i feel twitchy and not able to focus without my good friend (dylan) around, help? i dont like him like that, plus im already with someone, uhhh i cant explain this; helpp
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What moves in or out of a substance during a change of state?
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Answer: Option (c) is the correct answer.
Explanation:
According to the law of conservation of energy or matter, it is stated that energy can neither be created nor it can be destroyed. It can only be transformed from one form to another.
Same applies to the matter that matter can be transformed from one form to another.
Thus, we can conclude that during a chemical reaction both matter and energy is conserved.
Both energy and matter are conserved during a chemical reaction.
Further Explanation:
Chemical reaction
It is the process to convert one or more substances into different substances. Reactants are the substances that experience changes during chemical reactions whereas products are formed once the reaction is complete. The properties of products are usually different from those of reactants.
Law of conservation of mass:
According to this law, the mass of an isolated system can neither be created nor be destroyed in a chemical reaction. In other words, the mass of reactants will always be equal to the mass of products. The quantity of matter in any material is known as mass. The conservation of matter also holds good for chemical reactions.
Law of conservation of energy:
It states that the energy can neither be created nor be destroyed but can only be converted from one form to another.
Therefore both matter and energy are conserved during a chemical reaction.
Learn more:
- What does conserving mass mean in a chemical reaction? brainly.com/question/2093705
- Write the chemical formula of the compound: brainly.com/question/10585691
Answer details:
Grade: High School
Subject: Chemistry
Chapter: Basic concepts of chemistry
Keywords: chemical reaction, matter, mass, energy, conserved, created, destroyed, reactants, products, properties, different, isolated system.
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P2 =
where, P and T stands for pressure and temperature respectively, terms 1 and 2 indicates initial and final pressure/temperature respectively.
Given that, P1 = 1.5 atm, T1 = 320 K, T2 = 450 K,
∴P2 =
Final answer:
Using Gay-Lussac's Law, we calculate that when the temperature of a gas increases from 320 K to 450 K, the pressure of the gas will increase from 1.5 atm to 2.1 atm, assuming the volume and the amount of gas remain constant.
Explanation:
To answer the question, we need to use the concept in physics called Gay-Lussac's Law. This law states that the pressure of a given amount of gas held at a constant volume is directly proportional to the Kelvin temperature. It's also important to remember that when we're dealing with gases, temperatures have to be in Kelvin for our calculations to work.
Given that, we know that the initial pressure (P1) is 1.5 atm, the initial temperature (T1) is 320K, and the final temperature (T2) is 450K. We want to find the final pressure (P2). According to Gay-Lussac's law, this can be calculated using the following equation: P1/T1 = P2/T2.
Thus, P2 = P1 * T2 / T1 = 1.5 atm * 450K / 320K = 2.1 atm.
So, the gas pressure will be 2.1 atm when the temperature increases from 320 K to 450 K, assuming that the volume and the amount of gas remain constant.
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Answer:
38.8 g
Explanation:
Density is just mass divided by volume, so if you know 2 of those 3 things you can solve for the other one.
Let's write it as: D = m/v
We know D, and we know v, so solve for m:
m = Dv
Now just plug in the the known values:
m = (0.98 g/ml)( 39.63 ml) = 38.8 g
(Notice how ml cancelled out, leaving grams, which is what we wanted for mass.)
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So:
160g ---------- 6·10²³molecules
79g ---------- x
x = 2.9625·10²³ molecules
1molecule = 5 atoms
2.9625·10²³ molecules = 2.9625·10²³·5 = 14.8125·10²³ atoms
(1) KOH (3) Na3PO4
(2) NH4Cl (4) PbSO4
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Ans: 4) PbSO4
Different compounds are soluble in water to a different extent, some of them are completely insoluble in water. Solubility rules help in identifying the water soluble and insoluble compounds.
Based on the rules:
1) Salts of group IA (Li, Na, K, Rb and Cs) are soluble in water
2) Salts containing NH4+ ions are water soluble
3) All phosphates (PO4³⁻) are insoluble except those containing group IA elements and (NH4)₃PO4
4) All sulfates, SO4²⁻ salts are generally soluble with the exception of Ca2+, Sr2+, Ba2+, Hg₂²⁺, Hg2+, Pb2+ and Ag+
Therefore, among the given examples:
1) KOH contains group 1A (K) therefore soluble
2) Na3PO4 contains group IA element (Na), therefore soluble
3) NH4Cl contains NH4+ ion, therefore soluble
4) Sulfate of lead (Pb) is insoluble
The compound that is insoluble in water is:
- (4) PbSO4 (Lead(II) sulfate)
What is Lead(II) sulfate
Lead(II) sulfate (PbSO4) is generally considered insoluble in water. It forms a precipitate when mixed with water, indicating low solubility. In contrast, the other compounds listed are soluble in water:
(1) KOH (Potassium hydroxide) is soluble in water and dissociates into potassium ions (K+) and hydroxide ions (OH-).
(2) NH4Cl (Ammonium chloride) is soluble in water and dissociates into ammonium ions (NH4+) and chloride ions (Cl-).
(3) Na3PO4 (Sodium phosphate) is soluble in water and dissociates into sodium ions (Na+) and phosphate ions (PO43-).
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