A scientist would most likely need to update her model when?

Answers

Answer 1
Answer: A scientist would most likely need to update his / her model when it no longer supports the latest results. This could mean that the scientist's model is shrinking or growing, thus, he / she has to update them. Updating them would also make the model appear more interesting.

Related Questions

How many moles of CaO are needed to react with an excess of water to form 370 grams of calcium hydroxide?
Phosphorus is most abundant in the
Describe the motion of the atoms of a substance as it changes from a solid to a liquid. use complete sentences to explain the following concepts in your written response: what is the change in particle speed?
Explain the relationship between chemical bonds and energy in the body.
To show the electron configuration for an atom, when would it be better to use an orbital notation than to use a written configuration with numbers, letters, and superscripts? when the aim is to show orbital shapes in subshells when the aim is to show electron distributions in shells

The amplitude of a transversal wave in a spring toy triples. What happens to the energy of the wave in thetoy?

Answers

Answer: The energy of the wave increases by a factor of 9

Explanation:

3 x 3 = 9

Calculate the value of ?E in joules for a system that loses 115 J of heat and has 150 J of work performed on it by the surroundings.

Answers

Hey there!:

E = energy gained (input) - energy lost (output)

∆E = 150J - 115 J

∆E  =  35 J


Hope that helps!

Final answer:

The change in internal energy (?E) of the system is 35 J based on the first law of thermodynamics.

Explanation:

This problem can be solved using the first law of thermodynamics, which states that the change in internal energy (?E) of a system is equal to the heat added to it (Q) minus the work done by it (W) - this is expressed as ?E = Q - W.

In this particular case, the system loses 115 J of heat, so Q equals -115 J (as it's lost, it's negative), and 150J work is performed on the system which equals +150 J (as work is done on it, it is positive). Therefore, substituting these values into the formula, we get: ?E = -115 J - (-150 J) = 35 J:

So, the change in internal energy of the system is 35 J.

Learn more about Internal Energy here:

brainly.com/question/36602494

#SPJ3

Write a chemical equation for the following decomposition reaction.Nickel(II) hydroxide(s) decomposes to produce nickel(II) oxide(s) and water.

Answers

the chemical equation will be Ni(OH)2(s)------>heat---> NiO(s) + H2O(g)
we know that the heat supplied to decompose the compound.In the result the product H2O is assumed to be in the vapor state so that is gas.

hope it helps

Final answer:

The decomposition of Nickel(II) hydroxide produces Nickel(II) oxide and water. The chemical equation is: Ni(OH)2 (s) → NiO (s) + H2O (l).

Explanation:

The decomposition reaction of Nickel(II) hydroxide into Nickel(II) oxide and water can be written as follows: Ni(OH)2 (s) → NiO (s) + H2O (l) . In this reaction, solid Nickel(II) hydroxide decomposes into solid Nickel(II) oxide and liquid water. It’s important to remember that in these reactions, a single, complex reactant breaks down into multiple, simpler products.

Learn more about Decomposition Reaction here:

brainly.com/question/8009068

#SPJ11

Convert 8.5 x 10-3 mm to micrometers

Answers

Explanation:

1mm = 10^-3 micrometre

8.5 x 10^-3 mm = 8.5 x 10^-6 micrometre

The activation energy of a chemical reaction can be decreased by the addition of(1) a catalyst (3) electrical energy
(2) an indicator (4) thermal energy

Answers

A CATALYST would decrease the activation energy of a reaction thus creating an alternate pathway for the reaction to occur

In a fission reaction of U-235, there was a release of 9.20 × 1011 kJ of energy. What amount of mass in kilograms would have been lost?Recall that c = 3 × 108 m/s.

Answers

 e = mc^2 
 
m = e / c^2 

Plug in your numbers in the appropriate units.
m=1.02 × 10^-5

Answer : The amount of mass in kilograms lost would be, 1.022* 10^(-2)Kg

Solution : Given,

Energy of released in the reaction = 9.20* 10^(11)KJ

Speed of light = c = 3* 10^8m/s

Formula used :

E=m* c^2

where,

E = energy released

m = mass

c = speed of light

Now put all the given values in the above formula, we get the amount of mass would have been lost.

9.20* 10^(11)KJ=m* (3* 10^8m/s)^2

m=1.022* 10^(-5)KJ/m^2s^(-2)=1.022* 10^(-5)* 10^3Kg=1.022* 10^(-2)Kg

conversion : (1KJ/Kg=10^3m^2/s^2)

Therefore, the amount of mass in kilograms lost would be, 1.022* 10^(-2)Kg