MATHEMATICS HIGH SCHOOL

in 2004, 510,000 acres of farmland in region were devoted to growing nuts. by 2011, the number of acres used to grow nuts had increased to 830,000. find the avarage rate of change in the number of acres in a region used to grow nuts from 2004 to 2011

Answers

Answer 1
Answer:

Consider the (x, y) coordinates to be:  (2004, 510000) and (2011, 830000).

Average rate of change is another name for slope, So, use the slope formula: m = (y2 - y1)/(x2 - x1)

m = (830,000 - 510,000)/(2011 - 2004)

m = (320,000)/(7)

Answer: 320,000 acres every 7 years
Answer 2
Answer:

Answer: 45714 per year.

Step-by-step explanation:

Given : In 2004, 510,000 acres of farmland in region were devoted to growing nuts. by 2011, the number of acres used to grow nuts had increased to 830,000.

Change in acres of farmland from 2004 to 2011 = 830000-510000=320,000

Change in year = 2011-2004=7

The average rate of change is given by :-

\frac{\text{Change in acres of farmland}}{\text{Change in year}}\n\n=(320000)/(7)=45714.2857143\approx45714 \text{[Rounded to the nearest integer.]}

Hence, the average rate of change in the number of acres in a region used to grow nuts from 2004 to 2011 is 45714 per year.

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Shureka Washburn has score of 72,67,82, and 79 on her alebra test. Use an inequality to find the scores she must make on the final exam to pass the course with an average of 77 or higher, given that the final exam counts as two test.

Answers

Answer:

x \geq 81

Step-by-step explanation:

Shureka Washburn has score of 72,67,82, and 79 on her algebra test.

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ANSWER X MUST BE GREATER THAN OR EQUAL TO 81

Having trouble on this

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The answer is the first one

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Answers

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