An imaginary line dividing the earth's surface into two hemisphere the northern and southern hemisphere, it is locatedat 0⁰, which of the following imaginary lines is being described? a.equator b.latitude c.longitude d.prime meridian​

Answers

Answer 1
Answer:

Answer:

A. Equator

Explanation:

The equator is located in the centre of the Earth, dividing the northern and southern hemispheres.

Answer 2
Answer:

Answer:

Equator because equator divides the earth into Northern and Southern hemisphere.


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The image formed by a lens may be real or virtual. The image formed by a lens is always virtual.

Answers

There are types of lens; concave and convex lens.
The concave lens is a lens which has an inward curve in the middle, that is, the edges of the curve are thicker than the center of the lens, because of this, any light that enter the lens will spread out [diverge]. An image will look smaller and upright when viewed by a concave lens. Image formed by concave lens are usually VIRTUAL. 
A concave lens will produce a real image ONLY if the object is located beyond the focal point of the lens.
A convex lens is a converging lens, this is because, the center of the lens is thicker than its edges. Any ray of light that passes through the lens will converge at the middle of the lens at point called principal focus.  A convex lens produce a VIRTUAL image when the object is placed infront of the focal point. The virtual image formed is always magnified and upright.

The image formed by any lens like concave and convex may be real or virtual.

How many types of lens are present?

Mainly two types of lens are present and that are concave lens also known as divergent lens and convex lens, also known as convergent lens.

  • Any light passing through the lens will disperse [diverge]. When viewed through a concave lens, an image seems smaller and more upright. Concave lenses frequently produce VIRTUAL images and concave lens will produce a real image only if the object is located beyond the focal point of the lens.
  • Any beam of light passing through the lens will converge in the lens's center, known as the main focus. When an object is placed in front of the focal point, a convex lens produces a VIRTUAL image. The resulting virtual picture is constantly amplified and oriented vertically.

Hence image formed by a lens may be real or virtual.

To know more about concave & convex lens, visit the below link:

brainly.com/question/10256006

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For each of the following redox reactions in the, identify the oxidizing agent and the reducing agent.2Na(aq)+2H2O(l)→2NaOH(aq)+H2(g)
C(s)+O2(g)→CO2(g)
2MnO−4(aq)+5SO2(g)+2H2O(l)→2Mn2+(aq)+5SO2−4(aq)+4H+(aq)

Answers

anywhere between 5sogt2 and 776sogt2

An element x is found to have a mass number of 31 and atomic number of 17. idenrify the group and the period to which it belongs?

Answers

Answer:

Well atomic number 17 is Chlorine, which is most commonly found as a gas, and is period 7.

Explanation:

elements found on period 7 are some of the most unstable elements.

Complete and balance the equation for the following acid-base neutralization reaction. If water is used as a solvent, write the reactants and products as aqueous ions. In some cases, there may be more than one correct answer, depending on the amount of reactants used.(a)Mg(OH)2 + HClO4?
(b)SO3 + H2O? (Assume an excess of water and that the product dissolves)
(c) SrO + H2SO4?

Answers

Explanation:

A balanced equation is defined as the one that has equal number of atoms of all the elements present on both reactant and product side.

(a) Mg(OH)_(2) + HClO_(4) \rightarrow Mg(ClO_(4))_(2) + H_(2)O

Number of atoms on reactant side are as follows.

Mg = 1

O = 6

H = 3

Cl = 1

Number of atoms on product side are as follows.

Mg = 1

O = 9

H = 2

Cl = 2

So, to balance this equation we multiply Mg(OH)_(2) by 2 on reactant side and multiply H_(2)O by 2 on product side.

Therefore, the balanced reaction equation is as follows.

       2Mg(OH)_(2) + HClO_(4) \rightarrow Mg(ClO_(4))_(2) + 2H_(2)O  

(b)  SO_(3) + H_(2)O \rightarrow H_(2)SO_(4)

Number of atoms on reactant side are as follows.

S = 1

O = 4

H = 2

Number of atoms on product side are as follows.

S = 1

O = 4

H = 2

Therefore, this equation is balanced as it has same number of atoms on both reactant and product side.

(c)  SrO + H_(2)SO_(4) \rightarrow SrSO_(4) + H_(2)O

Number of atoms on  reactant side are as follows.

Sr = 1

O = 1

H = 2

S = 1

O = 4

Number of atoms on product side are as follows.

Sr = 1

O = 1

H = 2

S = 1

O = 4

Therefore, this equation is balanced.

When 1-iodo-1-methylcyclohexane is treated with NaOCH2CH3 as the base, the more highly substituted alkene product predominates. When KOC(CH3)3 is used as the base, the less highly substituted alkene predominates. Give the structures of the two products and offer an explanation.

Answers

Answer:

See explanation

Explanation:

In this case, we have 2 types of reactions. CH_3CH_2ONa is a strong base but only has 2 carbons therefore we will have less steric hindrance in this base. So,  the base can remove hydrogens that are bonded on carbons 1 or 6, therefore, we will have a more substituted alkene (1-methylcyclohex-1-ene).

For the  KOC(CH_3)_3 we have more steric hindrance. So, we can remove only the hydrogens from carbon 7 and we will produce a less substituted alkene (methylenecyclohexane).

See figure 1

I hope it helps!

Which response gives the products of hydrolysisofNH4Cl?
A. NH4+ + HCl
B. NH3 + OH- + HCl
C. NH3 + H+
D. NH4OH + HCl
E. No hydrolysis occurs.

Answers

Answer : The correct option is, (C) NH₃ + H⁺

Explanation:

Hydrolysis : It is defined as the chemical reaction in which the breakdown of compound takes place due to reaction with water.

As per question:

First ammonium chloride completely dissociates into ion.

NH_4Cl(aq)\rightarrow NH_4^+(aq)+Cl^-(aq)

Now ammonium ion react with water to give ammonia and hydronium or hydrogen ion.

The balanced hydrolysis reaction will be:

NH_4^++H_2O\rightarrow NH_3+H_3O^+

Hence, the correct option is, (C) NH₃ + H⁺

Answer:

NH₃ and H⁺

Explanation:

The dissociation of NH₄Cl will lead to two ions , i.e. , NH⁴⁺  and Cl⁻ .

Hence , the reaction is -

NH₄Cl  →  NH⁴⁺   +   Cl⁻

We can conclude that  NH₄Cl can be formed from the ions , NH⁴⁺  and Cl⁻

Hence ,

According to the reaction ,

NH⁴⁺ + H₂O  ⇆  NH₃ + H₃O⁺

Therefore ,

The reactant that will lead to the formation of NH₄Cl are -  NH₃ and H⁺