PHYSICS HIGH SCHOOL

Just after a motorcycle rides off the end of a ramp and launches into the air, its engine is turning counterclockwise at 8325 rev/min. The motorcycle rider forgets to throttle back, so the engine's angular speed increases to 12125 rev/min. As a result, the rest of the motorcycle (including the rider) begins to rotate clockwise about the engine at 4.2 rev/min. Calculate the ratio IE/IM of the moment of inertia of the engine to the moment of inertia of the rest of the motorcycle (and the rider). Ignore torques due to gravity and air resistance.

Answers

Answer 1

Answer:

Answer:

$(Ie)/(lm) = 1.10*10^(-3)$

Explanation:

GIVEN DATA:

Engine operating speed nf = 8325 rev/min

engine angular speed ni= 12125 rev/min

motorcycle angular speed N_m= - 4.2 rev/min

ratio of moment of inertia of engine to motorcycle is given as

$(Ie)/(lm) = (-N)/((nf-ni))$

$(Ie)/(lm) = (-(-4.2))/((12125 - (8325)))$

$(Ie)/(lm) = 1.10*10^(-3)$

Answer 2

Answer:

Answer: $1.105* 10^(-3)$

Explanation:

Given

Initial angular speed of engine( $\omega _E$ )=8325 rpm

Final angular speed of engine( $\omega _E_f$ )=12125 rpm

Initial angular speed of Motorcycle( $\omega _M$ )=0 rpm

Final angular speed of engine( $\omega _M_f$ )=4.2 rpm

as there is no external torque therefore angular momentum remains conserved

$I_E\omega _E+I_M\omega _M=I_E\omega _E_f+I_M\omega _M_f$

$I_E\omega _E+=I_E\omega _E_f+I_M\omega _M_f$

$I_E\left ( \omega _E-\omega _E_f\right )=I_M\omega _M_f$

$(I_E)/(I_M)=(\omega _M_f)/(\omega _E-\omega _E_f)$

$(I_E)/(I_M)=(-4.2)/(8325-12125)=0.0011052\approx 1.105* 10^(-3)$

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38. a 3.0 μc point charge is placed in an external uniform electric field that has a magnitude of 1.6 × 104 n/c. at what distance from the charge is the net electric field zero?

Answers

Answer:

To find the distance from the 3.0 μC point charge where the net electric field is zero in the presence of the external uniform electric field, you can use the principle that the electric fields due to the point charge and the external field will cancel each other at that point.

The electric field due to a point charge is given by Coulomb's law:

E_point_charge = k * (|q| / r^2),

where:

E_point_charge is the electric field due to the point charge.

k is Coulomb's constant (approximately 8.99 x 10^9 Nm^2/C^2).

|q| is the magnitude of the point charge (3.0 μC = 3.0 x 10^-6 C).

r is the distance from the point charge.

The external uniform electric field has a magnitude of 1.6 x 10^4 N/C. Let's denote this as E_external.

To find the point where the net electric field is zero, you want the magnitudes of the electric fields due to the point charge and the external field to be equal. So:

E_point_charge = E_external.

Substitute the expressions for both electric fields:

k * (|q| / r^2) = E_external.

Now, plug in the known values:

(8.99 x 10^9 Nm^2/C^2) * (3.0 x 10^-6 C / r^2) = 1.6 x 10^4 N/C.

Now, solve for r:

3.0 x 10^-6 C / r^2 = (1.6 x 10^4 N/C) / (8.99 x 10^9 Nm^2/C^2).

r^2 = (3.0 x 10^-6 C / (1.6 x 10^4 N/C)) * (8.99 x 10^9 Nm^2/C^2).

r^2 = (1.87 x 10^-11 m^2).

Take the square root of both sides to find r:

r ≈ 4.32 x 10^-6 m.

So, the net electric field is zero at a distance of approximately 4.32 x 10^-6 meters from the 3.0 μC point charge in the direction opposite to the external uniform electric field.

Explanation:

There was frost on the ground overnight because the temperature dropped. In addition, there was cold, damp moisture in the air. This may mean that there is a good chance of _____ in the morning. precipitation fog sunshine thunderstorms

Answers

Answer: Fog

Explanation:

Fog can be defined as the clouds on ground. Fog is made of condensed air and that is being cooled down to the point where it cannot hold more water.

The frost overnight forms fog. During the long nights the air gets cooled down and the the moisture in the air also adds to the formation of fog.

Thus, the correct answer is fog.

The answer would be fog.

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Answers

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Explanation :

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Now the conversion factor used for the temperature is,

$K=^oC+273$

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Now put the value of temperature, we get

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Answers

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Answers

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