Electric charges can only be transferred through a process called conduction.true or false

Answers

Answer 1

Answer:

Answer: The correct answer is false.

Explanation:

The electric charges can be transferred through the processes: Conduction and induction.

Conduction: In this process, the charges move from charged body to uncharged body by touching the charged and the uncharged bodies. Here, the charges flow from one body to another until the equilibrium of the charges on both bodies is attained.

Induction: In this process, the charged body is brought near to the uncharged body but without touching these together. In this process, the charge is induced on the uncharged body.

If the negatively charged body is brought near to the uncharged body then the positively charge is induced on the uncharged body.

Therefore, the electric charges cannot only be transferred through a process called conduction. The given statement is false.

Answer 2

Answer:

I'm going to say false hope that helped

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What can cause damge days after a large earthquake?

Answers

After shocks can cause damge for days after a large earthquake

Answer:Damge buildings that fall down after a earthquake also After shock

you are waiting in line to use the diving board at your local pool. While watching people dive into the pool from the board, you realize that using a diving board to spring into air before a dive is a good example of newtons third law of motion. Explain how a diving board illustrates newton's third law of motion?

Answers

Answer:

While we jump on the diving board then the force is applied by us in the downward direction on the diving board

due to this action force applied by us the diving board goes downwards while due to the reaction force of that diving board we will experience a force in opposite direction

that reaction force will be equal in the magnitude of the force applied by us on the diving board and it is opposite in the direction

so here we will move upwards and lift off the diving board

so this is a great example of newton's III law as per this law every action has equal and opposite reaction force

Well, because the diving board is helping the diver jump and helping increase the force of the diver's jump, they work together to help the jumper have a jump.

Why do we insulate houses?A. To prevent heat transfer from inside to
the outside
B. To allow energy to flow from inside to
the outside
C. To keep them cool in the winter and
warm in the summer

Answers

B to allow energy to flow from inside to the outside

Briefly lay out steps of using the tully fisher method.

Answers

Not sure what even is that

For communication to take place, there has to be:a. transmission of the message.
b. medium.
c. sharing of meaning.
d. absence of noise.

Answers

Answer:

C. Sharing of the message

Explanation:

...

A small 175-g ball on the end of a light string is revolving uniformly on a frictionless surface in a horizontal circle of diameter 1.0 m. The ball makes 2.0 revolutions every 1.0 s. What are the magnitude and direction of the acceleration of the ball? What's the tension in the string?

Answers

Answer :

Explanation :

It is given that:

mass of the ball, $m=175\ g=0.175\ Kg$

Radius of circle, $r=(diameter)/(2)=0.5\ m$

The ball makes 2.0 revolutions every 1.0 s. So, angular speed is $\omega=4\pi\ radian/sec$

Since, it is moving in circular path so centripetal acceleration will act here.

So, centripetal acceleration $\alpha$ = $m\omega^2r$

$\alpha=0.175\ Kg* (4\pi)^2* 0.5$

So, $\alpha=13.803\ m/s^2$

Hence, the acceleration is $13.803\ m/s^2$ and it is directed towards the center of rotation.

Tension is a force which is given by :

$F=ma$

$F=0.175\ Kg*13.803\ m/s^2$

$F=2.415\ N$

This is the required answer.

For circular motion.

Centripetal acceleration = mv²/r = mω²r

Where v = linear velocity, r = radius = diameter/2 = 1/2 = 0.5m

m = mass = 175g = 0.175kg.

Angular speed, ω = Angle covered / time

   = 2 revolutions / 1 second

   = 2 * 2π radians / 1 second

   = 4π radians / second

Centripetal Acceleration = mω²r = 0.175*(4π)² * 0.5 Use a calculator

   ≈13.817 m/s²

The magnitude of acceleration ≈13.817 m/s² and it is directed towards the center of rotation.

Tension in the string = m*a

   = 0.175*13.817

   = 2.418 N

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A stone with a mass of 0.70 kg is attached to one end of a string 0.80 m long. The string will break if its tension exceeds 65.0 N. The stone is whirled in a horizontal circle on a frictionless tabletop; the other end of the string remains fixed. Find the maximum speed the stone can attain without breaking the string.