A student is helping her teacher move a 9.5 kg box of books. What net sideways force must she exert on the box to slide it across the floor so that is accelerates at 1.0m/s2?
Answers
As we know that mass of the box is given as
m = 9.5 kg
acceleration of the box is given as
so by Newton's II law we can say
now we can substitute all the values in it
So it required 9.5 N force to slide it
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X-raysUV light waves Sound waves Earthquake waves All of these have which characteristic in common?
Answers
Answer:
Heterogeneous
Explanation:
A chemical substance is composed of one type of atom or molecule. A mixture is composed of different types of atoms or molecules that are not chemically bonded. A heterogeneous mixture is a mixture of two or more chemical substances where the various components can be visually distinguished.
Calculate:
(a) the time to reach maximum height
(b) the maximum height above the base of the cliff reached by the
projectile
(c) thetotal time it is in the air
(d) the horizontal range of the projectile.
Answers
Answer:
a) 9.99 s
b) 538 m
c) 20.5 s
d) 1160 m
Explanation:
Given:
x₀ = 0 m
y₀ = 49.0 m
v₀ = 113 m/s
θ = 60.0°
aₓ = 0 m/s²
aᵧ = -9.8 m/s²
a) At the maximum height, the vertical velocity vᵧ = 0 m/s. Find t.
vᵧ = aᵧ t + v₀ᵧ
(0 m/s) = (-9.8 m/s²) t + (113 sin 60.0° m/s)
t ≈ 9.99 s
b) At the maximum height, the vertical velocity vᵧ = 0 m/s. Find y.
vᵧ² = v₀ᵧ² + 2aᵧ (y − y₀)
(0 m/s)² = (113 sin 60° m/s)² + 2 (-9.8 m/s²) (y − 49.0 m)
y ≈ 538 m
c) When the projectile lands, y = 0 m. Find t.
y = y₀ + v₀ᵧ t + ½ aᵧ t²
(0 m) = (49.0 m) + (113 sin 60° m/s) t + ½ (-9.8 m/s²) t²
You'll need to solve using quadratic formula:
t ≈ -0.489, 20.5
Since negative time doesn't apply here, t ≈ 20.5 s.
d) When the projectile lands, y = 0 m. Find x. (Use answer from part c).
x = x₀ + v₀ₓ t + ½ aₓ t²
x = (0 m) + (113 cos 60° m/s) (20.5 s) + ½ (0 m/s²) (20.5 s)²
x ≈ 1160 m
Answers
Here a cat is running at constant speed which is given as 10 km/h for 5s
So here the average speed is defined as total distance moved in total time interval
so here it is given by
since
here speed of cat is constant so it will remain the same
And hence the average speed and instantaneous speed at any instant for this duration will remain the same
so here answer would be
average speed = 10 km/h
instantaneous speed = 10 km/h
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Answers
Answers
B) 37 V
The potential difference between point a and point b is equal to 37 V
Explanation:
The potential difference across a and b can be calculated by finding the equivalent resistance of the resistors R1, R2 and R3 and then by applying Ohm's law.
Given:
R1 = 3.0 Ω
R2 = 8.0 Ω
R3 = 10.0
Current = I = 5 A
To calculate equivalent resistance of the circuit:
R2 and R3 are connected in parallel configuration. The equivalent resistance of R2 and R3 can be calculated as
Resistance R1 is in series with Rp. The equivalent series resistance is calculated as
Thus the given 3 resistor circuit can be written as an equivalent resistance Rs equal to 7.44 Ω through which current I passes.
By Ohm's law;
If V is the potential difference between a and b
Potential difference across points a and b = Current flowing through the circuit × Resistance between points a and b
37.2 V ≈ 37 V
Therefore, the potential difference between point a and point b is equal to 37 V
Answer:
Explanation:
37V