Estimate how much heat in joules is released when 25.0 g of water (C = 4.184 J/g°C) is cooled from 80.0°C to 30.0°C?

Answers

Answer 1

Answer:

The amount of heat will be 5230 j.

What is heat?

Heat is a type of energy that is transferred between both the system and its surroundings as a result of temperature variations.

Calculation of heat.

Given data:

Mass = 25.0 g = 0.025 kg

C = 4.184 J/g°C

$T_(1)$ = 80.0°C

$T_(2)$ = 30.0°C

Q= ?

By using the formula of heat.

Q = MC ( $T_(2) - T_(1)$ )

Put the value of given data in heat equation.

Q(heat) = 0.025 × 4.184 ( 30 - 80)

Q(heat) = 5230 J.

Therefore, the amount of heat will be 5230 J.

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Answer 2

Answer:

Answer:

5230 J

Explanation:

m = 25 g = 0,025 kg

c = 4,184 J /(g * °C) = 4184 J /(kg * °C)

$t_(1)$ = 80 °C

$t_(2)$ = 30 °C

The formula is Q = c *m * ( $t_(2) - t_(1)$ )

Calculating:

Q = 4184 * 0,025 * (30 - 80) = 5230 J

Note that we get a negative heat (-5230 J). It just means that it is released.

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A 25.0mL solution acetic acid (CH3CO2H) is titrated with 0.20M NaOH and reaches the endpoint after the addition of 16.3mL of NaOH. What is the concentration of acetic acid in solution

Answers

Answer: 0.1304M

Explanation: Please see the attachments below

Final answer:

The concentration of acetic acid in the solution is 0.1304 M.

Explanation:

To determine the concentration of acetic acid in solution, we can use the concept of stoichiometry and the balanced chemical equation for the reaction between acetic acid and sodium hydroxide. The balanced equation is:

CH3CO2H + NaOH -> CH3CO2Na + H2O

From the balanced equation, we can see that 1 mole of acetic acid reacts with 1 mole of sodium hydroxide. In order to calculate the moles of acetic acid, multiply the volume of NaOH used (16.3 mL) by the molarity of NaOH (0.20 M), then divide the result by 1000 to convert mL to L:

Moles of acetic acid = (16.3 mL NaOH x 0.20 M NaOH) / 1000 = 0.00326 moles

Now, to calculate the concentration of acetic acid in the solution, we divide the moles of acetic acid by the volume of the solution in litres:

Concentration of acetic acid = (0.00326 moles) / (25.0 mL x 1 L/1000 mL) = 0.1304 M

This means that the concentration of the acetic acid in the solution is 0.13M.

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Which two structures will provide a positive identification of a plant cell under a microscope? A.) Lysosomes, cell wall. B.) large central vacuole, cell wall. C.) large central vacuole ribosomes. D.)nucleoid, chloroplasts.

Answers

The Right Answer Is D.) Nucleoid chloroplasts.

the answer is B large central vacuole and cell wall. they are the easiest/biggest things to see under a microscope to identify a plant cell

Differentiate between the formation of biochemical rocks and the formation of inorganic chemical rocks.Biochemical rocks form from organisms that were once alive, such as limestone from marine shells, whereas inorganic chemical rocks form from non-biological processes, such as salt that is left behind when a lake evaporates.

Answers

In contrast to inorganic chemical rocks, which result from non-biological processes such as salt left over when a lake evaporates, biochemical rocks are formed by once-living creatures, such as limestone from marine shells.

The process, which is inorganic and frequently the consequence of a body of water evaporating and concentrating the ions, occurs in chemical sedimentary rocks. The formation of one kind of sedimentary rock may be mediated by both chemical (inorganic) and biological (organic) processes. Aragonite and calcite make up limestone. The majority of limestone is biological in origin, while it can also occur as a chemical sedimentary rock that forms inorganically as a result of precipitation. In actuality, limestone is the biochemical sedimentary rock that is found most frequently. In marine (i.e., oceanic or salty sea) settings, nearly all limestone

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Draw the structure of a compound with the molecular formula CgH1002 that exhibits the following spectral data. (a) IR: 3005 cm-1, 1676 cm-1, 1603 cm-1
(b) H NMR: 2.6 ppm (singlet, I = 3H), 3.9 ppm (singlet, I = 3H), 6.9 ppm (doublet, I = 2H), 7.9 ppm (doublet, I = 2H)
(c) 13C NMR: 26.2, 55.4, 113.7, 130.3, 130.5, 163.5, 196.6 ppm ?

Answers

Answer:

The answer you are looking for is A

What is the percent composition of nitrogen in sodium nitride

Answers

The percent composition of nitrogen in sodium nitride is 16.86%

What is sodium nitride?

Sodium nitride is an inorganic compound that is used in preservatives and antidote for cyanide poisoning.

The molar mass of Na3N is 83 M

The mass of Na3N is 14 g

$% \;of \;N = (mass of N)/( molar mass of Na3N ) * 100$

$\% \;of \;N = (mass\; of \;N)/(molar\; mass\; of\; Na3N) * 100\n\n\n\% \;of \;N = (14)/(83) * 100 = 16.86\%$

Thus, the percent composition of nitrogen in sodium nitride is 16.86%.

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Answer:

16.86%

Explanation:

Na3N is sodium nitride.

% of N = mass of N/ molar mass of Na3N *100

% of N = 14/83*100= 16.86%

(II) To make a secure fit, rivets that are larger than the rivet hole are often used and the rivet is cooled (usually in dry ice) before it is placed in the hole. A steel rivet 1.872cm in diameter is to be placed in a hole 1.870cm in diameter in a metal at 22°C. To what temperature must the rivet be cooled if it is to fit in the hole

Answers

Given:

Rivet diameter, $d_(r)$ = 1.872 cm

Hole diameter, $d_(h)$ = 1.870 cm

Temperature, $T_(2)$ = 22 °C

Formula Used:

$\alpha = (\Delta d)/(d* \Delta T)$

where,

$\alpha$ = coefficient of linear expansion

$\Delta d$ = change in diameter = $d_(h) - d_(r)$

$\Delta T}$ = change in temperature = $T_(2) - T_(1)$

Solution:

we know that coefficient of linear expansion of steel, $\alpha$ = $12* 10^(-6)/^(\circ)C$

Using the above formula :

$\alpha = (\Delta d)/(d* \Delta T)$

$12* 10^(-6)/^(\circ)C$ = \frac{1.870 - 1.872}{1.872\times \T_{2} - T_{1}}[/tex]

$T_(2) - 20/^(\circ)C$ = \frac{1.870 - 1.872}{12\times 10^{-6}}}[/tex]

$T_(2) = -67.03/^(\circ)C$

Therefore, the rivet must be cooled to $-67.03/^(\circ)C$

Final answer:

The question involves the concept of thermal expansion in Physics. By knowing the initial diameter of the rivet and hole, as well as the ambient temperature, we can use the thermal expansion formula to calculate the temperature to which the steel rivet must be cooled to fit into the hole.

Explanation:

The subject in question pertains to Physics and specifically to the concept of thermal expansion. This indicates how objects (in this case, a steel rivet) tend to change in volume or shape as a response to a change in temperature. The diameter of the rivet when cooled will decrease slightly, allowing it to fit into the smaller hole.

To find the temperature to which the rivet needs to be cooled, we require knowledge of the thermal expansion coefficient of steel, which (for generalization) can be averaged to around 0.000012 (1/°C). The formula to calculate the change in diameter (Δd) is:

Δd = α * d * ΔT

where α is the coefficient of linear expansion, d is the original diameter, and ΔT is the change in temperature. Knowing the initial diameter of the rivet and the hole it must fit into, together with the ambient temperature (22°C), we can rearrange this formula to find the cooling temperature needed for the rivet to fit into the hole.

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