MATHEMATICS HIGH SCHOOL

Perform the indicated operation.

4/11 · 10/8

4/11
5/11
6/11

Answers

Answer 1
Answer: 4/11 * 10/8

Multiplying fractions
1) multiply the numerators: 4 * 10 = 40
2) multiply the denominators: 11 * 8 = 88
3) simplify the fraction
40/88 ⇒ 10/22 ⇒ 5/11

40 ÷ 4 = 10
88 ÷ 4 = 22

10 ÷ 2 = 5
22 ÷ 2 = 11

4/11 * 10/8 = 5/11

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a bookstore sells 617 books on moday ,498 books on tuesday, and 563 books on wednsday. on which two days did the bookstore sell about 600 books

Answers

monday and wednesday
617 rounds to 600
563 rounds to 600
498 rounds to 500

answer would be Monday and Wednesday

What is the factored form of 25x²-64?

Answers

Answer:

  • 25x²-64
  • (5x)²-8²
  • (5x-8)(5x+8)

hope it helps.

(I screenshot my question and choices. can you please help D: )

Answers

ratio
if 13.3:9.5=2.52:1.8 then they ar similar

we do
13.3/9.5=2.52/1.8?
1.4/1=1.4/1

ratio is 1.4:1 or invert 1:1.4

answer is 2nd choice

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PLS HELP. The cost of printing a flyer to spread knowledge of an organization that you run is a flat rate of $9 plus $0.05 per copy. Let C represent the total cost of printing and x represent the number of copies. Write in symbolic form an equation that will relate C and x. Organize the data into a table of values. Begin with 500 copies, increase by increments of 500, and end with 2500 copies. How much would it cost to print 2500 flyers and what equation would you use?

Answers

The cost of printing a flyer to spread knowledge of an organization that you run is a flat rate of $9 plus $0.05 per copy. 

We are given the equation: 9.00+0.05x=C

500 copies:

Equation - 9.00+0.05(500)=C

1500 copies: 

Equation - 9.00=0.05(1500)=C 

2500 copies: 

Equation - 9.00=0.05(2500)=C 

C = 9 + 0.05x = 2500  flyers will cost $134
u would need to spend about 100-500 dollars on copies

Do you know the answer? Help!Given: ∠D ≅∠T, ∠E ≅ ∠U, EO ≅ UX
Name the postulate or theorem you can use to prove the triangles congruent.

A. SSS Postulate
B. SAS Postulate
C. ASA Postulate
D. AAS Theorem

Answers

Answer: D. AAS Theorem


Step-by-step explanation:

Given: ∠D ≅∠T, ∠E ≅ ∠U, EO ≅ UX

Then in Δ DOE and Δ TXU

∠D ≅∠T, [Angle]

∠E ≅ ∠U, [Angle]

EO ≅ UX [Side]

From the figure we can see they are two pair of corresponding congruent  angles and one non included sides.

Thus by AAS theorem

Δ DOE ≅ Δ TXU

  • AAS theorem tells that if two angles and any side of one triangle are congruent to two angles and any side of another triangle, then the triangles are congruent.
A cannot be right, as you do not know all 3 sides are equal, you only know one side is.
B cannot be right, as again you only have one side, and need 2
C could be right, but the order is not correct. The side we know is not between the two angles, making this theory incorrect
D is correct, as we have 2 angles next to each other, and a side that is congruent

There were 88 vendors at the craft fair. They needed to set up an equal number in each of the rows and needed 4 flags to mark each row. How many rows and flags were needed?

Answers

Answer:

22 rows and 22 flags are needed

Step-by-step explanation:

Total number of vendors = 88

Existing number of rows and flags= 4

Number of rows and flags needed= 88/4 =22

Answer:

4rows and 16flags

Step-by-step explanation:

Since there were 88 vendors at the craft fair and 4flags on each rows. To set up equal number of vendors on each row, we will use the expression;

Number of vendors per row = Total number of vendors/total number of flags per row = 88/4 = 22 vendors

If there are 22 vendors in a rows and there are 88vendors in total, the total of rows will be;

Total number of vendors/number of vendors per row

= 88/22

= 4 rows

If there are four rows in total and 4flags in each row, the total of flags needed will be;

Total number of row × total flag per row

= 4×4

= 16flags

This shows that there are 4rows and 16flags were needed.
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