g/ml?

Answers

Answer:

M=4.63M

Explanation:

Hello,

In this case, with the given by-volume percentage and considering the molarity as:

M=(n_(Ethanol))/(V_(solution))

We assume the solution having 100 mL of volume in total, thus, the volume of ethanol is 27.0 mL, therefore, the moles:

n_(Ethanol)=27.0mL*(0.790g)/(1mL)*(1mol)/(46.07g)=0.463molEthanol

Moreover, the volume of the solution in liters is:

V_(solution)=100mL*(1L)/(1000mL) =0.1L

Finally, the molarity is:

M=(0.463mol)/(0.1L)\n M=4.63M

Best regards.

If the density of ethanol (c2h6o, molar mass 46.07 g/mol) is 0.790 g/ml, the molarity of the 27.0% (v/v) aqueous ethanol solution is 17.14 M.

Calculate the moles of ethanol contained in the solution, then divide that number by the volume of the solution in litres to determine the molarity of the ethanol solution.

To start, we must ascertain how much ethanol is included in each 100 millilitres of the solution. Given that ethanol has a density of 0.79 g/ml, the amount of ethanol in 100 millilitres is as follows:

Mass of ethanol = density × volume

Mass of ethanol = 0.790 g/ml × 100 ml = 79 g

Now,

Moles of ethanol = mass / molar mass

Moles of ethanol = 79 g / 46.07 g/mol = 1.714 mol

So,

Volume of solution = 100 ml / 1000 ml/L = 0.1 L

We know that:

Molarity = moles of solute / volume of solution

Molarity = 1.714 mol / 0.1 L = 17.14 M

Thus, the molarity is 17.14 M.

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What substance is used in the industrial preparation of methyl diantilis to reduce the aldehyde group of 3-ethoxy-4-hydroxybenzaldehyde?

Answers

The substance that is used for the industrial preparation of methyl diantilis is called the sodium borohydride (NaBH4).

Industrial preparation of methyl diantilis:

Methyl diantilis is a substance that has an elegant fragrance with a similar olfactive note to Isoeugenol.

It is used as complexing agent for vanilla, tobacco, leather and fruit accords.

It can be prepared industrially by the reduction of 3-ethoxy-4-hydroxybenzaldehyde (ethyl vanillin) to 3-ethoxy-4-hydroxybenzyl alcohol.

To reduce the aldehyde group of 3-ethoxy-4-hydroxybenzaldehyde, sodium borohydride is added in the industrial preparation process.

The sodium borohydride (NaBH4) produces a phenol functional group with other reactants leading to reduction of aldehyde group and increase in the solubility of reactants.

Therefore, the substance that is used for the industrial preparation of methyl diantilis is called the sodium borohydride (NaBH4).

Learn more about aldehydes here:

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Answer:

            Sodium Borohydride (NaBH₄)

Explanation:

                    Methyl diantilis (2-Ethoxy-4-(methoxymethyl)phenol) is a fragrance compound which smells like Vanilla. This compound is being synthesized from 3-ethoxy-4-hydroxybenzaldehyde also known as Ethyl Vanillin in two steps.

Step 1: Reduction of Aldehydic Group on Ethyl Vanillin:

The benzaldehyde derivative is treated with a mild reducing agent i.e. NaBH₄ (Sodium Borohydride). NaBH₄ is a source of Hydride (H⁻) ion and undergoes nucleophilic substitution reaction yielding 2-ethoxy-4-(hydroxymethyl)phenol.

Step 2: Etherification of 2-ethoxy-4-(hydroxymethyl)phenol:

In the second step 2-ethoxy-4-(hydroxymethyl)phenol is treated with Methanol in the presence of strong acidic polymeric resin known as Amberlyst-15-wet resulting in the formation of Methyl diantilis as shown in attached figure.

What is the partial pressure of nitrogen in a container that contains 3.96mol of oxygen, 7.49 mol of nitrogen and 1.19 mol of carbon dioxide when the total pressure is 563 mmHg?

Answers

Answer:

333.6 atm

Explanation:

The following data were obtained from the question:

Mole of O2 (nO2) = 3.96 moles

Mole of N2 (nN2) = 7.49 moles

Mole of CO2 (nCO2) = 1.19 moles

Total pressure = 563 mmHg

Partial pressure of N2 =..?

Next, we shall determine the total number of mole in the container.

This can be obtained as follow:

Mole of O2 (nO2) = 3.96 moles

Mole of N2 (nN2) = 7.49 moles

Mole of CO2 (nCO2) = 1.19 moles

Total mole =?

Total mole = nO2 + nN2 + nCO2

Total mole = 3.96 + 7.49 + 1.19

Total mole = 12.64 moles

Next, we shall determine the mole fraction of N2.

This can be obtained as follow:

Mole fraction = mole of substance/total mole

Mole of N2 (nN2) = 7.49 moles

Total mole = 12.64 moles

Mole fraction of N2 =?

Mole fraction of N2 = 7.49/12.64

Finally, we shall determine the partial pressure of N2.

This can be obtained as follow:

Mole fraction of N2 = 7.49/12.64

Total pressure = 563 mmHg

Partial pressure of N2 =..?

Partial pressure = mole fraction x total pressure

Partial pressure of N2 = 7.49/12.64 x 563

Partial pressure of N2 = 333.6 atm

The, the partial pressure of nitrogen, N2 is 333.6 atm

On average, about ____________ of incoming solar radiation is reflected back to space.A 50%
B 30%
C 20%
D 10%

Answers

I believe it B 30% hope that helps
I think it’s B I’m not sure sorry if it’s wrong