Why is there no overall electrical charge on an aluminium atom?

Answers

Answer 1
Answer: The atoms always have an equal amount of protons and neutrons so lets say if one had 10 positive then it would have 10 negatives making it neutral.
10-10=0

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Theresa invested $5,000 in an account she expects will earn 7% annually. Approximately how many years will it take for the account to double in value?

Which compound is an electrolyte?
(1) C6H12O6 (3) CaCl2
(2) CH3OH (4) CCl4

Answers

I think the correct answer is option 3. CaCl2 is the compound that is an electrolyte when dissolved in water. An electrolyte is a substance that conducts electricity in solution. Calcium Chloride when in solution dissociates into ions which allows the flow of current in the solution.

A patient is given 0.050 mg of technetium-99 m (where m means metastable—an unstable but long-lived state), a radioactive isotope with a half-life of about 6.0 hours.How long until the radioactive isotope decays to 1.3×10−2 mg ?

Answers

The correct answer is 9.6h.

As you know, a radioactive isotope's nuclear half-life tells you exactly how much time must pass in order for an initial sample of this isotope to be halved.

Using the formula , A = Ao.1/2^n

where , A- final mass after decay

Ao - initial mass

n - the number of half-lives that pass in the given period of time

Now, putting all the values, we get

1.3 × 10^-2 mg = 0.050 mg × 1/ 2^n

Take the natural log of both sides of the equation to get,

(1.3 . 10^(-2) / 0.050 ) = ㏑((1/2)^(n))

(1.3 . 10^(-2) / 0.050 ) = n. ln(1/2)\n

n = 1.6

Since n represents the number of half-lives that pass in a given period of time, you can say that

n = t /  t _(1/2)

t= 1.6 × 6 h

t = 9.6h
Hence, it will take 9.6 h  until the radioactive isotope decays.

Learn more about radioactive isotope andhalf life here:-

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Final answer:

Using the formula for radioactive decay and the provided half-life of technetium-99m, it can be calculated that it takes approximately 28.5 hours for 0.050 mg of technetium-99m to decay to a quantity of 1.3 x 10^-2 mg.

Explanation:

The decay of a radioactive isotope is an exponential process based on the half-life, which is, in turn, constant for any given isotope. The general formula for the remaining quantity of a radioactive isotope after a given time is given by: N = N0 (0.5) ^(t/t1/2), where (N0) is the initial amount, (N) is the remaining amount, (t) is time, and (t1/2) is the half-life of the isotope. In this case, we are given the initial quantity (N0 = 0.050 mg), the remaining quantity (N = 1.3 x 10^-2 mg), and the half-life (t1/2 = 6.0 hours).

We can solve for time (t) in the equation: N = N0 (0.5) ^(t/t1/2). Plugging in the values, we get 1.3 x 10^-2 = 0.050 x (0.5)^(t/6), and solving for t, we find that it takes approximately 28.5 hours for the technetium-99m to decay to 1.3 x 10^-2 mg.

Learn more about Radioactive Decay here:

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As a sample of matter is cooled, its particles

Answers

As a sample of matter is cooled, its particles slowly moves because their kinetic energy is being reduced due to the temperature being reduced also. 

From what class(es) of elements is the following compound made? copper || chloride metal and metalloid
metal and nonmetal
metalloid and nonmetal
two metals

Answers

Answer: The correct answer is metal and non-metal.

Explanation:

Elements are mainly divided into 3 classes in the periodic table.

1.) Metals: The element which lie on the left side of the periodic table are mainly metals. These elements loose electron easily and form positively charged species. These elements are present in the highest proportion in the periodic table.

2.) Non-metals: The elements which lie on the right side of the periodic table are considered as non-metals. These elements gain electrons easily and form negatively charged species.

3.) Metalloids: These lie between metals and non-metals and show the properties of both metals and non-metals.

Copper lie in the period 4 and group 11 of the periodic table and it can easily loose electron and hence, it is considered as a metal.

Chlorine lie in the period 3 and group 17 of the periodic table and it can easily gain electron and hence, considered as a non-metal.

Therefore, the correct answer is metal and non-metal.

Metal and non metal because copper is a metal and chloride is a non metal

The concentration of hydrogen peroxide (H2O2) can be determined by titrating it with an acidified MnO4− solution. The following is an unbalanced equation. MnO4− (aq) + H2O2 (aq) → O2 (g) + Mn2+ (aq)

(a) Balance the above redox reaction.
(b) Determine the concentration of H2O2 solution in molarity if 10.00 mL of this solution requires 20.00 mL of 1.5 M MnO4− for a complete reaction.

Answers

Answer:

A) {MnO_4}^- + 3 H^+ + (5)/(2) H_2O_2 \rightarrow Mn^(2+) + 4 H_2O + (5)/(2) O_2

B) 7.5 molar

Explanation:

A)Reduction

{MnO_4}^- + 8 H^+ + 5e^- \rightarrow Mn^(2+) + 4 H_2O

Oxidation

H_2O_2 \rightarrow O_2 + 2 H^+ + 2e^-

Multiplying the oxidation reaction by 5/2 and adding it to the reduction equation:

{MnO_4}^- + 8 H^+ + 5e^- \rightarrow Mn^(2+) + 4 H_2O

+

(5)/(2) H_2O_2 \rightarrow (5)/(2) O_2 + 5 H^+ + 5e^-

-----------------------------------------------------------------------------------------------------

{MnO_4}^- + 3 H^+ + (5)/(2) H_2O_2 \rightarrow Mn^(2+) + 4 H_2O + (5)/(2) O_2

B) 10 ml = 0.01 L

20 ml = 0.02 L

mol of MnO4− = molarity*volume = 1.5*0.02 = 0.03

1 mol of MnO4− reacts with 5/2 mol of H2O2, then:

mol of H2O2 = 0.03*5/2 = 0.075

molarity = mol/volume = 0.075/0.01 = 7.5 molar

according to the third law if a football player hits another player with an action force of 1500n how much will the reaction force be

Answers

Answer:

The reaction would be 1500n (equal reaction)

Explanation:

This can be explained by Newton's third law of motion which states that for every action (force), there is an opposite and equal reaction. In other words, when two objects or people come in contact, the magnitude of force which they exert on each other is equal and they both feel an equal reaction force.

It doesn't matter whether one of the colliding bodies is of bigger mass than the other.  This Newton's third law of motion is also known as the law of action and reaction.