Answers
Answer : The volume required to fill the gas tank is, 45.42 liters
Explanation :
Conversion used for gallon to liters are:
As we are given the volume of gas tank in gallon is, 12.0 gal
Now we have to determine the volume of gas tank in liters.
As, 1 gallon = 3.785 liter
So, 12.0 gallon =
Therefore, the volume required to fill the gas tank is, 45.42 liters
Related Questions
For the experiments from 1-3 with the same temperature change, what other parameters are the same at the initial reaction conditions?a. mmol HCl total mL solution b. mmol NaOH Initial concentration of NaOH c. mL H2O Initial concentration of HCl
hich of the following statements is true about cocaine? multiple choice cocaine is a powerful central nervous system opiate. cocaine may cause users to become overweight. cocaine hydrochloride powder produces a higher rate of dependence than crack cocaine.
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2Cl-(aq)--->Cl2(g)+2e-
Cr3+(aq)+3e- ---->Cr(s)
What is the final, balanced equation for this reaction?
1.) 2cr3+(aq)+6Cl-(aq) ------> 2Cr(s)+3Cl2(g)
2.) 2Cr3(aq)+2Cl-(aq)+6e- --->Cl2(g)+2Cr(s)
3.) Cr3+(aq)+6Cl-(aq)+3e- ---->2Cr(g)+3Cl2(g)
4.) Cr3+(aq)+2Cl-(aq)------>Cr(s)+Cl2(g)
Answers
Explanation:
1) Write the oxidation half-reaction:
2) Write the reduction half-raction:
3) Multiply each half-reaction by the appropiate coefficient to equal the number of electrons of both half-reactions.
4) Add both half-reactions
And that is the answer. You can count the atoms and charges on every side and check they are equal.
Answer:
A
Explanation:
got it correct on edge
Answers
Answer:
123.41 g
Explanation:
Given that the ethyl alcohol produced is 11.0 % by volume.
It means that 1000 mL contains 110 mL of ethyl alcohol
Given that the volume is:- 725 mL
So,
Volume of ethyl alcohol = = 79.75 mL
Given that:- Density = 0.789 g/cm³ = 0.789 g/mL
So, Mass = Density*Volume = = 62.92 g
Calculation of the moles of ethyl alcohol as:-
Molar mass of ethyl alcohol = 46.07 g/mol
The formula for the calculation of moles is shown below:
Thus,
According to the reaction:-
2 moles of ethyl alcohol is produced when 1 mole of glucose reacts
Also,
1.37 moles of ethyl alcohol is produced when mole of glucose reacts
Moles of glucose = 0.685 Moles
Molar mass of glucose = 180.156 g/mol
Mass = Moles*Molar mass = = 123.41 g
A property that will NOT change if temperature changes
A property that changes if the amount of substance changes
A property that does NOT change if the amount of substance changes
Help :( pls
Answers
Answer:
A property that changes if the amount of substance changes
Explanation:
An extensive property is a property that depends on the amount of matter in a sample.
Final answer:
An extensive property changes if the amount of substance changes. For instance, mass and volume are extensive properties as they would vary depending on the amount of substance.
Explanation:
An extensive property is a property that changes if the amount of substance changes. For example, mass and volume are extensive properties. If you have two separate samples of a substance, each with a different amount, their mass and volume would be different. On the other hand, the melting point or boiling point of the substance, which are examples of intensive properties, would not change regardless of the amount of substance.
Learn more about extensive property here:
#SPJ12
Answers
Consider the titration of a 17.2 mL sample of 0.128 M HC2H3O2 with 0.155 M NaOH. Ka(HC2H3O2) = 1.8x10-5 Determine the pH at 0.46 mL of added base.
Answers
Answer:
1. pH = 2,82
2. 3,20mL of 1,135M NaOH
3. pH = 3,25
Explanation:
The buffer of acetic acid (HC₂H₃O₂) is:
HC₂H₃O₂ ⇄ H⁺ + C₂H₃O₂⁻
The reaction of HC₂H₃O₂ with NaOH produce:
HC₂H₃O₂ + NaOH → C₂H₃O₂⁻ + Na⁺ + H₂O
And ka is defined as:
ka = [H⁺] [C₂H₃O₂⁻] / [HC₂H₃O₂] = 1,8x10⁻⁵ (1)
1. When in the solution you have just 0,13M HC₂H₃O₂ the concentrations in equilibrium will be:
[H⁺] = x
[C₂H₃O₂⁻] = x
[HC₂H₃O₂] = 0,13 - x
Replacing in (1)
[x] [x] / [0,13-x] = 1,8x10⁻⁵
x² = 2,34x10⁻⁶ - 1,8x10⁻⁵x
x² - 2,34x10⁻⁶ + 1,8x10⁻⁵x = 0
Solving for x:
x = - 0,0015 (Wrong answer, there is no negative concentrations)
x = 0,0015
As [H⁺] = x = 0,0015 and pH is -log [H⁺], pH of the solution is 2,82
2. The equivalence point is reached when moles of HC₂H₃O₂ are equal to moles of NaOH. Moles of HC₂H₃O₂ are:
0,0466L × (0,078mol / L) = 3,63x10⁻³ moles of HC₂H₃O₂
In a 1,135M NaOH, these moles are reached with the addition of:
3,63x10⁻³ moles × (L / 1,135mol) = 3,20x10⁻³L = 3,20mL of 1,135M NaOH
3. The initial moles of HC₂H₃O₂ are:
0,0172L × (0,128mol / L) = 2,20x10⁻³ moles of HC₂H₃O₂
As the addition of NaOH spent HC₂H₃O₂ producing C₂H₃O₂⁻. Moles of C₂H₃O₂⁻ are equal to moles of NaOH and moles of HC₂H₃O₂ are initial moles - moles of NaOH. That means:
0,46x10⁻³L NaOH × (0,155mol / L) = 7,13x10⁻⁵ moles of NaOH ≡ moles of C₂H₃O₂⁻
Final moles of HC₂H₃O₂ are:
2,20x10⁻³ - 7,13x10⁻⁵ = 2,2187x10⁻³ moles of HC₂H₃O₂
Using Henderson-Hasselbalch formula:
pH = pka + log₁₀ [C₂H₃O₂⁻] / [HC₂H₃O₂]
Where pka is -log ka = 4,74. Replacing:
pH = 4,74 + log₁₀ [7,13x10⁻⁵] / [2,2187x10⁻³ ]
pH = 3,25
I hope it helps!
Answers
Answer:
FeCl: Ferric Chloride (also called iron chloride), comes from Fe (ferrum, or iron), and Cl (Chlorine)
HNO: Nitroxyl, from N (Nitrogen), and the acidic nature of a radical ending in -yl.
NaSO: Sodium sulfate, Na (Sodium), S (Sulfur), O (Oxygen).
SO: Sulfur monoxide (Mono-One), O (Oxygen) and S (Sulfur).