How do you find relative atomic mass

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Answer 1
Answer:

Final answer:

To find the relative atomic mass of an element, you need to consider the masses of its isotopes and their relative abundance.


Explanation:

To find the relative atomic mass of an element, you need to consider the masses of its isotopes and their relative abundance. The relative atomic mass is the weighted average of the masses of all the isotopes of the element. The formula for calculating relative atomic mass is:

Relative Atomic Mass = (Mass of Isotope1 * Abundance of Isotope1) + (Mass of Isotope2 * Abundance of Isotope2) + ...

For example, let's calculate the relative atomic mass of carbon, which has two isotopes: carbon-12 and carbon-13. The mass of carbon-12 is 12 amu and its abundance is about 98.9%. The mass of carbon-13 is 13.003 amu and its abundance is about 1.1%. We can use the formula:

(12 amu * 0.989) + (13.003 amu * 0.011) = 12.011 amu


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A eraser has a mass of 4g and a volume of 2cm3 what is it’s density

Answers

Answer:

The answer is 2.0 g/cm³

Explanation:

The density of a substance can be found by using the formula

density =  (mass)/(volume) \n

From the question

mass = 4 g

volume = 2 cm³

We have

density =  (4)/(2)  \n

We have the final answer as

2.0 g/cm³

Hope this helps you

Assuming binding is fast relative to subsequent catalytic steps, what relative effect does substitute the various active site residues have on catalysis versus substrate-binding? The various substitutions affecta. substrate-binding more than catalytic turnover.
b. catalytic turnover more than substrate binding.
c. substrate binding, but not catalytic turnover.
d. catalytic turnover, but not substrate binding.

Answers

Answer:

Explanation:

The various substitutions affect catalytic turnover more than substrate binding.

The solubility of glucose at 30°C is125 g/100 g water. Classify a solution made by adding 550 g of glucose to 400 mL of water at 30°C. Explain your classification, and describe how you could increase the amount of glucose in the solution without adding more glucose.

Answers

Answer:

Saturated solution

We should raise the temperature to increase the amount of glucose in the solution without adding more glucose.

Explanation:

Step 1: Calculate the mass of water

The density of water at 30°C is 0.996 g/mL. We use this data to calculate the mass corresponding to 400 mL.

400 mL * (0.996g)/(1mL) =398g

Step 2: Calculate the mass of glucose per 100 g of water

550 g of glucose were added to 398 g of water. Let's calculate the mass of glucose per 100 g of water.

100gH_2O * (550gGlucose)/(398gH_2O) = 138 gGlucose

Step 3: Classify the solution

The solubility represents the maximum amount of solute that can be dissolved per 100 g of water. Since the solubility of glucose is 125 g Glucose/100 g of water and we attempt to dissolve 138 g of Glucose/100 g of water, some of the Glucose will not be dissolved. The solution will have the maximum amount of solute possible so it would be saturated. We could increase the amount of glucose in the solution by raising the temperature to increase the solubility of glucose in water.

The solution made by adding 550 g of glucose to 400 mL of water at 30°C is saturated. If you want to increase the amount of glucose in the solution without adding more glucose, you can increase the temperature.

The solution made by adding 550 g of glucose to 400 mL of water at 30°C is saturated.

Since the solubility of glucose at 30°C is 125 g/100 g water, adding 550 g of glucose to 400 mL of water exceeds the maximum amount of glucose that can dissolve in the given amount of water.

To increase the amount of glucose in the solution without adding more glucose, you can increase the temperature. Higher temperatures generally increase the solubility of solutes in water. By increasing the temperature, you can dissolve more glucose in the solution.

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lowly add a slight excess of concentrated (12 M) HCl to your aqueous solution until the pH of the solution is acidic as measured by pH paper.

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