Secondary amines react with the nitrosonium ion to generate ________. n-nitrosoamines diazonium salts anilines imines oximes

Answers

Answer 1

Answer: Answer:
Secondary amines react with the nitrosonium ion to generate N-Nitrosoamines.

Explanation:
Nitosonium Ion is generally utilized in the formation of Diazonium Salts which are considered excellent starting Material from synthesis point of View. Diazonium salts are formed by reacting Primary Amine or Anilines with Nitrosonium Ions. In our case, the Amine given is Secondary. So, reaction of Sec. Amines with Nitrosonium Ions stops after the formation of N-Nitrosoamine as there is no Hydrogen attached to Nitrogen atom of Amine to be eliminated and form a double and eventually triple bond with the Nitrogen atom of Nitrosonium Ion.

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The osmotic pressure, π, of a solution of glucose is 132 atm . find the molarity of the solution at 298 k.

Answers

The formula for osmotic pressure is:

$\Pi = iMRT$

where $\Pi$ is osmotic pressure, $i$ is van't Hoff's factor, $M$ molarity, $R$ is Ideal gas constant, and T is Temperature.

$\Pi$ = 132 atm

The van't Hoff's factor for glucose, $i$ = 1

$R = 0.08206 Latmmol^(-1)K^(-1)$

$T = 298 K$

Substituting the values in the above equation we get,

$132 atm = 1* M* 0.08206 Latmmol^(-1)K^(-1)* 298$

$M = (132 atm)/(1* 0.08206 Latmmol^(-1)K^(-1)* 298) = 5.4797 molL^(-1) \simeq 5.48 molL^(-1)$

So, the molarity of the solution is $5.48 molL^(-1)$ .

Which are correct ???

Answers

Answer:

last one

Explanation:

endothermic reactions release energy

Chem help due in 2 hours. please help. problem 14.

Answers

14 )

a) 1 HBr + 1 NaHCO₃ = 1 CO₂ + 1 H₂O + 1 NaBr

b) 2 HNO₃ + 1 K₂SO₃ = 1 H₂O + 2 KNO₃ + 1 SO₂

c) 2 HI + 1 Na₂S = 1 H₂S + 2 NaI

d) 1 (NH₄)₂SO₄ + 1 Ca(OH)₂ = 1 CaSO₄ + 2 H₂O + 2 NH₃

What is the name of the structures that help move substances across a tract surface?

Answers

Answer:

cilia and flagella

Explanation:

In prokaryotic species , cilia are present , and in eukaryotic species , flagella is present .

Cilia and flagella both have same function , i.e. , to enable the movement of the cell , along with the movement of some substance and direct the flow of these substance along the tracts.

Cilia and flagella are composed of basal bodies.

Hence , from the given statement of the question,

The correct term is cilia and flagella .

Final answer:

Cilia are the structures that help move substances across the surface of a tract. They are primarily found in certain types of cells such as those in the respiratory tract and the oviducts.

Explanation:

The structures that assist in moving substances across a tract surface are primarily called cilia. In biology, cilia are tiny hair-like structures that line certain types of cells, especially those in the respiratory tract and the oviducts. They work much like oars on a boat, moving in coordinated waves to propel substances (like mucus or egg cells) along the surface of the tract they occupy. They are responsible in movement of substances across tract.

Learn more about Cilia here:

brainly.com/question/34223400

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Sulfur dioxide and oxygen react to form sulfur trioxide during one of the key steps in sulfuric acid synthesis. An industrial chemist studying this reaction fills a 50.0L tank with 14. mol of sulfur dioxide gas and 2.6 mol of oxygen gas, and when the mixture has come to equilibrium measures the amount of sulfur trioxide gas to be 1.6 mol. Calculate the concentration equilibrium constant for the reaction of sulfur dioxide and oxygen at the final temperature of the mixture. Round your answer to 2 significant digits.

Answers

Answer:

Explanation:

From the given information:

The equation for the reaction can be represented as:

$2SO_2 + O_2 \to 2SO_3$

The I.C.E table can be represented as:

2SO₂ O₂ 2SO₃

Initial: 14 2.6 0

Change: -2x -x +2x

Equilibrium: 14 - 2x 2.6 - x 2x

However, Since the amount of sulfur trioxide gas to be 1.6 mol.

SO₃ = 2x,

then x = 1.6/2

x = 0.8 mol

For 2SO₂; we have 14 - 2x

= 14 - 2(0.8)

= 14 - 1.6

= 12.4 mol

For O₂; we have 2.6 - x

= 2.6 - 1.6

= 1.0 mol

Thus;

[SO₂] = moles / volume = ( 12.4/50) = 0.248 M ,

[O₂] = 1/50 = 0.02 M ,

[SO₃] = 1.6/50 = 0.032 M

Kc = [SO₃]² / [SO₂]² [O₂]

= ( 0.032²) / ( 0.248² x 0.02)

= 0.8325

Recall that; the equilibrium constant for the reaction $2SO_2 + O_2 \to 2SO_3$ = 0.8325;

If we want to find:

$SO_2 + (1)/(2)O_2 \to SO_3$

Then:

$K_c = (0.8325)^(1/2)$

$\mathbf{K_c = 0.912}$

Since no temperature is given to use in the question, it will be impossible to find the final temperature of the mixture.

Which description best characterization the motion of particles in a solid

Answers

Answer:

D) Vibrating in fixed position

Explanation:

just took it on edge 2020

Are there any choices? Because from what the question is it seems like we need choices to help

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