Sulfur dioxide and oxygen react to form sulfur trioxide during one of the key steps in sulfuric acid synthesis. An industrial chemist studying this reaction fills a 50.0L tank with 14. mol of sulfur dioxide gas and 2.6 mol of oxygen gas, and when the mixture has come to equilibrium measures the amount of sulfur trioxide gas to be 1.6 mol. Calculate the concentration equilibrium constant for the reaction of sulfur dioxide and oxygen at the final temperature of the mixture. Round your answer to 2 significant digits.

Answers

Answer 1
Answer:

Answer:

Explanation:

From the given information:

The equation for the reaction can be represented as:

2SO_2 + O_2 \to 2SO_3

The I.C.E table can be represented as:

                     2SO₂              O₂                   2SO₃

Initial:             14                  2.6                     0

Change:        -2x                -x                      +2x

Equilibrium:   14 - 2x          2.6 - x                2x

However, Since the amount of sulfur trioxide gas to be 1.6 mol.

SO₃ = 2x,

then x = 1.6/2

x = 0.8 mol

For 2SO₂; we have 14 - 2x

= 14 - 2(0.8)

= 14 - 1.6

= 12.4 mol

For O₂; we have 2.6 - x

= 2.6 - 1.6

= 1.0 mol

Thus;

[SO₂] = moles / volume = ( 12.4/50) = 0.248 M ,

[O₂] = 1/50 = 0.02 M ,  

[SO₃] = 1.6/50 = 0.032 M

Kc = [SO₃]² / [SO₂]² [O₂]

= ( 0.032²) / ( 0.248² x 0.02)

= 0.8325

Recall that; the equilibrium constant for the reaction 2SO_2 + O_2 \to 2SO_3 = 0.8325;

If we want to find:

SO_2 + (1)/(2)O_2 \to SO_3

Then:

K_c = (0.8325)^(1/2)

\mathbf{K_c = 0.912}

Since no temperature is given to use in the question, it will be impossible to find the final temperature of the mixture.


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An imaginary line dividing the earth's surface into two hemisphere the northern and southern hemisphere, it is locatedat 0⁰, which of the following imaginary lines is being described? a.equator b.latitude c.longitude d.prime meridian​
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Write the numbers in scientific notation.291.7 = 2.917
X10%
where x =
0.0960 -
X10%
where x =​

Answers

The numbers in scientific notation are 291.7 = 2.917 × 10₂ and 0.0960 = 9.60 × 10⁻².

Scientific notation is commonly used in scientific and mathematical calculations, as well as when dealing with very large or very small numbers. It allows for a more compact and manageable representation of these numbers.

To write the numbers in scientific notation, we need to express them in the form of "a × 10^b," where "a" is a number between 1 and 10, and "b" is an integer.

For the number 291.7, write it in scientific notation as:

291.7 = 2.917 × 10²

For the number 0.0960, write it in scientific notation as:

0.0960 = 9.60 × 10⁻²

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2.917 x 10^2 0.960x 10^1

A sample of iron having a mass of 93.3g is heated to 65.58OC is placed in 75.0g ofwater raising the temperature from 16.95 OC to 22.24 OC. Find the specific heatcapacity for this iron sample. The answer you find has had some lab errors due tohuman mistakes. Find your percent error for your work using %Error = [(Expected - Actual) / (Expected Yield)] x100

Answers

The heat gained or lost by a substance undergoing a change in temperature is:
Q = mCpΔT
The heat lost by the iron is equal to that gained by water. The Cp for water is 4.186 Joules/gram

75 x 4.186 x (22.24 - 16.95) = -93.3 x Cp x (22.24 - 65.58)
Cp = 0.411 J/g

The heat capacity of iron is 0.45 J/g

%Error = [(0.45 - 0.41) / 0.41] x 100
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Consider the following reaction: 2NO(g)+O2(g)→2NO2(g) Estimate ΔG∘ for this reaction at each of the following temperatures and predict whether or not the reaction will be spontaneous. (Assume that ΔH∘ and ΔS∘ do not change too much within the give temperature range.) 718k

Answers

Final answer:

The Gibbs free energy change (ΔG∘) for the reaction can be estimated using the equation ΔG∘ = ΔH∘ - TΔS∘. At a temperature of 718K, if ΔG∘ is negative, the reaction will be spontaneous.

Explanation:

The Gibbs free energy change (ΔG∘) for a reaction can be estimated using the equation ΔG∘ = ΔH∘ - TΔS∘, where ΔH∘ is the change in enthalpy and ΔS∘ is the change in entropy. At a temperature of 718K, you can estimate ΔG∘ by substituting the given values into the equation. If the value of ΔG∘ is negative, the reaction will be spontaneous. If it is positive or zero, the reaction will not be spontaneous.

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Iridium-192 is used in medicine to treat prostate cancer. Iridium-192 has two modes of radioactive decay: 96% of the time it decays by beta emission and 4% of the time it decays by electron capture. What are the daughter nuclides of these two decay processes?

Answers

Answer:

The daughter nuclides of these two decay processes are ^(192)_(78)Pt and ^(192)_(76)Os.

Explanation:

The beta emission is represented by:

A = (Z + 1) + (n - 1) = is invariant

n: neutron

p: proton

^(A)_(Z)X \rightarrow ^(A)_(Z+1)Y

Hence, the daughter nuclide of the beta emission of Ir-192 is:

^(192)_(77)Ir \rightarrow ^(192)_(78)Pt      

Now, electron capture is represented by:

A = (Z - 1) + (n + 1) = is invariant

^(A)_(Z)X \rightarrow ^(A)_(Z-1)Y

Then, the daughter nuclide of the electron capture of Ir-192 is:

^(192)_(77)Ir \rightarrow ^(192)_(76)Os    

Therefore, the daughter nuclides of these two decay processes are ^(192)_(78)Pt and ^(192)_(76)Os.

I hope it helps you!

The reform reaction between steam and gaseous methane () produces "synthesis gas," a mixture of carbon monoxide gas and dihydrogen gas. Synthesis gas is one of the most widely used industrial chemicals, and is the major industrial source of hydrogen. Suppose a chemical engineer studying a new catalyst for the reform reaction finds that liters per second of methane are consumed when the reaction is run at and . Calculate the rate at which dihydrogen is being produced. Give your answer in kilograms per second. Round your answer to significant digits..

Answers

The reform reaction between steam and gaseous methane (CH4) produces "synthesis gas," a mixture of carbon monoxide gas and dihydrogen gas. Synthesis gas is one of the most widely used industrial chemicals, and is the major industrial source of hydrogen.

Suppose a chemical engineer studying a new catalyst for the reform reaction finds that 924 liters per second of methane are consumed when the reaction is run at 261°C and 0.96atm. Calculate the rate at which dihydrogen is being produced. Give your answer in kilograms per second. Round your answer to 2 significant digits.

Answer: The rate at which dihydrogen is being produced is 0.12 kg/sec

Explanation:

The balanced chemical equation is ;

CH_4+H_2O\rightarrow 3H_2+CO

According to ideal gas equation:

PV=nRT

P = pressure of gas = 0.96 atm

V = Volume of gas = 924 L

n = number of moles

R = gas constant =0.0821Latm/Kmol

T =temperature =261^0C=(261+273)K=534K

n=(PV)/(RT)

n=(0.96atm* 924L)/(0.0820 L atm/K mol* 534K)=20.2moles

According to stoichiometry:

1 mole of methane produces = 3 moles of hydrogen

Thus 20.2 moles of methane produces = (3)/(1)* 20.2=60.6 moles of hydrogen

Mass of hydrogen =moles* {\text {Molar mass}}=60.6mol* 2g/mol=121.2g=0.12kg

Thus the rate at which dihydrogen is being produced is 0.12 kg/sec

Write for empiricalformula
Fe2+, cr4+, cl-, O2-

Answers

Answer:

{eq}Fe^{2+} {/eq} and {eq}I^- {/eq} forms {eq}FeI_2 {/eq}

{eq}Fe^{2+} {/eq} and {eq}S^{2-} {/eq} forms {eq}FeS {/eq}

{eq}Cr^{4+} {/eq} and...

Explanation:

Empirical formula:

The empirical formula gives the simple ratio of the different types of atoms in a compound. It is different from the molecular formula, which gives the exact number of each type of atom in a compound.

Final answer:

In basic chemistry, an empirical formula represents the simplest ratio of atoms in a compound. For example, the empirical formula for a compound formed by Fe2+ (Iron II) and O2- (Oxide) would be FeO. In this question, a compound composed of all these ions (Fe2+, Cr4+, Cl-, O2-) is unusual and there's insufficient information to determine a reasonable structure.

Explanation:

The question is asking for an empirical formula, which is a formula that gives the simplest whole number ratio of atoms of each element in a compound. The formula you're asked to provide involves the ions Fe2+ (Iron II), Cr4+ (Chromium IV), Cl- (Chloride), and O2- (Oxide).

Creating an empirical formula is a matter of balancing out the charges in order to get a neutral compound. For instance, if you wanted to combine Fe2+ and O2-, the empirical formula would be FeO because one Fe2+ ion would balance out one O2- ion to make an electrically neutral compound.

It's important to remember that the charge value of the ion helps you determine the necessary ratio to achieve neutrality. In essence, we need the amount of positive charge to equal the amount of negative charge in the empirical formula.

For a compound involving all these ions, unfortunately, it's not common or reasonable to have a compound with four different ions. Iron, chromium, and oxygen are transition metals that could form complex ions, but we do not have enough information in this question to determine the structure.

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