CHEMISTRY COLLEGE

If you are asked to make 40 mL of a 1.0% (w/v %) agarose gel, how many grams of agarose will you add to the 40ml of buffer

Answers

Answer 1
Answer:

Answer:

0.4g

Explanation:

1.0% (w/v%) = 1 g of agarose 100 ml of Tris-Acetate-EDTA,  this is the buffer that agarose is run with

the amount of agarose for 40 ml = 1 /100 × 40 ml = 0.4 g  

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Find the density of an object that has a volume of 2.3 x 10^2 and a mass of
3.5 x 10^3. *

Answers

Answer:

(250)/(23)

Step-by-step explanation:

  1. 10^(2) = 100  
  2. 2.3 × 100 = 230
  3. 10^(3) = 1000  
  4. 3.5 × 1000 = 3500
  5. D = (m)/(v)  
  6. D = (3500)/(230)  
  7. 3500 ÷ 230 = (250)/(23)  

I hope this helps!

For the Bradford assay, the instructor will make a Bradford reagent dye by mixing 50 ml of 95% v/v ethanol with 100 mg of Coomassie Blue followed by the addition of 50 ml of 85% v/v phosphoric acid. This entire mixture is then diluted to 1 liter with water. What is the final concentration of phosphoric acid?

Answers

Answer:

4,25% v/v H3PO4

Explanation:

The concentration of phosphoric acid (H3PO4) is expressed as a volume / volume percentage, which means:

%v/v H3PO4 = (mL of pure H3PO4/mL of solution)*100%

In other words, we are only interested in the final volume of the solution to which the phosphoric acid was diluted, regardless of its composition. Which in this case is 1 L (1000 mL).

We can then apply the following equation, commonly used to calculate the initial or final concentration (or volume) of a substance when it is diluted:

Ci*Vi=Cf*Vf

Where:

Ci, is the initial concentration of the substance.

Vi, the initial volume of the substance

Cf, the final concentration reached after dilution

Vf, the final volume of the solution at which the substance was diluted

In this case, the incognite would be the final concentration of H3PO4 reached after dilution, that is, Cf. Therefore, we proceed to clear Cf from the previous equation and replace our data:

Cf = (Ci*Vi)/Vf = (85% v/v * 50 mL)/1000 mL = 4,25 % v/v

Note that being up and down in the division, the mL unit is canceled to result in% v / v.

1. How do you determine how many protons are in a neutral element?

Answers

Answer:

The number of protons in an atom is always equal to the atomic number.

Explanation:

You wish to prepare 100 mL of a 0.100 M solution by dilution of a 1.00 M solution. Which of the following pieces of glassware will you use? A. 100 mL graduated cylinder
B. 100 mL volumetric flask
C. 10 mL volumetric pipet
D. 25 mL volumetric pipet
E. 10 mL graduated pipet
F. 25 mL graduated pipet

Answers

Answer:

C

Explanation:

The volumetric pipet is designed for a specific volume of solution. In this case, a 10 mL of volumetric pipet is required to take exactly 10 mL of the solution 1.00 M and add into a volumetric flask of 100 mL. Then water or solvent(s) can be added to reach the ring of the volumetric flask. This volumetric flask is also a laboratory equipment for precis dilutions beside the volumetric pipet

Consider two aqueous solutions of NaCl. Solution 1 is 4.00 M and solution 2 is 0.10 M. In what ratio (solution 1 to solution 2) must these solutions be mixed in order to produce a 0.86 M solution of NaCl

Answers

Answer:

The ratio of solution 1 to solution 2 is 24.20 to 100.00.

Explanation:

We will mix V₁ (L) of solution 1 with V₂ (L) of solution 2 to get the final solution.

So the mole concentration in the final solution is calculated as below, note that C₁ is the concentration of solution 1, and C₂ is the concentration of solution 2

[M] = (V_(1) C_(1) +V_(2)C_(2))/(V_(1)+V_(2)) = \frac{4 V_(1) + 0.1 V_(2)}_{V_(1)+V_(2)}}=0.86

Then we can calculate for the ratio

(V_(1))/(V_(2))=(0.86-0.10)/(4.00-0.86) =(0.76)/(3.14) or (24.20)/(100.00)

What are two causes of soil loss?​

Answers

Answer: The agents of soil erosion are the same as of other types of erosion for example water, ice, wind, and gravity. Soil erosion is more likely where the ground has been disturbed by agriculture, grazing animals, logging, mining, construction, and recreational activities.Basically what I mean is some causes of solid loss is mining, construction

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