A kite has diagonals 5.3 ft and 6 ft. What is the area of the kite? A. 5.65 ft². B. 15.9 ft². C. 31.8 ft². D. 22.6 ft²
Answers
Answer: The area of the kite is 15.9 sq. ft.
Step-by-step explanation: Given that a kite has diagonals of lengths 5.3 ft and 6 ft.
We are to find the area of the kite.
We know that the area of a kite having diagonals of length 'p' units and 'q' units is
Here, p = 5.3 ft and q = 6 ft.
Therefore, the area of the kite will be
Thus, the correct option is (B) 15.9 sq. ft.
A=(1/2)ab where a is one diagonal and b is the other
A=(1/2)(5.3)(6)
A=(3)(5.3)
A=15.9
B is answer
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We can divide 4 to the top and the bottom.
28 / 4 = 7
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Therefore our answer in simplest form is 7/25.
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3x = 1155
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Answer:
The answer is A
Step-by-step explanation:
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5 hats * $9.99 = 5 * 9.99 = $49.95
The correct result would be $49.95.
One solution?
two solutions?
no real solution?
cannot be determined
Answers
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Explanation:
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Given: -7x² − 11x − 2 = 0 ;
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We see that it is in "quadratic format" ; that is:
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" ax² + bx + c = 0 ; a ≠ 0 ; "
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Multiply the entire equation by "-1" ; to get rid of the "negative number" :
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→ -1 * {-7x² − 11x − 2 = 0} ;
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to get: → 7x² + 11x + 2 = 0 ;
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This expression is written in the "quadratic format";
ax² + bx + c = 0 ; in which: a = 7 ; b = 11; c = 2 ;
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The expression cannot be "factored"; so, we can solve for "x" ; by using the "quadratic equation formula" ;
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x = {-b ± √(b² − 4ac)} / {2a} ;
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Let us solve for: "(2a)" : 2a = 2 * a = 2 * 7 = 14 ;
Let us solve for: "(b² − 4ac)": 11² − 4*7*2 = 121 − 56 = 65;
→ √(b² − 4ac) = √65
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→ " -b" = -11 ;
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So, x = (-11 ± √65) / 14 ;
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There are TWO (2) solutions:
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Solution 1) x = (-11 + √65) / 14 = - 0.2098387322643893071; AND:
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Solution 2) x = (-11 − √65) / 14 = -1.3615898391641821214 ;
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So, there are TWO (2) real solutions.
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Explain when is a rational expression restricted.
Answers
some things that aren't allowed are dividing by zero and taking the square root of a number less than zero, restrict all values that make thos things hapen
exapmle
a/b, b can not be zero
(3+x)/(4-x)
x cannot be 4 since that would be dividing by zero
another example
√(x-3)
x cannot be less than 3 because that would make a sqrt of a negative
basiccally restrictions are not allowed becasue we don't understnad what happens when we break them