What group does paracetamol come under

Answers

Answer 1
Answer: Paracetamol is grouped within the 'painkillers' category. 

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What is the relation between Kilowatt-hour and joule ?

Answers

Answer: The relationship between " kWh " and " Joules " are :

1 kWh=1000 Watt×[60×60] seconds

1 kWh=10

3

 W×3600 s

1 kWh=3.6×10

6

 J

a person pushing a stroller starts from rest, uniformly accelerating at a rate of 0.500m/s^2. what is the velocity of the stroller after it has traveled 4.75m?

Answers

You're going to use the constant acceleration motion equation for velocity and displacement:
(V)final²=(V)initial²+2a(Δx)

Given:
a=0.500m/s²
Δx=4.75m
(V)intial=0m
(V)final= UNKNOWN

(V)final= 2.179m/s

Hello!

A person pushing a stroller start from rest uniformly accelerating at a rate of 0.500 m/s². What is the velocity of the stroller after it traveled 4.75 m ?

We have the following data:

a (acceleration) = 0.500 m/s²

Vf (final velocity) = ? (in m/s)

Vi (initial velocity) = 0 m/s

Δx (displacement) = 4.75 m

Solving:

Let's apply the Torricelli Equation, to find the velocity of the stroller, let's see:

V_f^2 = V_i^2 + 2*a*\Delta{x}

V_f^2 = 0^2 + 2*0.500*4.75

V_f^2 = 0 + 4.75

V_f^2 = 4.75

V_f = √(4.75)

\boxed{\boxed{V_f \approx 2.18\:m/s}}\:\:\:\:\:\:\bf\blue{\checkmark}\bf\green{\checkmark}\bf\red{\checkmark}

Answer:

The velocity of the stroller is approximately 2.18 m/s

________________________________

\bf\red{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}

A plane flies 300km in 3 hrs. What is
the rate of the plane?

Answers

the plane is on a average of 100km a hour

Answer:

on average, the plane is traveling at 100km per hour, so i think the rate is 100:1

Explanation:

What are the problems with monoculture farming?

Answers

One pest or disease can wipe out the whole crop population. Leading to lower yields.

A proton has a charge of 1.6 × 10-19 C and a mass of 1.67 × 10-27 kg. A proton moves with velocity 1.8 × 105 m/s in the z-direction. A magnetic field with B = 2.1 × 10-1 T points in the y-direction. Find the magnitude and direction of the magnetic force on the proton.What is the angle between the proton’s velocity and the magnetic field?
45°
90°
180°
50°

I'll report you if you don't actually help. I'd like an actual explanation, please.

Answers

Hey

So first we need to know what the direction of the force is, using your right hand rule point your right hand in the direction of the velocity. You're saying its the z direction, not telling me whether it's into the page or out? Since its a positive z im assuming its coming out. The magnetic field is pushing it upwards, so the force is going in the negative x direction.

The force of a magnetic field is

F = Qv X B

What's weird is that you don't need mass in this equation. Actually you don't even need the formula, its telling you that they're all going in perpendicar directions. the answer is 90 degrees.

Now if you want to know the F just multiply the charge, velocity and magnetic field .

F = GVB

F = 6.048 E -15

Answer : 90 degrees, sin(90) = 1

Final answer:

To find the magnitude and direction of the magnetic force on a proton moving in a magnetic field, you can use the equation F = qvBsinθ, where F is the force, q is the charge, v is the velocity, B is the magnetic field, and θ is the angle between the velocity and the magnetic field. The magnitude of the magnetic force can be calculated using the equation, and its direction can be determined using the right-hand rule. In this case, the angle between the proton's velocity and the magnetic field is 90°.

Explanation:

To determine the magnitude of the magnetic force on the proton, we need to use the equation F = qvBsinθ, where F is the force, q is the charge, v is the velocity, B is the magnetic field, and θ is the angle between the velocity and the magnetic field.

Plugging in the values, we have F = (1.6 × 10-19 C)(1.8 × 105 m/s)(2.1 × 10-1 T)sinθ.

To find the angle θ, we can use the fact that the force is perpendicular to both the velocity and the magnetic field, which means that sinθ = 1.

Therefore, the magnitude of the magnetic force on the proton is F = (1.6 × 10-19 C)(1.8 × 105 m/s)(2.1 × 10-1 T) = 6.048 × 10-14 N. The direction of the magnetic force is given by the right-hand rule, which shows that the force is perpendicular to both the velocity and the magnetic field, pointing in the positive x-direction.

The angle between the proton's velocity and the magnetic field is 90°.

Learn more about magnetic force on a charged particle here:

brainly.com/question/19525738

#SPJ3

(PLEASE HELP) Identify the following as electromagnetic (E) or mechanical (M) waves.sound waves

water waves

radio waves

ultraviolet waves

waves in a wheat field

Answers

Answer;

Mechanical waves;

  • sound waves
  • waves in a wheat field
  • water waves

Electromagnetic waves

  • Radio waves
  • Ultraviolet

Explanation;

  • A wave is a transmission of a disturbance from one place, the source to another.
  • Waves can be classified as mechanical waves or electromagnetic waves depending on the requirement of a material medium.
  • Mechanical waves are those waves that require a material medium for transmission, they include, sound waves, water waves, etc. The transmission of these waves is by vibration of particles in the medium.
  • Electromagnetic waves are those waves that do not require a material medium for transmission.They include, radio waves, microwaves, and all the waves in the electromagnetic spectrum.

sound waves (m)

water waves (m)

radio waves (e)

ultraviolet (e)

waves in a wheat field (m)