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How many mL of 0.100 M NaOH are needed to neutralize 50.00 mL of a 0.150 M solution of CH3CO2H, a monoprotic acid? How many mL of 0.100 M NaOH are needed to neutralize 50.00 mL of a 0.150 M solution of CH3CO2H, a monoprotic acid? a. 37.50 mL
b. 50.00 mL
c. 75.00 mL
d. 100.00 mL
e. 25.00 mL

Answers

Answer 1
Answer:

Answer:

We need 75 mL of 0.1 M NaOH ( Option C)

Explanation:

Step 1: Data given

Molarity of NaOH solution = 0.100 M

volume of 0.150 M CH3COOH = 50.00 mL = 0.05 L

Step 2: The balanced equation

CH3COOH + NaOH → CH3COONa + H2O

Step 3: Calculate moles of CH3COOH

Moles CH3COOH = Molarity * volume

Moles CH3COOH = 0.150 M * 0.05 L

Moles CH3COOH =  0.0075 moles

Step 4: Calculate moles of NaOH

For 1 mol of CH3COOH we need 1 mol of NaOH

For 0.0075 mol CH3COOH we need 0.0075 mole of NaOH

Step 5: Calculate volume of NaOH

volume = moles / molarity

volume = 0.0075 moles / 0.100 M

Volume = 0.075 L = 75 mL

We need 75 mL of 0.1 M NaOH

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Answers

The Ksp of FeCO₃ is 3.45x10-11 and the Ksp of CdCO₃ is 8.7x10-12.

What is Ksp?

Ksp is a mathematical expression used to predict the behavior of a saturated solution. It is an abbreviation of the term “solubility product constant”, and is derived from the thermodynamic equilibrium equation that exists between a solid and its dissolved ions in a solution. Ksp is used to predict the solubility of a given ionic compound, and is a measure of the maximum amount of solute that can be dissolved in a given solvent at a given temperature and pressure.

To initiate precipitation, the concentration of CO²⁻₃ must be greater than or equal to the solubility product of the least soluble salt, which is CdCO₃.
Therefore, the concentration of CO²⁻₃ must be greater than or equal to 8.7x10-12 M.

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Explain how paper chromatography could be used to separate a mixture of different coloured inks

Answers

The mobile phase is a suitable liquid solvent or mixture of solvents. You probably used paper chromatographyas one of the first things you ever did in chemistry to separate out mixturesof coloured dyes - for example, the dyes which make up a particular ink

I hope that this answer helps you out

If a 0.2g of oil consumed 1ml of sodium thiosulphate, calculate its iodine value and classify the oil?

Answers

Iodine value is a measure of the degree of unsaturation in fats and oils. It is essentially the number of grams of iodine consumed by 100 g of fat. If the iodine number is in the range of 0-70 then it is a fat, any value above 70 is considered an oil.

Formula:

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Information on the volume of thiosulphate required to titrate the blank solution is essential for calculation.

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Consider the reaction: 2 HI (g) ⇌ H₂ (g) + I₂ (g) At equilibrium, the partial pressure of HI is 1.9 atm and the partial pressures of H₂ and I₂ are 7.9 and 2.3 respectively. What is Kp for this equilibrium?

Answers

Answer:

To determine the value of Kp for the given equilibrium, we need to use the partial pressures of the gases involved.

In the balanced equation: 2 HI (g) ⇌ H₂ (g) + I₂ (g), the stoichiometric coefficients are 2, 1, and 1 respectively.

At equilibrium, the expression for Kp is given by:

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Using the provided partial pressures:

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Answers

Answer:

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Explanation:

Using the equation

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PLEASEEEEEEEE ASAPPPPPWhat is the density of a piece of cardboard that has a mass of 250 g and volume of 46 mL? *

Answers

HEELP ME HELP ME HELP ME HELP ME HELP ME

Answer:

5.4347826087

Explanation:

The formula for density is Mass/Volume so you would do 250/46 to get the answer of 5.4347826087 grams per milliliter
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