The density for potassium is 0.856 g/cm3. What would be the mass of a 35 cm3 piece of potassium?

Answers

Answer 1
Answer:

Answer:

30 grams

Explanation:

density = mass / volume => mass = density x volume

mass = 0.856 g/cm³  x  35 cm³ = 29.96 grams ≅ 30 grams 2 sig. figs.  


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To measure the solubility product of lead (II) iodide (PbI2) at 25°C, you constructed a galvanic cell that is similar to what you used in the lab. The cell contains a 0.5 M solution of a lead (II) nitrate in one compartment that connects by a salt bridge to a 1.0 M solution of potassium iodide saturated with PbI2 in the other compartment. Then you inserted two lead electrodes into each half-cell compartment and closed the circuit with wires. What is the expected voltage generated by this concentration cell? Ksp for PbI2 is 1.4 x 10-8. Show all calculations for a credit.

Answers

Answer:

0.2320V

Explanation:

Voltage can be defined as the amount of potential energy available (work to be done) per unit charge, to move charges through a conductor.

Voltage can be generated by means other than rubbing certain types of materials against each other.

Please look at attached file for solution to the problem.

Final answer:

The expected voltage generated by this concentration cell is approximately 0.113 V.

Explanation:

To calculate the voltage generated by the concentration cell, we can use the Nernst equation. The Nernst equation relates the concentration of the ions in the two compartments to the voltage of the cell. The equation is:

E = E° - (RT/nF) ln(Q)

Where:

  • E is the voltage of the cell
  • E° is the standard cell potential
  • R is the gas constant (8.314 J/mol·K)
  • T is the temperature in Kelvin (25 + 273 = 298 K)
  • n is the number of moles of electrons transferred (2 in this case)
  • F is Faraday's constant (96,485 C/mol)
  • ln(Q) is the natural logarithm of the reaction quotient

The reaction quotient (Q) can be calculated using the concentrations of the lead (II) and iodide ions in each compartment.

Since this is a concentration cell, the standard cell potential (E°) for this system is 0 V. Therefore, the equation simplifies to:

E = - (RT/nF) ln(Q)

Now we can calculate the voltage:

  1. Calculate Q:

The solubility product constant (Ksp) for PbI2 is 1.4 x 10-8. Because PbI2 is in a saturated solution, the concentration of Pb2+ ions and I- ions are both equal to the solubility of PbI2. We can substitute these values into the equation to calculate Q:

Q = [Pb²+] x [I-]

Q = (1.4 x 10-8) x (1.4 x 10-8) = 1.96 x 10-16

  1. Calculate E:

Now we can calculate the voltage using the given values:

For the Nernst equation, we need to convert the temperature to Kelvin:

T = 25°C + 273 = 298 K

Substitute the values into the equation:

E = - (8.314 J/mol·K x 298 K / 2 x 96,485 C/mol) ln(1.96 x 10-16)

E ≈ 0.113 V

Therefore, the expected voltage generated by this concentration cell is approximately 0.113 V.

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Consider the following reaction at 298K.I2 (s) + Pb (s) = 2 I- (aq) + Pb2+ (aq)
Which of the following statements are correct?
Choose all that apply.
ΔGo > 0
The reaction is product-favored.
K < 1
Eocell > 0
n = 2 mol electrons
B-

Answers

Answer:

Eªcell > 0; n = 2

Explanation:

The reaction:

I2 (s) + Pb (s) → 2 I- (aq) + Pb2+ (aq)

Is product favored.

A reaction that is product favored has ΔG < 0 (Spontaneous)

K > 1 (Because concentration of products is >>>> concentration reactants).

Eªcell > 0 Because reaction is spontaneous.

And n = 2 electrons because Pb(s) is oxidizing to Pb2+ and I₂ is reducing to I⁻ (2 electrons). Statements that are true are:

Eªcell > 0; n = 2

How many lone pairs are on the central atom of BrF3?

Answers

According to the molecular geometry, there are two lone pairs on central atom of BrF₃.

What is molecular geometry?

Molecular geometry can be defined as a three -dimensional arrangement of atoms which constitute the molecule.It includes parameters like bond length,bond angle and torsional angles.

It influences many properties of molecules like reactivity,polarity color,magnetism .The molecular geometry can be determined by various spectroscopic methods and diffraction methods , some of which are infrared,microwave and Raman spectroscopy.

They provide information about geometry by taking into considerations the vibrational and rotational absorbance of a substance.Neutron and electron diffraction techniques provide information about the distance between nuclei and electron density.

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Answer:

BrF3 has 2 lone pairs (4 unshared electrons)

Explanation:

The following reaction was monitored as a function of time: A→B+C A plot of ln[A] versus time yields a straight line with slope −4.3×10−3 /s. If the initial concentration of A is 0.260 M, what is the concentration after 225 s?

Answers

The concentration after 225 s is 0.099 M.

As we know that, the graph of ln [A] versus time yields a straight line with slope 'k'.

So, Slope = k =  4.3*10^(-3)/s

Rate law for first order kinetics:

t=(2.303)/(k) log (a)/(a-x)

where,

k = rate constant  =  4.3*10^(-3)/s

t = time passed by the sample  = 225 s

a = initial amount of the reactant  = 0.260 M

a - x = amount left after decay process = ?

On substituting the values:

t=(2.303)/(k) log (a)/(a-x)\n\nt=(2.303)/(4.3*10^(-3)) log (0.260)/(a-x)\n\na-x=0.099M

Therefore, the concentration after 225 s is 0.099 M.

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Answer : The concentration after 225 s is, 0.099 M

Explanation :

As we know that, the graph of ln [A] versus time yields a straight line with slope 'k'.

So, Slope = k = 4.3* 10^(-3)s^(-1)

Expression for rate law for first order kinetics is given by:

t=(2.303)/(k)\log(a)/(a-x)

where,

k = rate constant  = 4.3* 10^(-3)s^(-1)

t = time passed by the sample  = 225 s

a = initial amount of the reactant  = 0.260 M

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

225=(2.303)/(4.3* 10^(-3))\log(0.260)/(a-x)

a-x=0.099M

Therefore, the concentration after 225 s is, 0.099 M

Consider four small molecules, A–D, which have the following binding affinities for a specific enzyme (these numbers are the equilibrium constants Kd for the dissociation of the enzyme/molecule complex). Which binds most tightly to the enzyme? Which binds least tightly?A) 4.5 μM

B) 13 nM

C) 8.2 pM

D) 6.9 mM

Answers

Answer:

Binding affinity measures the strength of the interaction between a molecule to its ligand; it is expressed in terms of the equilibrium dissociation constant; and the higher value of this constant, the more weaker the binding between the molecule and the ligand is. On the other hand, small constans means that the interaction is tight. So "C" binds most tightly to the enzyme and "D" binds least tightly.

Write the balanced equation for the equilibrium reaction for the dissociation ofsilver chloride in water, and write the K expression for this reaction. Then create an ICE chart. Since we know the equilibrium concentration of the silver ion, we can solve for Ksp.Does it agree with the literature value

Answers

Answer:

See explanation

Explanation:

Hello there!

In this case, since the the concentrations are not given, and not even the Ksp, we can solve this problem by setting up the chemical equation, the equilibrium constant expression and the ICE table only:

AgCl(s)\rightleftharpoons Ag^+(aq)+Cl^-(aq)

Next, the equilibrium expression according to the produced aqueous species as the solid silver chloride is not involved in there:

Ksp=[Ag^+][Cl^-]

And therefore, the ICE table, in which x stands for the molar solubility of the silver chloride:

       \ \ \ \ \ \ \ \ \ \ \ \ \ \ AgCl(s)\rightleftharpoons Ag^+(aq)+Cl^-(aq)

I          -                   0             0

C        -                   +x           +x

E        -                    x             x

Which leads to the following modified equilibrium expression:

Ksp=x^2

Unfortunately, values were not given, and they cannot be arbitrarily assigned or assumed.

Regards!