Answers
Answer : The volume of calcium hydroxide is, 32.89 ml
Explanation :
Using neutralization law,
where,
= basicity of an acid = 1
= acidity of a base = 2
= concentration of hydrobromic acid = 0.389 M
= concentration of calcium hydroxide = 0.0887 M
= volume of hydrobromic acid = 15 ml
= volume of calcium hydroxide = ?
Now put all the given values in the above law, we get the volume of calcium hydroxide.
Therefore, the volume of calcium hydroxide is, 32.89 ml
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Answers
The dilution of each tube are as follows;
- Tube 2; 8.26 × 10-³
- Tube 3; 7.5 × 10-⁴
- Tube 4; 6.83 × 10-⁵
For each time a dilution is further diluted;
The dilution ratio is; 1 : 11; In essence, 0.5 mL of agent was added to 5.0 mL of nutrient broth.
- For the first tube; dilution factor is; 1 : 11 = 9.1× 10-²
- For the second tube; 0.5mL of the first tube was added to 5.0mL of the nutrient broth; The dilution factor is then; (1/11) × (1/11) = 1/121 = 8.26 × 10-³.
- For the third tube; 0.5mL of the second tube was added to 5.0mL of the nutrient broth; The dilution factor is then; (1/11) × (1/11) ×(1/11) = 1/121 = 7.5 × 10-⁴.
- For the fourth tube; 0.5mL of the third tube was added to 5.0mL of the nutrient broth; The dilution factor is then; (1/11) × (1/11) × (1/11) × (1/11) = 1/14641 = 6.83 × 10-⁵.
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Answer:
Tube 2: 8.26 * 10^-3; Tube 4: 6.83 * 10^-5
Explanation:
In the serial dilutions for MIC test, the volume of nutrient broth in each tube should be equal: 5.0 mL. And the volume of agent in each dilution should also be similar: 0.5 mL.
The serial dilutions was as following:
- Tube 1: 0.5/5.5
- Tube 2: 0.5 mL of tube 1 was diluted with 5.0 mL broth. Then, the dilution of tube 2 is (1:11) * (1:11) = (0.5/5.5) * (0.5/5.5) = 1:121 = 8.26 * 10^-3
- Tube 3: We perform the similar calculation. Thus, the result is 1:1331 = 7.51 * 10^-4
- Tube 4: It is 1:14641 = 6.83 * 10^-5.
Answers
You can get better at solving problems like this by practicing a lot!
B) Respiration O2 photosynthesis CO2
C) Photosynthesis H2 Respiration O2
D) Respiration CO2 photosynthesis H2
Answers
the answer is A:
Photosynthesis release O2 (oxygen)
then animals use oxygen for respiration and release Co2
Final answer:
The correct answer is A) Photosynthesis O2 Respiration CO2. Photosynthesis converts CO2 to O2, which is then used in respiration to be converted back into CO2. Both processes together create a continuous cycle.
Explanation:
The correct diagram that represents the cycling of gases between photosynthesis and respiration is A) Photosynthesis O2 Respiration CO2. Through the process of photosynthesis, plants convert carbon dioxide (CO2) and sunlight into oxygen (O2) and glucose. Organisms, including the plants themselves, then use that oxygen for respiration, during which they convert the oxygen back into carbon dioxide. The glucose is used for energy. This continuous cycling plays a critical role in life on Earth.
Learn more about Cycling of gases here:
#SPJ3
Answers
Answer:
Solubility= 1.08×10-12
Explanation:
Take the cube root of 1.27×10-36
Answer:
The solubility of CuX is 1.425x10⁻⁷M
Explanation:
Given:
initial concentration of NaCN=0.2M
Ksp=1.27x10⁻³⁶
The reaction are:
CuX → Cu²⁺ + X²⁺, Ksp=1.27x10⁻³⁶
Cu²⁺ + 4CN⁻ → (Cu(CN)₄)²⁻, Kf=1x10²⁵
The overall reaction is:
CuX + 4CN⁻ → (Cu(CN)₄)²⁻ + X²⁺
The equilibrium constant is:
K=Ksp*Kf=1.27x10⁻³⁶*1x10²⁵=1.27x10⁻¹¹
CuX + 4CN⁻ → (Cu(CN)₄)²⁻ + X²⁺
I - 0.2 0 0
C - -4 +x +x
E - 0.2-4 x x
The equation for equilibrium is:
Here, solving for x:
x=1.425x10⁻⁷M=CuX
Answers
Answer:
The value of Keq is 4e-9. See the solution below
Explanation:
We need to balanced rhe equation and use the formula of the Keq
Answers
Chemical reaction (dissociation) 2: C₂O₄H⁻(aq) ⇄ C₂O₄²⁻(aq) + H⁺(aq).
c(C₂O₄H⁻) = c(H⁺) = x.
c(C₂O₄H₂) = 0.0269 M.
pKa₁ = 1.23.
Ka₁ = 10∧(-1.23) = 0.059.
Ka₁ = c(C₂O₄H⁻) · c(H⁺) / c(C₂O₄H₂).
0.059 = x² / (0.0269 M - x).
Solve quadratic eqaution: x = c(H⁺) = 0.02 M.
pH = -log(0.02 M) = 1.7.