Variables x and y are in direct proportion, and y = 12.5 when x = 25. If x = 40, then y =A) 20
B) 28.5
C) 52.5
D) 65 will mark brainiest

Answers

Answer 1
Answer: (40/20)*12.5=20 is your answer .-.
Answer 2
Answer:

Answer:

A.) 20

Step-by-step explanation:

(40/25)*12.5=20

Hope this helps.


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If ABCD is a rectangle, calculate x as a function of α

Answers

Answer:

x = 90 - 2α

Step-by-step explanation:

Solution:-

- Consider the right angled triangle " ABD ". The sum of angles of an triangle is always "180°".

                       < BAD > + < ADB > + < ABD > = 180°

                       < ABD > = 180 - 90° - α

                        < ABD > = 90° - α

- Then we look at the figure for the triangle "ABE". Where " E " is the midpoint and intersection point of two diagonals " AC and BD ".

- We name the foot of the perpendicular bisector as " F ":  " BF " would be the perpendicular bisector. The angle < BAE > is equal to < ABD >.

                    < ABD > = < BAE >  = 90° - α   ... ( Isosceles triangle " BEA " )

Where, sides ( BE = AE ).

- Use the law of sum of angles in a triangle and consider the triangle " BFA " as follows:

                     < ABF> + < BFA > + < BAF > = 180°

                     < ABF > = 180 - (90° - α) - 90°

                    < ABF > = α  

Where,       < BAF > = < BAE >

- The angle < ABD > = < ABE > is comprised of two angles namely, < ABF > and < FBE >  = x.

                        < ABD > = < ABE > = < ABF > + x

                         90° - α = α + x

                        x = 90 - 2α   ... Answer

Answer:

Step-by-step explanation:

The length of this triangle is 10 squares

and the width is 4 squares

The diagonals divide the rectangle into four triangles

These traingles are isoceles

Each two triangles facing each others are identical

<B = 90 degree

B = alpha + Beta

Let Beta be the angle next alpha

The segment that is crossing Beta is its bisector since it perpendicular to the diagonals wich means that:

Beta = 2x

Then B = alpha + 2x

90 = alpha +2x

90-alpha = 2x

x = (90-alpha)/2

Round number to the nearest hundreds 748

Answers

700 because 48 is under 50 which makes it have to round down to the nearest hundred

a car dealership lowered all of its car prices by 15% given the information what was the original price of a car now priced at 9500 pounds please give a broader explanation

Answers

Hi,

The answer would be 10,925 pounds

I hope this helps!

(5xy - y^2) - (3yz + 2xy) + (3y^2 - 4xy)

Answers

(5xy - y^2) - (3yz + 2xy) + (3y^2 - 4xy) \n= 5xy-y^2-3yz-2xy+3y^2-4xy \n =2y^2-xy-3yz
(5xy - y^2) - (3yz + 2xy) + (3y^2 - 4xy)=\n 5xy-y^2-3yz-2xy+3y^2-4xy=\n 2y^2-xy-3yz

Suppose the lengths of the pregnancies of a certain animal are approximately normally distributed with mean mu equals 247 days and standard deviation sigma equals 16 days. Complete parts​ (a) through​ (f) below.

Answers

Answer:

The answer is given below

Step-by-step explanation:

a) What is the probability that a randomly selected pregnancy lasts less than 242 days

First we have to calculate the z score. The z score is used to determine the measure of standard deviation by which the raw score is above or below the mean. It is given by:

z=(x-\mu)/(\sigma)

Given that Mean (μ) = 247 and standard deviation (σ) = 16 days. For x < 242 days,

z=(x-\mu)/(\sigma)=(242-247)/(16)=-0.31

From the normal distribution table, P(x < 242) = P(z < -0.3125) = 0.3783

(b) Suppose a random sample of 17 pregnancies is obtained. Describe the sampling distribution of the sample mean length of pregnancies.

If a sample of 17 pregnancies is obtained, the new mean \mu_x=\mu=247, the new standard deviation: \sigma_x=\sigma/√(n) =16/√(17) =3.88

c) What is the probability that a random sample of 17 pregnancies has a mean gestation period of 242 days or less

z=(x-\mu)/(\sigma/√(n) )=(242-247)/(16/√(17) )=-1.29

From the normal distribution table, P(x < 242) = P(z < -1.29) = 0.0985

d) What is the probability that a random sample of 49 pregnancies has a mean gestation period of 242 days or less?

z=(x-\mu)/(\sigma/√(n) )=(242-247)/(16/√(49) )=-2.19

From the normal distribution table, P(x < 242) = P(z < -2.19) = 0.0143

(e) What might you conclude if a random sample of 49 pregnancies resulted in a mean gestation period of 242 days or less?

It would be unusual if it came from mean of 247 days

f) What is the probability a random sample of size 2020 will have a mean gestation period within 11 days of the mean

For x = 236 days

z=(x-\mu)/(\sigma/√(n) )=(236-247)/(16/√(20) )=-3.07

For x = 258 days

z=(x-\mu)/(\sigma/√(n) )=(258-247)/(16/√(20) )=3.07

From the normal distribution table, P(236 < x < 258) = P(-3.07 < z < 3.07) = P(z < 3.07) - P(z < -3.07) =0.9985 - 0.0011 = 0.9939

Pex Algebra PLS HELP

simplify 3^5 x 3^4

Answers

3 x 3 x 3 x 3 x 3 = 243
3 x 3 x 3 x 3 = 81
243 x 81 = 19,683
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