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Related Questions
Is it possible for three or more elements to form a solid solution? Explain your answer.
A 6.13 g sample of an unknown salt (MM = 116.82g/mol) is dissolved in 150.00 g water in a coffee cupcalorimeter. Before placing the sample in the water, thetemperature of the salt and water is 23.72°C. After thesalt has completely dissolved, the temperature of thesolution is 28.54°C.If 3.15 x 10J of heat was gained by the solution, whatis the total heat for the dissolution reaction of the 6.13 gof salt?
What is the pOH of a solution with a [OH^ - ] of 10^ -11?
What is the solubility in pure water of ba(io3)2 in moles per liter at 25 ˚c? [ksp (25 ˚c) = 6.0 10–10]?
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Answer:
An example is the formation of ATP, which is an endergonic process and is coupled to the dissipation of a proton gradient.
Explanation:
Hope this helped!
oxygen (O)
carbon (C)
radon (Rn)
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The element that has been a halogen from the given elements have been Chlorine. Thus, option A is correct.
Halogen has been given as the group of metallic compounds that have been consisted of the one valence electrons in their last orbitals.
The halogens have been the most reactive elements and belong to group 18 of the periodic table. From the given set of elements, the number of valence electrons in the following has been:
- Chlorine = 1 valence electron
- Oxygen = 6 valence electrons
- Carbon = 4 valence electrons
- Radon = 8 valence electrons
Since the element having 1 valence electron has been Chlorine. Thus, the element that has been a halogen from the given elements have been Chlorine. Thus, option A is correct.
For more information about halogen, refer to the link:
Answer is chlorine (Cl)
O 3.04 x 1028
O 5.76 x 1029
O 6.02 x 1023
O 3.13
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There are 5.78 × 10^20 sulfide ions in sodium sulfide
The formula of the compound is Na2S. The molar mass of the compound is calculated as follows; 2(23) +32 = 46 + 32 = 78 g/mol
Number of moles of Na2S = 0.15 g/ 78 g/mol = 0.0019 moles
Since there is 1 mole of Na^+ and 2 moles of S^2- in Na2S, the number of S^2- ions in 0.19 moles of Na2S is 0.00096 moles of S^2-.
If 1 mole of S^2- contains 6.02 × 10^23
0.095 moles of S^2- contains 0.00096 moles × 6.02 × 10^23/ 1 mole
= 5.78 × 10^20 sulfide ions
Learn more: brainly.com/question/1309057
X 10 grams of lead is present in 250
mL of water, is it safe to drink the water?
Support your answer with mathematical
proof.
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We are given:
Maximum concentration of Lead in water = 9 ppb
Mass of Lead in the given solution = 20 grams
Volume of water in the given solution = 250 mL
What is 1 ppb?
1 ppb, short for parts-per-billion. As from its name itself, ppb is used to find how many molecules of solute are present per 1 Billion molecules of the solvent
you can also use it in grams to get the formula:
1 ppb = 1 gram of solute / 1 Billion grams of Solvent
Finding the Ideal ppb concentration:
We are given that the maximum allowed concentration is 9 ppb
which means that we need 9 grams of the solute per 1 Billion grams of Solvent: 9 grams of Solute / 10⁹ grams of Solvent
ppb Concentration of the given solution:
We have 20 grams of Solute in 250 mL of water
Since the density of water is 1 gram/mL
20 grams of Solute / 250 grams of Solvent
As we can see, this fraction is FAR more large that the maximum ppb concentration
This means that the concentration of Lead in the Given solution is higher than the maximum amount and Hence, is unfit to drink
Calculate no of gram atoms in 7.5g of gold
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therefore molar mass of gold is - 197.2 g/mol
avagadros number states that 1 mol of any substance is made of 6.022 x 10²³ units. These units could be atoms making up elements or molecules making up compounds.
1 mol of gold is made of 6.022 x 10²³ atoms of gold
since 1 mol weighs 197.2 g
therefore if 197.2 g of gold contains - 6.022 x 10²³ atoms of gold
then 7.5 g contains - 6.022 x 10²³ x 7.5/ 197.2 = 2.29 x 10²² atoms of gold
answer is 2.29 x 10²² atoms of gold