What mass of magnesium bromide is formed when 1.00 g of magnesium reacts with 5.00 g of bromine?

Answers

Answer 1
Answer:

Answer:

when 1.00 g of magnesium reacts with 5.00 g of bromine, approximately 7.57 g of magnesium bromide is formed.

Explanation:

To find the mass of magnesium bromide formed when 1.00 g of magnesium reacts with 5.00 g of bromine, you need to first write a balanced chemical equation for the reaction between magnesium and bromine. The balanced equation for the formation of magnesium bromide (MgBr2) is as follows:

Mg + Br2 → MgBr2

Now, you can calculate the molar mass of each substance involved in the reaction:

Molar mass of Mg (magnesium) = 24.31 g/mol

Molar mass of Br2 (bromine) = 2 * 79.90 g/mol = 159.80 g/mol

Molar mass of MgBr2 (magnesium bromide) = 24.31 g/mol + 2 * 79.90 g/mol = 184.11 g/mol

Next, calculate the number of moles for each reactant:

Moles of Mg = Mass (1.00 g) / Molar mass (24.31 g/mol) = 0.0411 moles

Moles of Br2 = Mass (5.00 g) / Molar mass (159.80 g/mol) = 0.0313 moles (approximately, rounded to four decimal places)

Now, determine the limiting reactant. To do this, compare the mole ratio between Mg and Br2 in the balanced equation. The balanced equation shows that 1 mole of Mg reacts with 1 mole of Br2. Therefore, the limiting reactant is the one that is present in the smaller amount relative to the balanced equation's stoichiometry.

In this case, magnesium (0.0411 moles) is present in a smaller amount than bromine (0.0313 moles). So, magnesium is the limiting reactant.

Now that you know magnesium is the limiting reactant, you can calculate the mass of magnesium bromide formed using the stoichiometry of the balanced equation. According to the balanced equation, 1 mole of Mg produces 1 mole of MgBr2.

Moles of MgBr2 formed = Moles of Mg (limiting reactant) = 0.0411 moles

Now, calculate the mass of magnesium bromide formed:

Mass of MgBr2 = Moles of MgBr2 × Molar mass of MgBr2

Mass of MgBr2 = 0.0411 moles × 184.11 g/mol = 7.57 g

So, when 1.00 g of magnesium reacts with 5.00 g of bromine, approximately 7.57 g of magnesium bromide is formed.

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In the "Méthode Champenoise," grape juice is fermented in a wine bottle to produce sparkling wine. The reaction is the following. C6H12O6(aq) → 2 C2H5OH(aq) + 2 CO2(g) Fermentation of 754 mL of grape juice (density = 1.0 g/cm3) is allowed to take place in a bottle with a total volume of 840. mL until 13% by volume is ethanol (C2H5OH). Assuming that the CO2 is insoluble in H2O (actually a wrong assumption), what would be the pressure of CO2 inside the wine bottle at 21°C? (The density of ethanol is 0.79 g/cm3.) WebAssign will check your answer for the correct number of significant figures. atm

Answers

Answer:

The pressure inside the wine bottle at 21 °C is 4.8 · 10² atm

Explanation:

Hi there!

We know that 1 mol of CO₂ is produced per mol of produced ethanol.

If the final concentration of ethanol is 13%, let´s calculate how many moles of ethanol are present at that concentration.

A concentration of 13% means that in 100 ml of solution, 13 ml is dissolved ethanol. We have 754 ml of solution, then, the volume of ethanol will be:

754 ml solution · (13 ml ethanol/100 ml solution) = 98 ml ethanol

With the density, we can calculate the mass of ethanol present:

density = mass/ volume

0.79 g/ml = mass / 98 ml

mass = 0.79 g/ml · 98 ml

mass = 77 g

The molar mass of ethanol is 46.07 g/mol, then 77 g of ethanol is equal to:

77 g · (1 mol/46.07 g) = 1.7 mol

Then, the number of moles of CO₂ produced will be 1.7 mol.

Using the equation of the ideal gas law, we can calculate the pressure of CO₂:

P = nRT/V

Where:

P = pressure

n = number of moles

R = ideal gas constant

T = temperature

V = volume

The volume will be the headspace of the bottle (840 ml - 754 ml) 86 ml = 0.086 l.

The temperature in kelvin will be: 21 + 273 = 294 K

The gas constant is 0.082 l atm / K mol

Then:

P = (1.7 mol · 0.082 l atm/K mol · 294 K)/ 0.086 l

P = 4.8 · 10² atm

The pressure inside the wine bottle at 21 °C is 4.8 · 10² atm

When hydrogen (H2) and chlorine (Cl2) gases are mixed, hydrogen chloride (HCl) is produced. Hydrogen chloride is classified as what type of matter?

Answers

Answer:

Gaseous matter

Explanation:

Hydrogen chloride gas is formed from the combination of volumes of hydrogen gas and chlorine gas in equal proportion. It is one of the hydrogen halides I.e a compound formed from the combination of hydrogen and halogens.

Hydrogen chloride gas is a colorless gas.

Both hydrogen gas and chlorine gas can be obtained through the electrolysis of brine in the chlor alkali process.

Cl2(g) + H2(g) → 2 HCl(g)

The combination is exothermic and thus heat is released to the surroundings. A construction called HCl burner is used to carry out the reaction because of the heat given off. The produced gas is then absorbed in water

#1. The arrangement of atoms at the peak of the activation energy barrier is known as the _____. A. activation rate B. activated complex C. transition state D. both B and C #2. Two opposing reactions (A + B C + D) occurring simultaneously at the same rate is an example of:A. reversibility./B. chemical equilibrium./C. neither a nor b/D. both a and b
#3. A substance that interferes with the action of a catalyst is known as a(n) _____.

A. negative inhibitor
/B. either an inhibitor or negative inhibitor /C. inhibitor /D. activated complex
#4. The reducing agent in the reaction described in Fe + 2HCl → FeCl2 + H2 is


A. Fe./B. HCl./C. FeCl2.

Answers

1) Answer is: D. both B and C.

Activated complex  is collection of intermediate structures in a chemical reaction that forms while bonds are breaking and new bonds are forming.

The transition state is the configuration at the peak of the diagram while the activated complex can refer to any point near the maximum.

Activation energy is the minimum energy colliding particles must have in order to react.

2) Answer is: B. chemical equilibrium.

Balanced chemical reaction: A + B ⇄ C + D.

1) In a chemical reaction, chemical equilibrium is the state in which both reactants ( and BA) and products (C and D) are present in concentrations which have no further tendency to change with time.  

2) At equilibrium, both the forward and reverse reactions are still occurring.

3) Reaction rates of the forward and backward reactions are equal and there are no changes in the concentrations of the reactants and products.

3) Answer is: C. inhibitor.

Inhibitor is a substance that decreases the rate of a chemical reaction.

Inhibitor can reduce the effectiveness of a catalyst in a catalysed reaction.

Catalysis is the increase in the rate of a chemical reaction due to the participation of an additional substance called a catalyst.  

Reactions occur faster with a catalyst because they require less activation energy.  

4) Answer is: A. Fe.

Balanced reaction: Fe + 2HCl → FeCl₂ + H₂.

Oxidation reaction: Fe⁰ → Fe⁺² + 2e⁻.

Reduction reaction: 2H⁺ + 2e⁻ → H₂⁰.

Reducing agent is an element or compound that loses an electron to another chemical species in a redox chemical reaction and they have been oxidized.

Iron (Fe) change oxidation number from 0 to +2 (lose electrons), iron is oxidized (reducing agent).

Answer :

1) The correct option is, (D) both B and C.

2) The correct option is, (D) both A and B

3) The correct option is, (C) inhibitor.

4) The correct option is, (A) Fe

Explanation :

For part 1 :

Activated complex or transition state : It is the state where the bonds are loosened and new lose bonds are formed between them. It is unstable state and immediately dissociates to form the stable products. The arrangement of atoms takes place at the peak of the activation energy barrier.

For part 2 :

The balanced chemical reaction is,

A+B\rightleftharpoons C+D

Chemical equilibrium : It is defined as a state where the rate of forward reaction is equal to the rate of backward reaction. That means there is no net change in the concentration of the reactants and the products.

Reversibility : It is defined as, in a reversible reaction when reactant A and B react to form products C and D and in the reverse reaction, C and D react to form A and B. That means process is reversible.

For part 3 :

Inhibitor : It is the substance that decreases the rate of the chemical reaction. It can reduce the effectiveness of the catalyst in a catalyzed reaction.

Or we can say that it is a substance that interferes with the action of a catalyst.

For part 4 :

The balanced redox reaction is :

Fe+2HCl\rightarrow FeCl_2+H_2

The half oxidation-reduction reactions are:

Oxidation reaction :Fe\rightarrow Fe^(2+)+2e^-

Reduction reaction :2H^++2e^-\rightarrow H_2

From this we conclude that the 'Fe' is the reducing agent that loses an electron to another chemical species in a redox chemical reaction and itself oxidized.

Hence, the reducing agent is, Fe

Is Ba(NO3)2 covalent or ionic

Answers

It is ionic..........

Answer:

Barium Nitrate ( Ba(NO3)2 ) is an Ionic bond.

Explanation:

Ionic bonding is a type of chemical bond that involves the electrostatic attraction between oppositely charged ions, and is the primary interaction occurring in ionic compounds.

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The metal wire in an incandescent light bulb glows when the light is switched on and stops glowing when it is switched off. This simple process is which kind of a change?

Answers

physical change because the matter in the object is not chemically changing 

How does the number of protons compare to the number ofelectrons in an anion?
a There are more electrons than protons.
b There are more protons than electrons.
c
There is no consistent relationship between the
numbers of protons and electrons.
d There are equal numbers of protons and electrons.

Answers

It is A).
Electrons are negatively charged and an anion is a negatively charged ion so that means there is more electrons(negative charge) than protons(positive charge) in an anion

Answer:B is the right answer

Explanation: