How many moles are in 987 grams of Ra(OH)2?

Answers

Answer 1
Answer:

The number of moles in 987 grams of Ra(OH)2 = 3.8 moles

Calculating number of moles

Ra = 226g

O= 16g

H = 1

Therefore molar mass of Ra(OH)2= 226+ (16+1)×2

= 260g/mol

The molar mass of Ra(OH)2 = 260g/mol

Thus means that 260g of Ra(OH)2 makes up 1 mole

Therefore, 987 g = X moles

Make X moles the subject of formula,

X mole = 987/260

= 3.8 moles

Therefore, the number of moles in 987 grams of Ra(OH)2 = 3.8 moles

Learn more about molar mass here:

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Answer 2
Answer:

Answer : 3.79 moles are in 987 grams of Ra(OH)_2.

Solution : Given,

Mass of Ra(OH)_2 = 987 g

Molar mass of Ra(OH)_2 = 260 g/mole

Now we have to calculate the moles of Ra(OH)_2.

Formula used :

\text{Moles of }Ra(OH)_2=\frac{\text{Mass of }Ra(OH)_2}{\text{Molar mass of }Ra(OH)_2}

Now put all the given values in this formula, we get the moles.

\text{Moles of }Ra(OH)_2=(987g)/(260g/mole)=3.79moles

Therefore, 3.79 moles are in 987 grams of Ra(OH)_2.


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H2(g) + CO2(g) + 10 kcal H2O(g) + CO(g)In another experiment involving the above reaction at 1,000°C, the equilibrium concentrations were found to be:

H2(g) = 2.0 moles per liter
H2O(g) = 4.0 moles per liter
CO2(g) = 5.0 moles per liter
CO(g) = 4.0 moles per liter

What is the equilibrium constant, Keq, for this reaction?

Answers

Answer: The equilibrium constant for the given reaction is 0.8

Explanation:

Equilibrium constant is defined as the ratio of concentration of the products raised to the power its stoichiometric coefficients to the concentration of reactants raised to power its stoichiometric coefficient. It is represented as K_c

For the general equation:

aA+bB\rightleftharpoons cC+dD

The equilibrium constant is represented as:

K_c=([C]^c[D]^d)/([A]^a[B]^b)

For the given chemical equation:

H_2(g)+CO_2(g)+10 kcal\rightleftharpoons H_2O(g)+CO(g)

K_c for this equation is given by:

K_c=([H_2O][CO])/([H_2][CO_2])

Concentration at equilibrium of

H_2=2mol/L\nH_2O=4mol/L\nCO_2=5mol/L\nCO=4mol/L

Putting values in above equation, we get:

K_c=(4* 4)/(2* 5)\nK_c=0.8

Hence, the equilibrium constant for the given chemical reaction is 0.8

This might be a little hard for me but I got it. So you have 2.0, 4.0, 5.0 and 4.0. Subtract from 3.0 - 2.0 = 1.0 and 4.5 - 2.0 = 2.5.

So now we have other answers. 

H20, H2, CO2 and CO

Keq reaction for each formula is 1.6

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Answers

Answer:

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Answers

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Answers

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The invisible electric force field around charged objects depends on

Answers

The invisible electric force field around charged objects depends on the amount of charge, distance involved, and shape of the objects.

What does the formation of charged object depend on ?

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HELP ME PLEASE 40 POINTS You may select a topic from the list below, or choose your own.black hole
oort cloud
star types (supergiant, red dwarf, white dwarf)
supernovae
planetary nebulae
Andromeda galaxy
quasar
Use the library and other resource materials to research and understand your topic. Remember that nasa.gov is a web site that has reliable information as well that you may use for your research. Now write a 300-word report on what you have learned in the essay box below.

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Answer:

Do black hole

Explanation: