You begin sliding down a 15∘ ski slope. part a ignoring friction and air resistance, how fast will you be moving after 10 s?

Answers

Answer 1
Answer:

Answer:

25 m/s

Explanation:

This is a uniformly accelerated motion, so the velocity at time time is given by

v(t) = v_0 +at

where v_0 is the initial velocity and a is the acceleration.

In this problem, the initial velocity is zero: v0=0. The acceleration is the component of the gravitational acceleration projected along the direction of motion, so

a=g sin \theta = (9.8 m/s^2) sin 15^(\circ)=2.5 m/s^2

Therefore, the velocity after t=10 s will be

v(10 s)=at=(2.5 m/s^2)(10 s)=25 m/s

Answer 2
Answer:

Final answer:

Ignoring friction and air resistance, a skier moving down a 15-degree slope with an acceleration of 2.1 m/s² will be traveling at a speed of 21 m/s after 10 seconds.

Explanation:

This question is asking about the speed of a skier sliding down a 15-degree ski slope under the influence of acceleration due to gravity, ignoring friction and air resistance. Given the acceleration of the skier is 2.1 m/s², we can use the equation of motion to find the velocity after a certain time (10 seconds).

This equation is v = u + at, where u is the initial velocity (which is 0 m/s as the skier starts from rest), a is the acceleration (2.1 m/s²), and t is time in seconds (10 seconds). So, v = 0 + 2.1 * 10 = 21m/s.

Therefore, ignoring friction and air resistance, the skier will be moving at a speed of 21 m/s after 10 seconds down the 15-degree ski slope.

Learn more about Physics of Skiing here:

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Answers

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Explanation:

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Answers

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Answers

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Answers

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Answers


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