Select all the factors listed that influence the density of ocean water.a. tides
b. salinity
c. fecundity
d. temperature E. wave height F. current speed

In this exercise we have to use the knowledge in distance, in this way we will find that the proportional distance found is:

So from the information given in the text we find that:

• The distance from the center of the sun to the center of the earth is

• The radius of the sun is

• We need to assume a radius for the ball bearing, so suppose that the radius is  

First, we need to find in what way or manner often the radius of the brightest star exist considerable respect to the range of the ball significance, that exist given apiece following equating:

Now, we can calculate the distance from the center of the sun to the center of the sphere representing the earth:  

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Answer:

d = 0.645 m(assuming a radius of the ball bearing of 3 mm)

Explanation:

The given information is:

• The distance from the center of the sun to the center of the earth is 1.496x10¹¹m =
• The radius of the sun is 6.96x10⁸m =

We need to assume a radius for the ball bearing, so suppose that the radius is 3 mm = .  

First, we need to find how many times the radius of the sun is bigger respect to the radius of the ball bearing, which is given by the following equation:

Now, we can calculate the distance from the center of the sun to the center of the sphere representing the earth, :  

[tex] d_{s} = \frac{d_{e}}{r_{s}/r_{b}} = \frac{1.496 \cdot 10^{11} m}{2.32\cdot 10^{11}} = 0.645 m

I hope it helps you!

Final answer:

The average magnitude of the upward force of air resistance on Mike during his initial descent is 0 N. The average upward force during the descent after Mike opens his parachute is 1.552 N. The downward speed of the wallet when it reaches the ground is 196.196 m/s.

Explanation:

(a) Average magnitude of the upward force of air resistance:

To find the average magnitude of the upward force of air resistance during Mike's initial descent, we need to calculate the net force acting on him. This can be done by subtracting his weight from the gravitational force:

Net force = gravitational force - weight

Gravitational force = mass * acceleration due to gravity = 97 kg * 9.8 m/s2 = 950.6 N

Weight = mass * acceleration due to gravity = 97 kg * 9.8 m/s2 = 950.6 N

Net force = 950.6 N - 950.6 N = 0 N

Since the net force is 0 N, the average magnitude of the upward force of air resistance is also 0 N.

(b) Average upward force after opening parachute:

When Mike opens his parachute, air resistance plays a significant role in slowing him down. The average upward force can be calculated using the equation:

Average upward force = mass * acceleration

Acceleration = (final speed - initial speed) / time

Time = distance / (final speed - initial speed)

Acceleration = (4.0 m/s - 68 m/s) / (1000 m / (4.0 m/s - 68 m/s)) = 0.016 m/s2

Average upward force = 97 kg * 0.016 m/s2 = 1.552 N

(c) Speed of the wallet:

Since the wallet has negligible air resistance, we can use the equation for freefall to calculate its speed:

Final speed = initial speed + acceleration * time

Acceleration = acceleration due to gravity = 9.8 m/s2

Time = sqrt(2 * height / acceleration) = sqrt(2 * 2000 m / 9.8 m/s2) = 20.02 s

Initial speed = 0 m/s

Final speed = 0 m/s + 9.8 m/s2 * 20.02 s = 196.196 m/s

Therefore, the downward speed of the wallet when it reaches the ground is 196.196 m/s.

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Final answer:

The force of air resistance on Mike during his initial descent and after opening his parachute is approximately 950.6 N. Ignoring air resistance, his wallet will reach the ground at approximately 198 m/s.

Explanation:

The subject of this question is Physics, and it requires understanding of forces and kinematics to apply to the real world scenario of skydiving.

Part (a)

During the initial descent, Mike doesn't have a parachute open. So, the only forces at play initially are his weight and the force of air resistance. We know that he achieves a steady speed of 68 m/s, which means the forces are balanced (net force is zero). Since weight and air resistance counterbalance each other, we calculate the weight by multiplying mass (97 kg) by acceleration due to gravity (9.8 m/s2), which yields 950.6 N. Given the forces balance, this is also the force of air resistance and the answer to part (a).

Part (b)

After the parachute opens, Mike continues to descend, eventually reaching the ground with a speed of 4.0 m/s, indicating a different balance between weight and airresistance. The weight remains the same, but the air resistance (upward force) has increased and once again equals weight since there is no acceleration. Hence, the upward force is still 950.6 N.

Part (c)

For the wallet, we're told to ignore air resistance. So, it's a free fall scenario. We can use the equation of motion v2 = u2 + 2gs to calculate the final speed. Initial speed (u) is 0, g is 9.8 m/s2 and s (displacement) is 2000 m. Substituting these values in, we calculate a final speed of approximately 198 m/s.

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Answer:

The temperature of the gas is 48.75 Kelvin.

Explanation:

Using the ideal gas equation as shown

PV = nRT where;

P is the pressure of the gas in ATM

V is the volume of the gas

n is the number of moles

R is the ideal gas constant

T is the temperature in Kelvin

From the formula,

Given the following parameters V = 1litre, n = 0.5moles. pressure = 2ATM

R = 0.08206 atm L/molK

On substituting to get the temperature we have:

Answer:

shirt

Explanation:

shirt