Opposite electric charges will repel, and like charges will attract.
Answers
There are two ways to make the statement true:
#1). Exchange the places of the words "Opposite" and "like".
#2). Exchange the places of the words "repel" and "attract".
Either ONE of these changes will make the statement true.
Doing BOTH of these changes will leave it false.
Answer:
False. Opposite electric charges will attract, and like charges will repel.
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In real-life circuits, there will always be more than one capacitor or resistor included. In a circuit with multiple capacitors, the total or equivalent capacitance can be calculated to represent all the capacitors as a single one with a capacitance called either the "net capacitance" or "equivalent capacitance". The formula to use to calculate this net capacitance is dependent on whether the capacitors are in series or in parallel.
Answers
The equivalent capacitance of the three capacitors shown in the figure is equal to 7.5 microfarad.
Capacitance is the ability to store charge. It is visible from the figure that capacitance C1 = 10μF, C2 = 20μF and C3 = 10μF. The capacitors C1 and C2 are connected in parallel. Therefore we first take the equivalent capacitance of C1 and C2, which can be calculated as follows;
Now, the equivalent capacitance of C12 and C3 is calculated. Since they are connected in series, so the formula will be reciprocal sum of the capacitance C12 and C3, which is shown below:
Hence, the equivalent capacitance will be equal to 7.5 microfarad units.
Learn more about equivalent capacitance at:
#SPJ4
Answers
Light travels at speed of
The distance covered by the light during this time can be found with the formula
where S is the distance covered and t the time. By re-arranging this formula and by plugging the numbers into it, we find how far the light went in 1 millisecond:
Final answer:
The speed of light is approximately 299,792 kilometers (186,282 miles) per second. Given a millisecond is a thousandth of a second, light will travel approximately 299.792 kilometers in one millisecond.
Explanation:
The speed of light in a vacuum, such as outer space, is a set constant in physics, approximately 299,792 kilometers per second, or about 186,282 miles per second. Thus, if we want to know how far light travels in 1 millisecond, that is, one hundredth of a scecond, we need to convert seconds into milliseconds.
There are 1,000 milliseconds in one second. Hence, in 1 millisecond, light will travel about 299.792 kilometers (or about 186.282 miles).
Learn more about Speed of Light here:
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Answers
(-20) / (the object's mass).
Call it a crazy hunch, but I can't shake the feeling that there was more
to the question before the part you copied, that mentioned the object's
mass, and its velocity before this force came along.
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Wow ! This is not simple. At first, it looks like there's not enough information, because we don't know the mass of the cars. But I"m pretty sure it turns out that we don't need to know it.
At the top of the first hill, the car's potential energy is
PE = (mass) x (gravity) x (height) .
At the bottom, the car's kinetic energy is
KE = (1/2) (mass) (speed²) .
You said that the car's speed is 70 m/s at the bottom of the hill,
and you also said that 10% of the energy will be lost on the way
down. So now, here comes the big jump. Put a comment under
my answer if you don't see where I got this equation:
KE = 0.9 PE
(1/2) (mass) (70 m/s)² = (0.9) (mass) (gravity) (height)
Divide each side by (mass):
(0.5) (4900 m²/s²) = (0.9) (9.8 m/s²) (height)
(There goes the mass. As long as the whole thing is 90% efficient,
the solution will be the same for any number of cars, loaded with
any number of passengers.)
Divide each side by (0.9):
(0.5/0.9) (4900 m²/s²) = (9.8 m/s²) (height)
Divide each side by (9.8 m/s²):
Height = (5/9)(4900 m²/s²) / (9.8 m/s²)
= (5 x 4900 m²/s²) / (9 x 9.8 m/s²)
= (24,500 / 88.2) (m²/s²) / (m/s²)
= 277-7/9 meters
(about 911 feet)
Answers
two heavy bags of groceries upstairs to your
kitchen. Will you do more work on the bags if
you carry them up one at a time? Explain.
Answers
Answer:
no both remains same...
Explanation:
because the work done is given by the product of the both the masses added (m+m) Displacement
and second time when you carry the bags individually it comes out to be the same m×displacement + m×displacement