Gold melts at 1064 c. Melting point is a ___.A)chemical change
B)chemical property
C)physical change
D)physical property

Answers

Answer 1
Answer:

Physical property .      


Answer 2
Answer:

Answer:

i would say Chemical property

Explanation:


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How are electromagnetic waves affected as the frequency of the waves increases?A) energy and wavelength increase
B) energy and wavelength decrease
C) energy decreases, wavelength increases
D) energy increases, wavelength decreases

Answers

When the frequency of the waves increases, its energy increases, while the wavelength decreases.  

• A travelling disturbance, which mediates energy from one place to another is known as a wave.  

• The tendency to do work or cause a change is known as the energy.  

• Waves can be determined with the help of frequency and wavelength.  

• In a given unit of time, the number of complete wavelengths is known as frequency.  

• With the increase of the size of wavelengths, its energy and frequencydecreases.  

• There are two basic kind of waves, that is, electromagnetic and mechanical waves.  

• The waves, which can travel through a medium or a vacuum is known as the electromagnetic waves.  

• The waves with long wavelengths comprise less energy than waves with short wavelengths.  

Thus, correct answer is option d, that is, energy increases, wavelength decreases.  

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As the frequency is how many waves pass a fixed point in certain amount of times. This means that the waves get closer together and, therefore, the wavelength decreases. It also means that the wave has more energy.

Answer: D) Energy increases, wavelength decreases

After decaying for 48 hours,1/16 of the original mass of a radioisotope sample remains unchanged. What is the half-life of this radioisotope?

Answers

Half-life is the period in which radioisotope sample halves it's mass.
If 1/16 of the sample remains it means that there were 4 half-life periods (16=2⁴)
4 half-life periods = 48 hours      /4
half-life period = 12 hours

Hope it helped :)

The radioisotope is an unstable chemical element. The half-life of the radioisotope after decaying for 48 hours is 12 hours.

What is half-life?

Half-life is a period taken by the radioisotope to get decayed by half the original amount. The half-life is the time that is needed by the reactant to get decreased and form the product.

If the sample remained is 1/16 then there are 4 half-life periods present.

4 half life = 48 hours ÷ 4

= 12 hours

Therefore, 12 hours is the half-life period.

Learn more about half-life here:

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What do not have a definite shape or volume in sience?

Answers

it is gas such as oxygen,nitrogen,hydrogen,etc

Which of the following is not a result when a change to an equilibrium system is applied? (2 points)Increasing the rate of the forward reaction will cause a shift to the left.

Increasing the rate of the reverse reaction will cause a shift to the left.

Decreasing the rate of the forward reaction will cause a shift to the left.

Decreasing the rate of the reverse reaction will cause a shift to the right.

Answers

Answer: Option (2) is the correct answer.

Explanation:

According to LeChatelier principle, any change in the equilibrium of a chemical reaction will result in shifting of equilibrium which is opposing the change.

Therefore, when we increase the rate of the reverse reaction that is, we move towards left side then this will actually cause a shift to the right hand side which is opposing the change.

Thus, we can conclude that increasing the rate of the reverse reaction will cause a shift to the left is not a result when a change to an equilibrium system is applied.

It should be increasing the rate of the forward reaction will cause a shift to the left because the external stress, which is the increase in rate, will cause the reaction to be unbalanced, and to reach equilibrium it needs to shift to the right.

When butter is heated it melts and when that melted butter cools and solidifies the process called

Answers

I'm pretty sure it is called condensation

A 440.0 g piece of copper is dropped into 400.0 mL of water at 20.00 °C. The final temperature of the water was measured at 35.80 °C. Calculate the initial temperature of the metal. (SCu = 0.3850 J/gC)

Answers

Answer:

207.50°C

Explanation:

Mass of metal (M1) = 440g

Volume of water = 400mL

Initial temperature of water (T2) = 20°C

Final temperature of the mixture (T3) = 35.80°C

Specific heat capacity of the metal (C1) = 0.3850J/g°C

Specific heat capacity of water = 4.184J/g°C

Density of water = 1g/mL

Temperature of metal (T1) = ?

Heat lost by the metal = Heat gained by the water

Q = MC∇T

Q = heat energy

M = Mass

C = specific heat capacity

∇T = change in temperature

M1C1(T1 - T3) = M2C2(T3 - T2)

M2 = ?

Density = mass / volume

Mass = density * volume

Mass = 1g/mL * 400mL

Mass = 400g

M1C1(T1 - T3) = M2C2(T3 - T2)

400 * 0.3850 (T1 - 35.80) = 400 * 4.184 * (35.80 - 20)

154(T1 - 35.80) = 1673.6 * (15.8)

154T1 - 5513.2 = 26442.88

154T1 = 26442.88 + 5513.2

154T1 = 31956.08

T1 = 31956.08 / 154

T1 = 207.50

The initial temperature of the metal was 207.50°C