Nitrogen dioxide is one of the many oxides of nitrogen (often collectively called "") that are of interest to atmospheric chemistry. It can react with itself to form another form of , dinitrogen tetroxide. A chemical engineer studying this reaction fills a flask with of nitrogen dioxide gas. When the mixture has come to equilibrium he determines that it contains of nitrogen dioxide gas. The engineer then adds another of nitrogen dioxide, and allows the mixture to come to equilibrium again. Calculate the pressure of dinitrogen tetroxide after equilibrium is reached the second time. Round your answer to significant digits.

The molarity is an important method which is used to calculate the concentration of a solution. The molarity of a solution that contains 0.50 g of NaCl dissolved in 100mL of solution is 0.085 M.

What is molarity?

The molarity of a solution is defined as the number of moles of the solute present per litre of the solution. It is an most important method to calculate the concentration of a binary solution. It is represented as 'M'.

The equation used to calculate the molarity is:

Molarity = Number of moles of the solute / Volume of the solution in litres

1L = 1000 mL

100 mL = 0.1 L

Number of moles (n) = Given mass / Molar mass

n = 0.50 / 58.44 = 0.008

Molarity = 0.0085 /  0.1  = 0.085 M

Thus the molarity of the solution is 0.085 M.

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Answer:

ksp = 0,176

Explanation:

The borax (Na₂borate) in water is in equilibrium, thus:

Na₂borate(s) ⇄ borate²⁻(aq) + 2Na⁺(aq)

When you add just borax, the moles of Na²⁺ are twice the moles of borate²⁻, that means 2borate²⁻=Na⁺ (1)

The ksp is defined as:

ksp = [borate²⁻] [Na⁺]²

Then, borate²⁻(B₄O₇²⁻) reacts with HCl thus:

B₄O₇²⁻ + 2HCl + 5H₂O → 4H₃BO₃ + 2Cl⁻

The moles of HCl that reacts with B₄O₇²⁻ are:

0,500M×0,01200L = 6,00x10⁻³ mol of HCl

As two moles of HCl react with 1 mol of B₄O₇²⁻, the moles of B₄O₇²⁻ are:

6,00x10⁻³ mol of HCl× = 3,00x10⁻³ mol of B₄O₇²⁻

For (1), moles of Na⁺ are 3,00x10⁻³ mol ×2 = 6,00x10⁻³ mol of Na⁺

The [borate²⁻] is 3,00x10⁻³ mol of B₄O₇²⁻/0,00850L = 0,353M

And [Na⁺] is 6,00x10⁻³ mol of Na⁺ / 0,00850L = 0,706M

Replacing in the expression of ksp:

ksp = [0,353] [0,706]²

ksp = 0,176

I hope it helps!

Answer:

The coefficient of is 3 in the balanced redox reaction.

Explanation:

Oxidation reaction is defined as the chemical reaction in which an atom loses its electrons. The oxidation number of the atom gets increased during this reaction.

Reduction reaction is defined as the chemical reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.

For the given chemical reaction:

The half cell reactions for the above reaction follows:

Oxidation half reaction:  

Reduction half reaction:  

To balance the oxidation half reaction must be multiplied by 3 and reduction half reaction must be multiplied by 2 thus, the balanced equation is:-

The coefficient of is 3 in the balanced redox reaction.

The mass of hydrogen gas obtained is 0.068 g of hydrogen gas.

The equation of the reaction is;

Ca(s) +2H2O(l) →Ca(OH)2(aq) + H2(g)

We have to obtain the number of moles of hydrogen gas produced using the information in the question.

P =  988mmHg - 17.54 mmHg = 1.28 atm

V = 641 mL or 0.641 L

T = 20 + 273 = 293 K

n = ?

R = 0.082 atmLK-1mol-1

From;

PV = nRT

n = PV/RT

n = 1.28 atm × 0.641 L/ 0.082 atmLK-1mol-1 × 293 K

n = 0.82/24.026

n = 0.034 moles

Mass of hydrogen =  0.034 moles × 2 g/mol = 0.068 g of hydrogen gas

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Answer:

There is 0.0677 grams of H2 gas obtained

Explanation:

Step 1: Data given

The total pressure (988 mmHg) is the sum of the pressure of the collected hydrogen + the vapor pressure of water (17.54 mmHg).  

ptotal = p(H2)+ p(H2O)

p(H2) = ptotal - pH2O = 988 mmHg - 17.54 mmHg = 970.46 mmHg

Step 2: Calculate moles of H2 gas

Use the ideal gas law to calculate the moles of H2 gas

PV = nRT

n = PV / RT

 ⇒ with p = pressure of H2 in atm = 970.46 mmHg * (1 atm /760 mmHg) = 1.277 atm

⇒ V = volume of H2 in L = 641 mL x (1 L / 1000 mL) = 0.641 L

⇒ n = the number of moles of H2 = TO BE DETERMINED

⇒ R = the gas constant = 0.08206 L*atm/K*mol

⇒ T = the temperature = 20.0 °C = 293.15 Kelvin

n = (1.277)(0.641) / (0.08206)(298.15) = 0.0335 moles H2

Step 3: Calculate mass of H2

Mass of H2 = moles H2 ¨molar H2

0.0335 moles H2 * 2.02 g/mol H2  = 0.0677g H2

There is 0.0677 grams of H2 gas obtained

Answer:- .

Explanation:- Atomic number for fluorine(F) is 9 and it's electron configuration is . is formed when F loses one electron from it's valence shell.

Second shell is the valence shell for fluorine and so it loses one electron from 2p to form    and the electron configuration of the ion becomes .

Final answer:

The ground state electron configuration of F+ is 1s²2s²2p⁴, which is derived from the neutral Fluorine's configuration 1s²2s²2p⁵ by removing one electron from the outermost 2p orbital.

Explanation:

The question asked for the full ground state electron configuration of F+. The neutral Fluorine atom (F) has 9 electrons. Its electron configuration is: 1s²2s²2p⁵. When Fluorine loses one electron it becomes a positively charged ion (F+), so its electron configuration will be: 1s²2s²2p⁴. This is because the electron is removed from the outermost shell, specifically the 2p orbital. This ground-state electron configuration refers to the most stable arrangement of electrons around the nucleus.

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