Calculate the average power required to lift a 490 Newton object of vertical distance of 2 m in 10 seconds

Answers

Answer 1
Answer:              Power  =  (work done) / (time to do the work)

             Work  =  (force) x (distance)

If you want to lift a 490N object, you'll need (at least) 490N of force.
So, when you lift it 2 meters vertically, the work you do is

             Work  =  (490 N) x (2 m)  =  980 joules
and
             Power = (980 joules) / (10 sec)  =  98 watts .  
                 

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Which concept represents most encompassing aspect of our lives

Answers

the most ecompassing aspect of our lifes is emotional health

A particle has a charge of +1.5 µC and moves from point A to point B, a distance of 0.15 m. The particle experiences a constant electric force, and its motion is along the line of action of the force. The difference between the particle's electric potential energy at A and B is EPEA - EPEB = +9.0 10-4 J. (a) Find the magnitude and direction of the electric force that acts on the particle. _______N the direction of motion (along, against, perpendicular)
(b) Find the magnitude and direction of the electric field that the particle experiences. _______N/C the direction of motion (along, against, perpendicular)

Answers

The magnitude of the electric field is 4000 N/C while the direction of the electric field is along the direction of the motion of the charge.

Given to us

Charge of the particle, q = +1.5 µC = 1.5 x 10⁻⁶

Distance between points A and B, d = 0.15 m

The particle's electric potential energy at A and B

= \rm EPE_A - EPE_B = +9.0x10⁻⁴ J

What is the magnitude and direction of the electric force that acts on the particle?

The electric charge in electric potential energy is equal to the work done by an electric field. therefore,

\rm W=EPE_A - EPE_B

W = 9.0x10⁻⁴ J

We know that work done by the system can be given as,

\rm Work = force* displacement

Substitute the values,

9 * 10^(-4)= F * 0.15

F = 1.5 x 10⁻³ N

Thus, the magnitude of the force is 1.5 x 10⁻³ N while its direction is along with the motion of the charge.

What is the magnitude and direction of the electric field that the particle experiences?

We know the relationship between electrostatic and electric force, therefore,

\rm Force = charge* Electric\ field

Substitute the values,

6* 10^(-3)=1.5* 10^(-6) * \rm E

E = 4000 N/C

Hence, the magnitude of the electric field is 4000 N/C while the direction of the electric field is along the direction of the motion of the charge.

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Answer:

Part a)

F = 6 * 10^(-3) N

Direction of force is along the motion of charge

Part b)

E = 4000 N/C

direction of electric field is along the direction of motion

Explanation:

Part a)

As we know that the change in electric potential energy is equal to the work done by electric field

W = EPE_A - EPE_B

W = 9.0 * 10^(-4) J

now from the equation of work done we know that

W = F.d

(9.0 * 10^(-4)) = F(0.15)

F = 6 * 10^(-3) N

Direction of force is along the motion of charge

Part b)

As we know the relation between electrostatic force and electric field given as

F = qE

(6 * 10^(-3)) = 1.5 * 10^(-6) E

E = 4000 N/C

direction of electric field is along the direction of motion

What collides and creates a movement of heat called conduction?A. photons

B. compounds

C. Molecules

D. atoms

Answers

Molecules collide and create a movement of heat called conduction.

What is conduction?

Conduction is defined as a process  as a means of which heat is transferred from the hotter end of the body to it's cooler end.Heat flows spontaneously from a body which is hot to  a body which is cold.

In the process of conduction,heat flow is within the body and through itself.In solids the conduction of heat is due to the vibrations and collisions of molecules  while in liquids and gases it is due to the random motion of the molecules ,

When conduction takes place, heat is usually transferred from one molecule to another as they are in direct contact with each other.There are 2 types of conduction:1) steady state  conduction 2) transient conduction.According to the type of energy conduction is of three types:

1) heat conduction

2) electrical conduction

3)sound conduction

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Answer:

c.

Explanation:

The unit for measuring the rate at which light energy is radiated from a source is the A. Angstrom.
B. lux.
C. lumen.
D. candela.

Answers

The correct answer is letter D. candela. The unit for measuring the rate at which light energy is radiated from a source is the candela. Lumen is the unit for measuring the total amount of visible light emitted by a source. Lux is lumen per square meter. 

A car slams on its breaks,producing friction between the tires and the road.Into which type of energy is the mechanical energy of the car converted?

Answers

the answer is Heat Energy

its is turning into electrical energy

At 400 K, a volume of gas has a pressure of 0.40 atmospheres. What is the pressure of this gas at 273 K?

Answers

The pressure of the sample of gas at 273 K is equal to 0.273 atm assuming the volume is constant.

What is Gay Lussac's law?

Gay-Lussac's law can be described as that when the volume of the gas remains constant then the pressure (P) of the gas and the absolute temperature (T) in a direct relationship.

Gay Lussca's law can be  described as mentioned below:

P/T = k

The pressure of gas is directly proportional to absolute temperature of the gas.

P ∝ T                               ( Volume of gas is constant)

or,    P₁/T₁ = P₂/T₂                                            .................(1)

Given, the initial temperature of the gas, T₁ = 400 K

The final temperature of the gas, T₂ = 273 K

The initial pressure of the gas, P₁ = 0.40 atm

The final pressure of the given gas can be calculated from Gay Lussac's law as:

\displaystyle P_2 =(P_1)/(T_1)* T_2

P₂ = (0.40/400) ×273

P₂ = 0.273 atm

Therefore, the pressure of this gas at 273 K is 0.273 atm.

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The ratio p/T is constant. So, you'd get 273*0.40/400