Enter the symbol of a sodium ion, Na+, followed by the formula of a sulfate ion, SO42−. Separate the ions with a comma only—spaces are not allowed. Express your answers as ions separated by a comma.

Answers

Answer 1

Answer:

Sodium and sulfate are known to form the anion and cation by the gain and loss of electrons. Sodium forms a cation, Na⁺ and sulfate form anions, SO₄²⁻.

What are anions and cations?

Anions and cations are ions formed as charged entities formed by losing and gaining electrons from the valence shell. They completely transfer their electrons to form the ionic bond.

The cation is formed by the loss of electrons from a neutral atom when there are more electrons in the valence shell. Sodium form cations as,

Na (neutral atom) - e⁺ → Na⁺ (cation)

The anions are formed by gaining electrons from a neutral atom when there is less number of electrons in the valence shell. Sulfate form anions as,

SO₄ (neutral atom) + e⁻ → SO₄²⁻ (anion)

Therefore, ions are Na⁺, SO₄²⁻.

Learn more about cations and anions, here:

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Answer 2

Answer:

The respective symbols of sodium and sulphate ions are $\boxed{{\text{N}}{{\text{a}}^ + },{\text{ SO}}_4^(2 - )}$ .

Further explanation:

The species that are produced after loss or gain of electrons are known as ions. Since ions are charged entities, these can be either positively charged or negatively charged. The positively charged ions are formed by the loss of electrons from the neutral atom and are known as cations. The negatively charged ions are called anions and are formed by the gain of electrons to the neutral atom.

The formation of anion occurs as follows:

${\text{A}}\left( {{\text{Neutral atom}}} \right) + {e^ - } \to {{\text{A}}^ - }\left( {{\text{Anion}}} \right)$

The formation of cation occurs as follows:

${\text{C}}\left( {{\text{Neutral atom}}} \right) - {e^ - } \to {{\text{C}}^ + }\left( {{\text{Cation}}} \right)$

The atomic number of Na is 11 so it has a configuration of $1{s^2}2{s^2}2{p^6}3{s^1}$ . It easily loses its 3s electron to form ${\text{N}}{{\text{a}}^ + }$ whose configuration becomes $1{s^2}2{s^2}2{p^6}$ . These ions are beneficial for heart activity, regulation of blood and body fluids and in transmission of nerve impulses. The formation of ${\text{N}}{{\text{a}}^ + }$ occurs as follows:

${\text{Na}}\left( {1{s^2}2{s^2}2{p^6}3{s^1}} \right) - {e^ - } \to {\text{N}}{{\text{a}}^ + }\left( {1{s^2}2{s^2}2{p^6}} \right)$

${\text{SO}}_4^(2 - )$ is a polyatomic ion that involves a central sulphur atom surrounded by four oxygen atoms and has a charge of -2 on it. These ions are used as cleansing agents in soaps and shampoos.

Learn more:

Balanced chemical equation: brainly.com/question/1405182
Identify the precipitate in the reaction: brainly.com/question/8896163

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Ionic compounds

Keywords: ions, cations, anions, loss, gain, electrons, Na, Na+, A, C, A-, C+, atomic number, configuration, formation.

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Find the product.
(n + 8)(n - 2)
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Answers

Answer:The product of the given expression is : $n^2+6n-16$

Explanation:

Given expression:(n + 8)(n - 2)

Using identity: $(a+b)(a+c)=a^2+(b+c)a+bc$

a = n, b=8, c= (-2)

$n^2+(8+(-2))n+(8)(-2)$

$n^2+6n-16$

The product of the given expression is : $n^2+6n-16$

Answer : The product of the given expression is:

$n^2+6n-16$

Explanation :

The given expression is:

$(n+8)(n-2)$

First we have to open the bracket by multiplying the terms.

$n^2-2n+8n-16$

Now we are adding like terms.

$n^2+6n-16$

Hence, the product of the given expression is, $n^2+6n-16$

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Answers

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Answer:

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Explanation:

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Answers

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