A solution in which the molarity of the hydroxide ion is larger than the molarity of the hydronium ion is termed 1. amphiprotic. 2. electrolyte. 3. basic. 4. neutral. 5. acidic.

Answers

Answer 1
Answer:

Answer: 3. basic

Explanation:

pH is the measure of acidity or alkalinity of a solution.

pH is measured by taking negative logarithm of hydrogen ions concentration.

Electrolyte is a solution which contains ions dissolved in water and hence is a good conductor of electricity.

A basic solution has more concentration of OH^- as compared to H^+.

An neutral solution has equal  concentration of H^+ as that of OH^-.

An acidic solution has more concentration of H^+ as compared to OH^-.


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Grunge is a rock style from Detroit. True False

Answers

Answer:

FALSE

Explanation:

Grunge refers to the genre of rock music and the fashion inspired by it. It originated in the mid-1980s in Seattle, Washington State.

Grunge was described as the fusion of punk rock and heavy metal.

This genre of music became popular in the early mid-1990s and included lyrics based on the theme of emotional and social alienation, betrayal, abuse, trauma etc.    

How much energy is required to heat the solid iron from 1535 ∘C to 2000 ∘C?

Answers

"206.46 J/g" energy required to heat the solid iron.

Energy due to change in temperature:

The movements or the activity of microscopic particles known as atoms, molecules, or ions in solids, solvents, as well as gases.

Thermal energy may go from one item towards the another one.

Given:

Temperature, T_1 = 1535°C

                       T_2 = 2000°C

Change, \Delta T = T_2-T_1

We know the relation,

Q = mC_p \Delta T

By putting the values,

      = 0.444(2000-1535)

      = 206.46 J/g

Thus the answer above is right.

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Answer:

Q=206.46(J)/(g)

Explanation:

Hello,

In this case, since the energy due to the change of temperature is computed via:

Q=mCp\Delta T

Thus, since the specific heat of iron is 0.444 J/(g°C), the heat per unit of mass turns out:

Q=0.444(J)/(g\°C)(2000-1535)\°C\n \nQ=206.46(J)/(g)

Best regards.

Draw the mechanism of the reaction of N,N-dimethylaniline and the diazonium salt of sulfanilic acid to form the azo dye.

Answers

Answer:

See attachment

Explanation:

The amine group of N,N-dimethylaniline is an electron-donating group and will cause the benzene ring to act as a nucleophile in an electrophilic aromatic substitution reaction with the diazonium salt of sulfanilic acid.

What is the change in electrons for nitrogen in the following reaction?S + NO3 - -> SO2 + NO


A. Gain 2 electrons
B. Gain 3 electrons
C. Lose 2 electrons
D. Lose 3 electrons

Answers

Nitrogen changes from +5 in NO_3- to +2 in NO. This means nitrogen has gained 3 electrons. Option B

To determine the change in electrons for nitrogen in the given reaction, we need to compare the oxidation state of nitrogen in the reactant (NO_3-) and the product (NO).

In the reactant, -, nitrogen is in the +5 oxidation state. This is because oxygen has an oxidation state of -2, and there are three oxygen atoms in NO_3-. Therefore, nitrogen must have an oxidation state of +5 to balance the overall charge of NO_3-.

In the product, NO, nitrogen is in the +2 oxidation state. This is because oxygen has an oxidation state of -2, and there is only one oxygen atom in NO. Therefore, nitrogen must have an oxidation state of +2 to balance the overall charge of NO.

By comparing the oxidation states of nitrogen in the reactant and the product, we can determine the change in electrons. The change in oxidation state corresponds to the change in the number of electrons gained or lost by the nitrogen atom.

In this case, nitrogen changes from +5 in NO_3- to +2 in NO. This means nitrogen has gained 3 electrons.

Therefore, the correct answer is B) Gain 3 electrons.

The nitrogen atom undergoes a reduction because it gains electrons, reducing its oxidation state from +5 to +2 in the reaction.

Option B

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Describe the range of radii of most atoms in nanometers (nm)

Answers

Final answer:

The range of radii of most atoms is typically in the nanometer scale (nm) and can be measured using the covalent radius. The size of an atom's nucleus is much smaller than the atom itself. The Bohr model provides a formula to calculate the radius of hydrogen-like atoms.

Explanation:

The range of radii of most atoms is typically in the nanometer scale (nm). The covalent radius, which is defined as half the distance between the nuclei of two identical atoms when they are joined by a covalent bond, provides a practical way to measure the size of atoms. As we move down a group in the periodic table, the covalent radius generally increases, indicating a larger size of the atom. For example, the covalent radius of the halogens increases as we move from fluorine to iodine.

The size of an atom's nucleus, on the other hand, is much smaller than the atom itself. The nucleus has a diameter of about 10-15 meters, while the typical atom has a diameter of the order of 10-10 meters. This difference in size illustrates the emptiness of atoms, with the distance from the nucleus to the electrons being typically 100,000 times the size of the nucleus.

The Bohr model provides a formula to calculate the radius of hydrogen-like atoms, which depends on the principal quantum number (n) and the atomic number (Z). The calculated radii of the orbits of the hydrogen atom have been experimentally verified to have a diameter of a hydrogen atom.

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Final answer:

The range of radii of most atoms is typically measured in nanometers (nm). Covalent radius and hydrogen-like orbits are two methods used to estimate the size of atoms. The size of an atom can vary depending on the element and measurement technique, but most atoms have radii on the order of nanometers (nm).

Explanation:

The range of radii of most atoms is typically measured in nanometers (nm). The size of an atom can be estimated using various techniques. One commonly used measure is the covalent radius, which is defined as one-half the distance between the nuclei of two identical atoms when they are joined by a covalent bond. The covalent radii of different elements can be found in tables and can vary depending on the element and its position in the periodic table.

Another way to estimate the size of atoms is by looking at the sizes of their orbits in hydrogen-like atoms. These orbits are given in terms of their radii by a mathematical expression that includes a constant called the Bohr radius, which is approximately 5.292 × 10-11 m.

Overall, the size of an atom can vary depending on the element and the specific measurement technique used, but most atoms have radii on the order of nanometers (nm).

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How many liters of the antifreeze ethylene glycol [CH2(OH)CH2(OH)] would you add to a car radiator containing 6.50 L of water if the coldest winter temperature in your area is -10.°C? (The density of ethylene glycol is 1.11 g/mL. Assume the density of water at -10.°C is 1.00 g/mL.)

Answers

Answer:

Around 2.0 L of ethylene glycol needs to be added to the car radiator

Explanation:

The depression in freezing point ΔTf of a solution is directly proportional to its molality (m), i.e.

\Delta T_(f)= T_(f)^(0)-T_(f)=i*K_(f)*m

From the given information:

T_(f) = freezing pt of solution = -10.0 C

T_(f)^(0) = freezing pt of pure solvent = 0 C

Kf = freezing pt depression constant = 1.86 C/m

i = 1 for ethylene glycol antifreeze

[0-(-10.0)] C= 1*(1.86 C/m) *( m)\n\nm = 5.38

Molality = (moles\ of\ solute)/(kg\ solvent) \n\nTherefore,\ moles of antifreeze = molality* mass\ of\ water\n

Molality = (moles\ of\ solute)/(kg\ solvent) \n\nTherefore,\ moles of ethylene glycol = molality* mass\ of\ water\n

Volume of water = 6.50 L = 6500 ml

Density of water = 1.00 g/ml

Therefore mass of water = density * volume = 1.00g/ml*6500ml = 6500g = 6.50kg

moles\ of\ ethylene glycol= 5.38moles/kg*6.50kg = 34.9 moles

Molar mass of ethylene glycol = 62 g/mol

Mass of ethylene glycol needed = molar\ mass* moles = 62g/mol*34.9moles=2163.8g

Density of ethylene = 1.11 g/ml

Therefore, volume needed = (mass)/(density) =(2163.8g)/(1.11g/ml) =1949ml

 16 = m x 1.86 
m = 8.60 = moles solute / 6.50 Kg 

moles solute = 55.9 

mass solute = 55.9 x 62.068 g/mol=3470 g 

V = 3479/ 1.11 =3126 mL= 3.13 L 

delta T = 8.60 x 0.512 =4.40 
boling point = 104.4 °C

Hope this helps.