The water displaced by a strong earthquake on the ocean floor forms large waves called_______.

Answers

Answer 1
Answer: The water displaced by a strong earthquake on the ocean floor forms large waves called tsunamis.

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Given the balanced equation representing a reaction:Al2(SO4)3 +6NaOH ==> 2Al(OH)3 + 3Na2SO4

The mole ratio of NaOH to Al(OH)3 is

(1) 1:1 (2) 3:1

(3) 1:3 (4) 3:7

Answers

The answer is number 2. 3:1. This is the simplified value of 6:2 which came from 6NaOH:2Al(OH)3. The original ratio is 6:2 but it can be simplified through dividing it each by 2. So 6 divided by 2 equals to 3 and 2 divided by 2 is 1. Therefore the simplified ratio is 3:1.

4. Allison is trying to identify the type of bacteria found on common surfaces like doorknobs, table tops, etc. For this experiment, she will collect samples of bacteria and allow them to grow for several days. Then, she will observe the bacterial colonies that are formed and compare their appearance with pictures of bacterial colonies in her textbook. Which of the following pieces of equipment will Allison most likely use for the growth of the bacteria?

Answers

You will use a....
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Petri Dish

Suppose 300 mL of 0.50 M lithium bromide solution and 300 mL of 0.70 M rubidium bromide solution are combined. What is the concentration of the bromide ion in the resulting solution?

Answers

Answer:

0.60 mol·L⁻¹  

Explanation:

Data:  

LiBr: c = 0.50 mol/L; V =300 mL

RbBr: c = 0.70 mol/L; V =300 mL

1. Calculate the moles of Br⁻ in each solution

(a) LiBr

\text{Moles} = \text{0.300 L} * \frac{\text{0.50 mol}}{\text{1 L}} = \text{ 0.150 mol}

(b) RbBr

\text{Moles} = \text{0.300 L} * \frac{\text{0.70 mol}}{\text{1 L}} = \text{ 0.210 mol}

2. Calculate the molar concentration of Br⁻

(a) Moles of Br⁻

n = 0.150 mol  + 0.210 mol = 0.360 mol

(b) Volume of solution

V = 300 mL + 300 mL = 600 mL = 0.600 L

(c) Molar concentration

c = \frac{\text{moles}}{\text{litres}} = \frac{\text{0.360 mol}}{\text{0.600 L}} =  \textbf{0.60 mol/L}

 

The concentration of Br ions in the resulting solution of LiBr and RbBr has been 0.6 M.

The addition of LiBr and RbBr has been dissociated into the equal moles of Li, Rb, and Br.

\rm LiBr\;\rightarrow\;Li^+\;+\;Br^-

\rm RbBr\;\rightarrow\;Rb^+\;+\;Br^-

Thus 1 mole of LiBr = 1 mole Br

1 mole RbBr = 1 mole Br.

The moles of LiBr in 0.5 M solution:

Molarity = \rm moles\;*\;(1000)/(volume\;(ml))

0.5 = \rm moles\;*\;(1000)/(300\;ml)

Moles of LiBr = 0.15 mol

The moles of Br from LiBr = 0.15 mol.

The moles of RbBr in 0.7 M solution:

Molarity = \rm moles\;*\;(1000)/(volume\;(ml))

0.7 = \rm moles\;*\;(1000)/(300\;ml)

Moles of RbBr = 0.21 mol

The moles of Br from RbBr = 0.21 mol.

The total moles of Br ions from LiBr and RbBr has been :

= 0.15 + 0.21

= 0.36 mol.

The total volume of the solution will be:

= 300 + 300 ml

= 600 ml.

The concentration of the Br ion has been:

Molarity = \rm moles\;*\;(1000)/(volume\;(ml))

Molarity of Br ions =  \rm 0.36\;*\;(1000)/(600\;ml)

Molarity of Br ions = 0.6 M.

The concentration of Br ions in the resulting solution of LiBr and RbBr has been 0.6 M.

For more information about the concentration of the sample, refer to the link:

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If it takes 25 mL of 0.05 M HCl to neutralize 345 mL of NaOH solution, what is the concentration of the NaOH solution? (Round answer to 4 decimal places) *

Answers

Answer:

Concentration of NaOH= 0.0036 M

Explanation:

Given data:

Volume of HCl  = 25 mL

Concentration of HCl = 0.05 M

Volume of NaOH = 345 mL

Concentration of NaOH = ?

Solution:

Formula:

C₁V₁ = C₂V₂

C₁ = Concentration of HCl

V₁ = Volume of HCl

C₂ = Concentration of NaOH

V₂ = Volume of NaOH

Now we will put the values in formula.

C₁V₁ = C₂V₂

0.05 M × 25 mL =  C₂ × 345 mL

1.25 M.mL = C₂ × 345 mL

C₂ = 1.25 M.mL/345 mL

C₂ = 0.0036 M

Final answer:

To find the concentration of the NaOH solution, we can use the concept of titration. By using the equation Moles = Concentration * Volume, we can calculate the moles of HCl used and then use the ratio of moles between HCl and NaOH to find the concentration of the NaOH solution.

Explanation:

To find the concentration of the NaOH solution, we need to use the concept of titration. From the given information, it takes 25 mL of 0.05 M HCl to neutralize 345 mL of NaOH solution. We can use the equation Moles = Concentration * Volume to find the amount in moles of HCl used. Then, we can use this information to calculate the concentration of the NaOH solution.

First, let's calculate the moles of HCl used:

Moles of HCl = (0.05 M) x (0.025 L) = 0.00125 mol

Next, we can use the ratio of moles between HCl and NaOH, which is 1:1, to find the moles of NaOH in the solution:

Moles of NaOH = 0.00125 mol

Finally, we can calculate the concentration using the formula:

The concentration of NaOH = (0.00125 mol) / (0.345 L) = 0.00362 M

Learn more about Concentration of NaOH solution here:

brainly.com/question/34408783

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A filament at which temperature would have the most light absorbed by a piece of yellow glass?

Answers

soft light (answer) is the filament between (2700k-3000k). 
 The higher the kelvin number the whiter the light.

3500k-4100k is bright white/cool white

5000k-6500k is daylight 

\and those are the three primary colors of color temperature

During natural selection, which organisms are most likely to survive as the environment changes

Answers

The organisms more likely to survive in a changing environments are the ones that have genetic variation.

Answer:

A: ones that can best adapt to and survive in the changed environment

Explanation: