Which property is true for metals

Answers

Answer 1
Answer:

The true property of metals is metals have low ionization energies.

(Option 3).

What are the characteristics of metals?

Metals are characterized by their ability to conduct electricity and heat, malleability, and ductility.

These properties are primarily due to the behavior of their electrons. In a metal, the valence electrons are not tightly held by the individual atoms but rather form a "sea" of delocalized electrons that can move freely throughout the metallic lattice.

One of the key factors that contribute to the delocalization of electrons in metals is their low ionization energies.

Ionization energy is the amount of energy required to remove an electron from an atom, specifically from the outermost shell.

Learn more about Ionization energy here: brainly.com/question/30831422

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The complete question is below:

Which property is true for metals?

1. localized electrons

2. high electronegativity

3. low ionization energies

4. tightly held valence electrons

Answer 2
Answer: metals are solid, shiny, and good conductors of electricity and heat
hope this helps :)

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The first table was arranged by atomic mass, but later Mosely improved it by arranging by _______________.

Answers

Order of increasing atomic mass!

hope this helps :)

The first table, created by Mendeleev, was arranged by increasing atomic mass. However, it was later changed by Mosley, who arranged it the way it is today. He organized it by atomic number.

Quantum theory states that _____. A. electrons orbit the nucleus of an atom B. electrons cannot be created or destroyed C. electrons have both wave-like and particle-like properties D. the exact position of an electron within an atom can be calculated

Answers

Answer:

Its C. electrons have both wave-like and particle-like properties

Explanation:

Match the careers in chemistry.1. sales technician
2. theoretical research legal services
3. quality of life corporate management
4. finds practical applications information chemist
5. manufacturing environmental engineer
6. market research R&D
7. short and long term objectives marketing
8. patent rights production
9. services equipment product development

Answers

1. sales / marketing 

2. theoretical research / information chemist 

3. quality of life /environmental engineer 

4. finds practical applications / R&D 

5. manufacturing /production 

6. market research /product development 

7. short- and long-term objectives /corporate management 

8. patent rights /legal services 

9. services equipment /technician 


The careers in chemistry should be closely related to working with chemical substances and the methods involved in experiments. Thus, the answers are finds practical applications information chemist and market research R&D.

In a fission reaction of U-235, there was a release of 9.20 × 1011 kJ of energy. What amount of mass in kilograms would have been lost?Recall that c = 3 × 108 m/s.

Answers

 e = mc^2 
 
m = e / c^2 

Plug in your numbers in the appropriate units.
m=1.02 × 10^-5

Answer : The amount of mass in kilograms lost would be, 1.022* 10^(-2)Kg

Solution : Given,

Energy of released in the reaction = 9.20* 10^(11)KJ

Speed of light = c = 3* 10^8m/s

Formula used :

E=m* c^2

where,

E = energy released

m = mass

c = speed of light

Now put all the given values in the above formula, we get the amount of mass would have been lost.

9.20* 10^(11)KJ=m* (3* 10^8m/s)^2

m=1.022* 10^(-5)KJ/m^2s^(-2)=1.022* 10^(-5)* 10^3Kg=1.022* 10^(-2)Kg

conversion : (1KJ/Kg=10^3m^2/s^2)

Therefore, the amount of mass in kilograms lost would be, 1.022* 10^(-2)Kg

At normal temperature and pressure, air has a density of 0.001184 g/mL. What is the mass of air in a room that is 3.07 m by 3.00 m by 3.77 m? Answer in units of kg.

Answers

1 ml = 1 cm3
The volume of the room is 34.7217 m3 or 34.721.700 cm3, so 34.721.700 * 0.001184 g/cm3= 41,1104928 kg.

The molar mass of I2 is 253.80 g/mol, and the molar mass of NI3 is 394.71 g/mol. How many moles of I2 will form 3.58 g of NI3?

Answers

The balanced chemical reaction is:

N2 +3 I2 = 2NI3

We are given the amount of product formed. This will be the starting point of our calculations.

3.58 g NI3 ( 1 mol NI3 / 394.71 g NI3 ) ( 3 mol I2 / 2 mol NI3 ) = 0.014 mol I2.

Thus, 0.014 mol of I2 is needed to form the given amount of NI3.

Answer:

Answer is 0.0136.

Explanation: