URGENT PLEASE HELP
are all fractions with a denominator of 9 recurring decimals investigate
Answers
1/9 0.111111
2/9 0.22222
3/9 0.33333
4/9 0.44444
5/9 0.55555
6/9 0.66666
7/9 0.77777
8/9 0.88888
Related Questions
Consider the quadratic function f(x) = x2 – 5x + 12. Which statements are true about the function and its graph? Select three options. The value of f(–10) = 82 The graph of the function is a parabola. The graph of the function opens down. The graph contains the point (20, –8). The graph contains the point (0, 0).
Find the GCF of the given polynomial. 8x^6y^5 - 3x^8y^3
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Calculate the difference (home-away) in winning percentage. A) Need more information B) Positive C) Negative D) Zero
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Laʀc = (2πR) • (θ ⁄ 2π) = R • θ ... where θ = central angle (of sector)
Ps = R + R + (R • θ) ... perimeter of sector = Ps
Ps = R • (2 + θ) ... Ps = 100 ft
100 = R • (2 + θ)
θ = (100 ⁄ R) – 2
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~...
Similarly, the sector area is just a fraction of the circle area:
As = (πR²) • (θ ⁄ 2π) ... area of sector = As
As = R² • θ ⁄ 2 ... substitute for θ
As = R² • [(100 ⁄ R) – 2 ] ⁄ 2
As = 50R – R² ... differentiate
As' = 50 – 2R ... set to zero
0 = 50 – 2R
R = 25 ft ... optimum radius
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~...
As = 50R – R² ... evaluate at: R = 25 ft
As = 50(25) – (25)²
As = 625 ft² ... maximum area
Note ... at any other R_value, the sector area is less.
" θ " can be determined using: θ = (100 ⁄ R) – 2
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Final answer:
For a circular sector with a fixed perimeter of 100 ft, the values of radius (r) and arc length (s) that will maximize the sector's area are r=25 and s=50.
Explanation:
The perimeter of a circular sector is composed by the length of the arc (s) plus twice the radius (r). If this sum is fixed at 100 ft, then the length of the arc s is equal to 100 - 2r. The area A of a circular sector can be defined as A = 0.5 * r * s.
Substituting the expression for s into the area formula obtains A = 0.5 * r * (100-2r). Simplifying results in A = 50r - r^2 which is a downward opening parabola.
The maximum value of a parabola occurs at the vertex. For a parabola in the form y=ax^2 + bx + c, the x-coordinate of the vertex is -b/(2a). In this case, a=-1 and b=50, hence r=-50/2*(-1) = 25. Substituting r=25 back into the formula for s obtains s = 100-2*25 = 50. Therefore, the values for r and s that will give the circular sector the greatest area are r=25 and s=50.
Learn more about Perimeters and Areas here:
#SPJ11
one of its games. The company sets a goal of $75,000 profit on the game for the first
month of its roll out. How many games does the company need to sell in order to reach its
profit goal?
explain your work
Answers
Answer:
Break-even point in units= 22,273
Step-by-step explanation:
Giving the following information:
Contribution margin per game= $3.59
Fixed cost= $4,960
Desired profit= $75,000
To calculate the number of games to be sold, we need to use the following formula:
Break-even point in units= (fixed costs + desired profit) / contribution margin per unit
Break-even point in units= (4,960 + 75,000) / 3.59
Break-even point in units= 22,273
2) (b-7) (b-2)
3) (b+7) (b-2)
4) (b+7) (b+2)
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(y₂-y₁)=m(x₂-x₁)
(k - (-2) =
k + 2 =
k + 2 =
k = -16/5 = -3 1/5
check:
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Answer:
π 3.142?
Step-by-step explanation:
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96ft² : 6 = 6 ft² - one wall surface
pattern on the surface of the cube
A = a²
a - the edge of the cube
A = a² ⇔ a=√A
a = √(16ft)² = 4ft
V = volume
V = a³
V = (4ft)³ = 64 ft³